How to do Rf(:,1:mi2)/Ru ? it is like division, when i use Rf*inv(Ru), as Ru is not square matrix, i can not inv itwould like to do this in c# or F#in Matlab, it is doing as belowRf(:,1:mi2) =  Columns 1 through 5 -105.0504    3.1516   -2.1058   -2.0203    0.0000 -105.2698    3.1611   -2.7366   -1.8278    2.0180 -105.3153    3.1854   -2.7852   -2.6192    1.7987 -105.5817    2.5264   -2.5088   -2.7951    2.3594  Columns 6 through 8   -0.0000   -0.0000    0.0000    0.0000   -0.0000    0.0000   -2.0267   -0.0000    0.0000   -1.8753    1.7196    0.0000Ru =  Columns 1 through 5 -105.2698    3.1611   -2.7366   -1.8278    2.0180 -105.3153    3.1854   -2.7852   -2.6192    1.7987 -105.5817    2.5264   -2.5088   -2.7951    2.3594 -105.7833    2.3793   -2.0379   -2.5519    2.6915  Columns 6 through 8         0         0         0   -2.0267         0         0   -1.8753    1.7196         0   -2.3215    1.6814   -1.7207Rf(:,1:mi2)/Ru =    0.8783    0.3381   -0.0977   -0.1207    1.0000    0.0000   -0.0000   -0.0000         0    1.0000    0.0000         0   -0.0000   -0.0000    1.0000   -0.0000
how to compute Rf(:,1:mi2)/Ru as like in Matlab
algorithms;matlab;matrix