code: def solve():
      """
      It can be seen that the number, 125874, and its double, 251748, contain exactly the same digits, but in a different order.
  
      Find the smallest positive integer, x, such that 2x, 3x, 4x, 5x, and 6x, contain the same digits.
      """
  
      def multiples_have_same_digits(n):
          digit_keys = dict.fromkeys(list(str(n)))
          for x in range(2, 4):
              for d in list(str(x * n)):
                  if d not in digit_keys:
                      return False
          return True
  
      n = 0
      while True:
          n = n + 9  # n must be a multiple of 9 for this to happen
          if multiples_have_same_digits(n):
              return n
              break
  
label_desc: Use image node_id 1 for calling a global function with example usage: solve() and returns: True, n, False