I wrote the below function which successfully creates pairs of dates in the format I need. However, I'm fairly new to Python and feel there must be a way to make this easier to read. Can this code be improved?def getNextTenDays():    dates = []    arrive = datetime.datetime.now()    for n in range(1, 11):        arrive += datetime.timedelta(days=1)        next_day = arrive + datetime.timedelta(days=1)        arrive_s = datetime.datetime.strftime(arrive, '%m/%d/%Y')        next_day_s = datetime.datetime.strftime(next_day, '%m/%d/%Y')        dates.append({'arrive': arrive_s, 'depart': next_day_s})    return dates
Create array of date pairs for next 10 days
python;datetime
Rather that continuing to append to arrive, just use the n offset from 'today'.You can also use call strftime from a datetime object directly, like so:def getNextTenDays():    dates = []    today = datetime.datetime.now()    for n in range(1, 11):        arrive = today + datetime.timedelta(days=n)        next_day = today + datetime.timedelta(days=n+1)        arrive_s = arrive.strftime('%m/%d/%Y')        next_day_s = next_day.strftime('%m/%d/%Y')        dates.append({'arrive': arrive_s, 'depart': next_day_s})    return datesIf you are just going to return the strings, and throw away the actual date times you can do that in one go like so:def getNextTenDays():    dates = []    today = datetime.datetime.now()    for n in range(1, 11):        dates.append({            'arrive': (today + datetime.timedelta(days=n)).strftime('%m/%d/%Y'),            'depart': (today + datetime.timedelta(days=n+1)).strftime('%m/%d/%Y'),        })    return datesFor here its a simple step to making it a list comprehension:def getNextTenDays():    today = datetime.datetime.now()    return [        {            'arrive': (today + datetime.timedelta(days=n)).strftime('%m/%d/%Y'),            'depart': (today + datetime.timedelta(days=n+1)).strftime('%m/%d/%Y'),        }        for n in range(1,11)    ]