I have been having a look at this for a while but I haven't found any answer yet.I've got a curl command to send a HTTP POST request to a server, then I have created a script called tmg.sh which looks like the next one:#! /bin/bashecho There you go:sleep 3scurl http://tmg.xunta.gal/consulta-tarxeta?blah_blah_blah&numero=$1echo Thanks!Right then, so when I write the next command on the terminal:chmode u+x ./tmg.shBecause for some reason even in root account if I don't do this, it returns: bash: ./tmg.sh: Permission denied, but anyway let's go on, after I have done that, when I write the following:./tmg.sh NUMBER_GOES_HEREThat number is the variable, then I got this answer:There you go:<html code not relevant><div class=infoContido><p>Non hai ningunha recarga para o n&uacute;mero de tarxeta introducido.</p></div><html code not relevant>Thanks!Right, here comes my question, how can I get just a part of the whole HTML code? I mean, I just want a part of the website, something like this:Non hai ningunha recarga para o nmero de tarxeta introducido.Also, I'd like to notice that as I get a full page, there are plenty of <p>, <div>... Is that possible, if it is, how should I edit my script to get just this part?Thank you so much and have a lovely day!
How to cut part of a curl answer
shell script;shell;curl;cut;html