   vertice array
CUSTOMVERTEX vertices[] =    {{ 100.0f, 400.0f, 0.5f, 1.0f, 0xffff0000, },   { 300.0f,  50.0f, 0.5f, 1.0f, 0xff00ff00, },    { 500.0f, 400.0f, 0.5f, 1.0f, 0xff0000ff, },    }; what means "  0xffff0000?" ?    I know 100.0f, 400.0f, 0.5f, 1.0f, means the point
It's the colour expressed as a 32-bit hexadecimal unsigned int; you can derive these values yourself using the D3DCOLOR_ARGB macro.;You can lay out your CUSTOMVERTEX however you want but I am assuming that the first 4 floats correspond to the position as a float4(x,y,z,w) and the last integer is a vertex color 0xRRGGBBAA for red, green, blue and transparency. In the first one it is probably the color teal. Your input layout determines all of these (D3D11_INPUT_ELEMENT_DESC).;So this sample draw a triangle with three color points, or a blending color triangle?HRESULT InitVB(){//user's data of the points    CUSTOMVERTEX vertices[] =    {{ 100.0f, 400.0f, 0.5f, 1.0f, 0xffff0000, },   { 300.0f,  50.0f, 0.5f, 1.0f, 0xff00ff00, },    { 500.0f, 400.0f, 0.5f, 1.0f, 0xff0000ff, },    };//creat the point buffer area    if( FAILED( g_pd3dDevice->CreateVertexBuffer( 3*sizeof(CUSTOMVERTEX),0, D3DFVF_CUSTOMVERTEX,D3DPOOL_DEFAULT, &g_pVB, NULL ) ) )    {   return E_FAIL;    }//blend    VOID* pVertices;    if( FAILED( g_pVB->Lock( 0, sizeof(vertices), (void**)&pVertices, 0 ) ) )   return E_FAIL;    memcpy( pVertices, vertices, sizeof(vertices) );    g_pVB->Unlock();    return S_OK;};No, that sample draws nothing.  What that sample does is create a vertex buffer and fill it with the data you supply.  It's probably copy and pasted from a tutorial that uses SetFVF with D3DFVF_XYZRHW | D3DFVF_DIFFUSE.  Since it's using SetFVF the actual blending mode (or lack thereof) will depend on the SetTextureStageState calls elsewhere in the tutorial.;menohack, on 21 May 2013 - 08:13, said:the last integer is a vertex color 0xRRGGBBAA for red, green, blue and transparency. In the first one it is probably the color teal.The format is 0xAARRGGBB, so the first color is red. Always use the D3DCOLOR_ARGB() macro when composing colors.L. Spiro   ;Thanks for help, I've figured them out.