#include <bits/stdc++.h>
using namespace std;
long long int n, k;
int main() {
  cin >> n >> k;
  if ((n * (n - 1)) / 2 <= k) {
    cout << "no solution" << endl;
    return 0;
  }
  for (int i = 0; i < (n); i++) {
    cout << "0 " << i << endl;
  }
}
