I found this very cool code to get upload/download speed:awk '{ if (l1) {        print ($2-l1)/1024kB/s ,($10-l2)/1024kB/s    } else {        l1=$2; l2=$10;    }}' <(grep wlan0 /proc/net/dev) <(sleep 1; grep wlan0 /proc/net/dev)However, it returns up to 4 decimals. I rather have no decimals whatsoever. I have previously been able to round numbers using bc or printf, but I seem to only be able to use print in awk. What is a good solution to this issue?
Formatting numbers using awk / print
bash;awk
#!/bin/awk -f{     if (l1) {             printf( %.2f kB/s  %.2f kB/s\n \               , ($2 - l1) / 1024, ($10 - l2) / 1024)     } else {             l1 = $2;             l2 = $10;     }}%.2f is a floating point number with two decimal places. Use %.0f or %i (integer) to display just the integral part.