code: def _py__path__(self):
      search_path = self.evaluator.get_sys_path()
      init_path = self.py__file__()
      if os.path.basename(init_path) == "__init__.py":
          with open(init_path, "rb") as f:
              content = python_bytes_to_unicode(
                  f.read(), errors="replace"
              )
              # these are strings that need to be used for namespace packages,
              # the first one is ``pkgutil``, the second ``pkg_resources``.
              options = (
                  "declare_namespace(__name__)",
                  "extend_path(__path__",
              )
              if options[0] in content or options[1] in content:
                  # It is a namespace, now try to find the rest of the
                  # modules on sys_path or whatever the search_path is.
                  paths = set()
                  for s in search_path:
                      other = os.path.join(s, self.name.string_name)
                      if os.path.isdir(other):
                          paths.add(other)
                  if paths:
                      return list(paths)
                  # TODO I'm not sure if this is how nested namespace
                  # packages work. The tests are not really good enough to
                  # show that.
      # Default to this.
      return [self._get_init_directory()]
  
imports: import re
  import os
  from parso import python_bytes_to_unicode
  from jedi.evaluate.cache import evaluator_method_cache
  from jedi._compatibility import iter_modules, all_suffixes
  from jedi.evaluate.filters import GlobalNameFilter, ContextNameMixin, AbstractNameDefinition, ParserTreeFilter, DictFilter, MergedFilter
  from jedi.evaluate import compiled
  from jedi.evaluate.base_context import TreeContext
  from jedi.evaluate.imports import SubModuleName, infer_import
label_desc: Use image node_id 11 for calling the ModuleContext obj's underlying member method code with example usage: obj._py__path__() and returns: list, list