code: def replace(string, *reps):
      """Return ``string`` with all keys in ``reps`` replaced with
      their corresponding values, longer strings first, irrespective
      of the order they are given.  ``reps`` may be passed as tuples
      or a single mapping.
  
      Examples
      ========
  
      >>> from sympy.utilities.misc import replace
      >>> replace('foo', {'oo': 'ar', 'f': 'b'})
      'bar'
      >>> replace("spamham sha", ("spam", "eggs"), ("sha","md5"))
      'eggsham md5'
  
      There is no guarantee that a unique answer will be
      obtained if keys in a mapping overlap (i.e. are the same
      length and have some identical sequence at the
      beginning/end):
  
      >>> reps = [
      ...     ('ab', 'x'),
      ...     ('bc', 'y')]
      >>> replace('abc', *reps) in ('xc', 'ay')
      True
  
      References
      ==========
  
      .. [1] https://stackoverflow.com/questions/6116978/how-to-replace-multiple-substrings-of-a-string
      """
      if len(reps) == 1:
          kv = reps[0]
          if isinstance(kv, dict):
              reps = kv
          else:
              return string.replace(*kv)
      else:
          reps = dict(reps)
      return _replace(reps)(string)
  
imports: from __future__ import annotations
  import operator
  import sys
  import os
  import re
  import struct
  from textwrap import fill, dedent
label_desc: Use image node_id 10 for calling a global function with example usage: replace(string) and returns: _replace, string