code: def solve(max):
      """
      If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
  
      Find the sum of all the multiples of 3 or 5 below 1000.
      """
  
      n = 0
      for i in range(1, max):
          if not i % 5 or not i % 3:
              n = n + i
  
      return n
  
label_desc: Use image node_id 1 for calling a global function with example usage: solve(max) and returns: n