   Linked List Problem
  I am new to c++ and i wana make a pathfinding program anyway i want to save positions of the map on a linked list. So i wrote this:typedef class anlist//ALPHANUMERIC LIST{public:anlist(){pointer = 0;_next = 0;x = y = 0;}void add(){if(_next == 0){_next = new anlist;}else{cout << "?";}}~anlist(){if(pointer != 0){delete [] pointer;}if(_next != 0){delete [] _next;}}unsigned short x,y;private:char *pointer;  anlist *_next;}ANLIST;The problem is that when i try to add() a bode to the list it says Debig Assseretion Failed! and an expression _BLOCK_TYPE_IS_VALID(pHEAD->nBlockinuse).But that just doesent make sense !?Any reply would be apriciated   
  If you're using new (rather than new[]), you need to use delete rather than delete[].   ;  Thanks  bakery2k1 cause that was it :S.lol   ;  The real problem seems to be that you're not using the STL (std::list) :)   ;  I am using namespaces :|Isnt that the same ?;  delete & delete[] both check for null-ness, you're just adding one more check like this:if (p != NULL) {    // delete {    if (p != NULL) {   ...    } // } delete}EDIT:  The A.P. meant that you should be using std::list:#include <list>using std::list;int main() {    std::list<int> l;    l.push_back(1);    l.push_front(0);    l.push_front(123);    l.pop_front();    // should be:    // 0 1};  Well i got that about delete but about the stl ?My list is a cust one i am not using list.h.The std::list<int> l;Doesent mean that list is a class template ?and i have wrote using namespace std then the std:: would not be necesary,would it ?PS:How do you put the source code in a box ?   ;  Code in a box in source /source tags, each in square brackets.They mean you "should" use std::list in the sense that it is better to use the tried and tested, writted by experts list class rather than write you own.Writing your own is a very good learning technique though. Just don't do it in any critical, team-based or life-critical applications!   ;Quote:Original post by DigitalBeingMy list is a cust one i am not using list.h.The std::list<int> l;Doesent mean that list is a class template ?Yes, it's a templated class. Hence, you can use it for any type you want, including your own one.Quote:Original post by DigitalBeingand i have wrote using namespace std then the std:: would not be necesary,would it ?You are correct.