In a bash script I define a function that is called from find. The problem is that the scope of variables does not extend to the function. How do I access variables from the function? Here is an example:variable=Filename:myfunction() {    echo $variable $1}export -f myfunctionfind . -type f -exec bash -c 'myfunction {}' \;This will output filenames but without the string Filename:.Is there perhaps a better way to invoke a function from find such that it is called for every file that find finds, and variables are still defined?
Scope of variables when calling function from find
bash;find;function;variable
You could declare variable as an environment variable, i.e.,export variable=Filename: