Question:A coach placed 15 tennis balls and 5 soccer balls each into 5 baskets. He gave 5 of his students a short period of time to remove as many balls each from a basket as they could. 3 of them removed 8 balls each and the other 2 removed a certain number of balls each. If a total of 56 balls are still in the baskets, how many balls did the other 2 students each remove?
Answer:Combining the tennis and soccer balls, there are 15+5=<<15+5=20>>20 balls in each basket
There are 5 baskets, hence 5*20=<<5*20=100>>100 balls in total
3 students removed 8 balls each, they removed 3*8=<<3*8=24>>24 balls
From the total number of balls, they left 100-24=<<100-24=76>>76 balls
There are 56 balls left so the other 2 students must have removed a total of 76-56=20 balls
This means that each of these 2 students removed 20/2=<<20/2=10>>10 balls.
#### 10