Continuing to work my way through some of of Project Euler. Problem 6 solved by my code below. Is it better to use sumOfTheSquares += i*i or utilize Math.Pow()? The sum of the squares of the first ten natural numbers is,  \$1^2 + 2^2 + ... + 10^2 = 385\$  The square of the sum of the first ten natural numbers is,  \$(1 + 2 + ... + 10)^2 = 55^2 = 3025\$Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025  385 = 2640.Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.class Program{    static void Main(string[] args)    {        Console.WriteLine(SumSquareDifference(100));        Console.ReadLine();    }    static int SumSquareDifference(int upperValue)    {        int sumOfTheSquares = 0;        for (int i = 1; i <= upperValue; i++)        {            sumOfTheSquares += (int)Math.Pow(i,2); //Can't formulate this myself...        }        int squareOfTheSums =  (int)Math.Pow((upperValue + 1) * (upperValue / 2),2);        return squareOfTheSums - sumOfTheSquares;    }}
Project Euler Problem 6: Sum square difference
c#;beginner;programming challenge
I don't know about the difference between sumOfTheSquares += i*i and Math.pow() but the sum of squared of first n natural numbers is as follows \$ 1^2 + 2^2 + 3^2 + 4^2 = \dfrac{n(n+1)(2n+1)}{6}\$ So its faster than using a for loop    Edit: General way to prove this is to use mathematical inductionHere's a link!  