code: def _is_unorderable_exception(e):
      """
      Check if the exception raised is an unorderable exception.
  
      The error message differs for 3 <= PY <= 3.5 and PY >= 3.6, so
      we need to condition based on Python version.
  
      Parameters
      ----------
      e : Exception or sub-class
          The exception object to check.
  
      Returns
      -------
      boolean : Whether or not the exception raised is an unorderable exception.
      """
  
      if PY36:
          return "'>' not supported between instances of" in str(e)
  
      elif PY3:
          return "unorderable" in str(e)
      return False
  
imports: import warnings
  import numpy
  from pandas._libs import algos, lib
  from pandas._libs.tslibs import conversion
  from pandas.compat import PY3, PY36, string_types
  from pandas.core.dtypes.dtypes import CategoricalDtype, DatetimeTZDtype, ExtensionDtype, IntervalDtype, PandasExtensionDtype, PeriodDtype, registry
  from pandas.core.dtypes.generic import ABCCategorical, ABCDateOffset, ABCDatetimeIndex, ABCIndexClass, ABCPeriodArray, ABCPeriodIndex, ABCSeries
  from pandas.core.dtypes.inference import is_array_like, is_bool, is_complex, is_decimal, is_dict_like, is_file_like, is_float, is_hashable, is_integer, is_interval, is_iterator, is_list_like, is_named_tuple, is_nested_list_like, is_number, is_re, is_re_compilable, is_scalar, is_sequence, is_string_like
label_desc: Use image node_id 34 for calling a global function with example usage: _is_unorderable_exception(e) and returns: False, unknown, unknown