This is what I have so far, so I just want to know if I am doing everything right or wrong. I am novice in the topic.I have been given:$(A \oplus B) \land \neg A \lor A$XOR = $\oplus$By order of operations regroup:$(A \oplus B ) \land (\neg A \lor A)$    // XOR (~A B + A ~B) * ~A + A    // Distributive law(~A ~A B + ~A A ~B) + A          // Idempotent Law~A B + A ~A ~B + A       //   Inverse Law~A B + 0 ~B + A    ~A B + AIs this statement right?
Question simplifying boolean expression
boolean algebra
Note that $\land$ has higher precedence than $\lor$ (see order of precedence@wiki). Therefore, $$(A \oplus B) \land \lnot A \lor A = ((A \oplus B) \land \lnot A) \lor A = (((\lnot A \land B) \lor (A \land \lnot B)) \land \lnot A) \lor A$$Then iteratively apply the distributive law and you will get $A \lor B$.