I use Debian (Raspbian) Wheezy. If this command line works fine: smsd -c sms/out -i 60 -0 -f sms/smsd.logand this alias also works fine: bsmsd='smsd -c sms/out -i 60 -0 -f sms/smsd.log'then why does this self-same command line in an executable bash script start the command smsd, but does not see any of the parameters I'm specifying? This is the script: #!/bin/bashsmsd -c sms/out -f /home/pi/sms/smsd.log -i 60 -0 -vI've tried redirecting and piping, to no avail. I'm invoking the script (it's called ssmsd) from the command line like so: ./ssmsdAfter that, this is the output from ps -fC smsd: UID        PID  PPID  C STIME TTY          TIME CMDEdit: I know it doesn't recognise the parameters, because it tells me I didn't specify a spooling directory. But I did: -c sms/out. When called from the script, it gives version number and author, and exits.  Perhaps I should add: it calls itself a daemon, but it's not a well-behaved daemon. You can't smsd start|stop|restart it, and it doesn't run in the background. So if I call it from a command line (or with that alias) and then start another terminal and do ps -fC smsd, I get: UID        PID  PPID  C STIME TTY          TIME CMDpi        2860  2621  0 17:49 pts/0    00:00:00 smsd -c xxxxxxx -i 60 -0 -f sms/smsd.log
Command-line parameters in bash script not recognised
bash;shell script;command line