[PAR] [TLE] Stefan Struve [SEP] Stefan Jaimy Struve ( ; born February 18, 1988) is a Dutch mixed martial artist who competes as a heavyweight in the Ultimate Fighting Championship (UFC).  At 7'0", he is the current tallest fighter on the roster. [PAR] [TLE] Bob Schrijber [SEP] Robert "Bob" Schrijber (born March 3, 1965) is a Dutch former mixed martial artist and kickboxer.  He currently runs his own MMA and Muay Thai team in Wormer, Netherlands called Team Schreiber.  His most famous student at the moment is UFC fighter Stefan Struve.  He is internationally known as Bob Schreiber because the Dutch vowel 'ij' is very uncommon in other languages.  He holds the notable distinction of being one of the two fighters to lose to Melvin Manhoef by decision, the other one being Jae-young Kim, and the first to defeat and knock Manhoef out in professional mixed martial arts competition, Manhoef's other 27 wins come by KO/TKO.
[PAR] [TLE] Stefan Struve [ SEP ] Stefan Jaimy Struve ( ; born February 18 , 1988 ) is a Dutch mixed martial artist who competes as a heavyweight in the Ultimate Fighting Championship ( UFC ) . At 7'0 " , he is the current tallest fighter on the roster . [PAR] [TLE] Bob Schrijber [ SEP ] Robert " Bob " Schrijber ( born March 3 , 1965 ) is a Dutch former mixed martial artist and kickboxer . He currently runs his own MMA and Muay Thai team in Wormer , Netherlands called Team Schreiber . His most famous student at the moment is UFC fighter Stefan Struve . He is internationally known as Bob Schreiber because the Dutch vowel ' ij ' is very uncommon in other languages . He holds the notable distinction of being one of the two fighters to lose to Melvin Manhoef by decision , the other one being Jae - young Kim , and the first to defeat and knock Manhoef out in professional mixed martial arts competition , Manhoef 's other 27 wins come by KO / TKO .
How tall is Robert "Bob" Schrijber's most famous student?
How tall is Robert " Bob " Schrijber 's most famous student ?
7'0"
7'0"