code: def maxArea(
      self,
      h: int,
      w: int,
      horizontalCuts: List[int],
      verticalCuts: List[int],
  ) -> int:
      # Start by sorting the inputs
      horizontalCuts.sort()
      verticalCuts.sort()
  
      # Consider the edges first
      max_height = max(horizontalCuts[0], h - horizontalCuts[-1])
      for i in range(1, len(horizontalCuts)):
          # horizontalCuts[i] - horizontalCuts[i - 1] represents the distance between
          # two adjacent edges, and thus a possible height
          max_height = max(
              max_height, horizontalCuts[i] - horizontalCuts[i - 1]
          )
  
      # Consider the edges first
      max_width = max(verticalCuts[0], w - verticalCuts[-1])
      for i in range(1, len(verticalCuts)):
          # verticalCuts[i] - verticalCuts[i - 1] represents the distance between
          # two adjacent edges, and thus a possible width
          max_width = max(
              max_width, verticalCuts[i] - verticalCuts[i - 1]
          )
  
      # Python doesn't need to worry about overflow - don't forget the modulo though!
      return (max_height * max_width) % (10**9 + 7)
  
label_desc: Use image node_id 1 for calling the Solution obj's underlying member method code with example usage: obj.maxArea(h, w, horizontalCuts, verticalCuts) and returns: unknown