   Sinus
  Hey everybody!Anybody knows how to prove that sin(x) < x for 0 < x < 1?Thanx! 
  Well, just look at the function f(x)=x-sin(x) on that interval. You would like to show that f(x) is always non-negative.  So, note that f(0)=0, and then all you need to show is that the derivative of f on that interval is always positive (thus f is increasing on that interval).   ;  If this is homework, as I suspect, he is probably not allowed to use derivation in the proof. There is quite a simple geometrical proof though. ;  You can write sin(x) as the following infinite sequence:sin(x) = x - (1/(3!))*x^3 + (1/(5!))*x^5 - (1/(7!))*x^7 + (etc..)If x>0 and x<1 the term x^3 is greater or equal to x^5.Additionally (1/(3!)) is greater than (1/(5!)).That is: subtracting (from x) a bigger number between 0..1 and adding a smaller number between 0..1 forces x to be smaller than before these operations.Thus: Computing (x2 = x - (1/(3!))*x^3 + (1/(5!))*x^5) with x in [0,1] yields (x2sequence (with its higher powers).Cheers,   Oliver ;  Thanx for the replies..Can you please explain me what derivation is. (I live in Israel and I just does not know the right term for it in Hebrew.. Sorry). 2pilarsor:Can you please explain me how did you get the following equation:sin(x) = x - (1/(3!))*x^3 + (1/(5!))*x^5 - (1/(7!))*x^7 + (etc..) ;  i think I have understood what derivation of f is:it''s lim h->0 [f(x + h) - f(x)] / h?If it''s this I am not allowed to you this..AnonymousPoster said that there is a simple geometric proof..Can anyone explain it to me?Thanx guys.. ;  > Can you please explain me how did you get the following equation:> sin(x) = x - (1/(3!))*x^3 + (1/(5!))*x^5 - (1/(7!))*x^7 + (etc..) That is the power series, that defines the sine-function.You may look this up in any (good) mathbook.Cheers,  Oliver ;  Search for "Taylor Series" ;  Well, I don''t know how rigorous you want the proof to be.  The geometric argument works well too.  I guess I won''t give it away since it seems that this is a homework assigment, but draw a unit circle and look at some angle x (keeping in mind that an angle is just the length of the arc that it subtends on a unit circle).  Then, look at the sin of the angle.  It should be pretty clear from that. ;  I''ll google it out about "Taylor Series"2yellowjon:What you said is all about intuition.. It''s not a mathematical proof. Thanx anyway..