title: Short Circuit Calculations: The Easy Way
author:  J. R. Seiver 
description: This book is written specifically to simplify short circuit calculations. It contains the most streamlined, simplified method of short circuit calculations ever made available. Although in the past the subject of short circuit calculations has been a difficult one, this book shows just how straightforward it can actually be, and how amazingly little time it can take to make highly-accurate short circuit calculations for an entire electrical power system.
zlib_text: 2
  Circuit Elements
  Assessment Problems
  AP 2.1
  [a] To ﬁnd vg write a KVL equation clockwise around the left loop, starting below
  the dependent source:
  −ib
  4 + vg = 0
  so
  vg = ib
  4
  To ﬁnd ib write a KCL equation at the upper right node. Sum the currents
  leaving the node:
  ib + 8 A = 0
  so
  ib = −8 A
  Thus,
  vg = −8
  4 = −2 V
  [b] To ﬁnd the power associated with the 8 A source, we need to ﬁnd the voltage
  drop across the source, vi. To do this, write a KVL equation clockwise around
  the left loop, starting below the voltage source:
  −vg + vi = 0
  so
  vi = vg = −2 V
  Using the passive sign convention,
  ps = (8 A)(vi) = (8 A)(−2 V) = −16 W
  Thus the current source generated 16 W of power.
  2–1
  
  2–2
  CHAPTER 2. Circuit Elements
  AP 2.2
  [a] Note from the circuit that vx = −25 V. To ﬁnd α write a KCL equation at the
  top left node, summing the currents leaving:
  15 A + αvx = 0
  Substituting for vx,
  15 A + α(−25 V) = 0
  so
  α(25 V) = 15 A
  Thus
  α = 15 A
  25 V = 0.6 A/V
  [b] To ﬁnd the power associated with the voltage s