code: def version_compare(v0: str, v1: str) -> int:
      """Returns 1 if version of v0 is larger than v1 and -1 otherwise
  
      Use this method to compare Python package versions and see which one is
      newer.
  
      Examples:
  
          >>> # compare two versions
          >>> version_compare('1.2.0', '1.1.2')
          >>> 1
      """
      v0_parsed = [int(n) for n in v0.split(".")][::-1]
      v1_parsed = [int(n) for n in v1.split(".")][::-1]
      if len(v0_parsed) != 3 or len(v1_parsed) != 3:
          raise ValueError(
              f"Length of version strings is not 3 (expected pattern `x.y.z`) but is "
              f"{v0_parsed} and {v1_parsed}."
          )
      pairs = list(zip(v0_parsed, v1_parsed))[::-1]
      for x, y in pairs:
          if x < y:
              return -1
          if x > y:
              return 1
      return 0
  
label_desc: Use image node_id 1 for calling a global function with example usage: version_compare(v0, v1) and returns: int, unknown, int