My sh is bash. I need a percentile progress indicator for my 0~9999 'for' loop... So I use this lines within the loop, but the output is very strange.#!/bin/bashdeclare -i percentilefor((i=0;i<=9999;i++))do        percentile=($i+1)%100        if [ $percentile == 0 ];then                echo -ne $((($i+1)/100))\%\r        fidoneecho -n '\n'What I want to see is it outputs '1%' and then replace this line with '2%' and '3%' ... but not '1%', '2%', '3%', ... line by line.After execute this .sh file, what displayed on the terminal is -ne 1%r-ne 2%r-ne 3%r-ne 4%r-ne 5%r-ne 6%r-ne 7%r-ne 8%r-ne 9%r-ne 10%r...The bash just didn't recognize the '-ne' option and the escaped '\r' for 'echo' command, what should I do to solve this problem?
Can't use echo option within shell script file
shell script;echo;options