code: def test_difference(self, tz, sort):
      rng_dates = [
          "1/2/2000",
          "1/3/2000",
          "1/1/2000",
          "1/4/2000",
          "1/5/2000",
      ]
  
      rng1 = DatetimeIndex(rng_dates, tz=tz)
      other1 = date_range("1/6/2000", freq="D", periods=5, tz=tz)
      expected1 = DatetimeIndex(rng_dates, tz=tz)
  
      rng2 = DatetimeIndex(rng_dates, tz=tz)
      other2 = date_range("1/4/2000", freq="D", periods=5, tz=tz)
      expected2 = DatetimeIndex(rng_dates[:3], tz=tz)
  
      rng3 = DatetimeIndex(rng_dates, tz=tz)
      other3 = DatetimeIndex([], tz=tz)
      expected3 = DatetimeIndex(rng_dates, tz=tz)
  
      for rng, other, expected in [
          (rng1, other1, expected1),
          (rng2, other2, expected2),
          (rng3, other3, expected3),
      ]:
          result_diff = rng.difference(other, sort)
          if sort is None and len(other):
              # We dont sort (yet?) when empty GH#24959
              expected = expected.sort_values()
          tm.assert_index_equal(result_diff, expected)
  
imports: from datetime import datetime, timezone
  import numpy
  import pytest
  import pytz
  import pandas.util._test_decorators
  import pandas
  from pandas import DataFrame, DatetimeIndex, Index, Series, Timestamp, bdate_range, date_range
  import pandas._testing
  from pandas.tseries.offsets import BMonthEnd, Minute, MonthEnd
label_desc: Use image node_id 17 for calling the TestDatetimeIndexSetOps obj's underlying member method code with example usage: obj.test_difference(tz, sort) without return types