Question:On a moonless night, three fireflies danced in the evening breeze.  They were joined by four less than a dozen more fireflies, before two of the fireflies flew away.  How many fireflies remained?
Answer:Four less than a dozen is 12-4=<<12-4=8>>8.
The three fireflies were joined by four less than a dozen more fireflies, for a total of 3+8=<<3+8=11>>11 fireflies.
Two flew away, leaving 11-2=<<11-2=9>>9 fireflies remaining.
#### 9