   Radius of turn given speed and rate of turn
  Hi, I have a constant rate of turn, (RoT), and a constant speed.I want to calculate the radius of the circle should I turn 360 degrees.What I have is:  // RoT is degrees per seconds and speed is NM per hour  //  // convert everything to seconds  dMinutesTo360 = (360 / dTurnDegreePerSeconds) / 60;  dSpeedToMinutes = dSpeed / (pi * 60 )  // get the radius in NM  dTurnRadius = ( dSpeedToMinutes / 2) * dMinutesTo360;Is the formula above correct?Can you suggest anything else?Many thanksFFMG[Edited by - FFMG on September 6, 2010 6:17:57 AM]
  I'm guessing NM is Newton meters, the SI Torque unit? strange...Anyway, work out how many seconds it takes the car to turn 360 degrees.t(full rotation) = 360 / degrees per second;work out how far the car travels in this time.d = speed*t;Note speed is in m/s. Conversion shouldn't be too tricky.That distance should be the circumference of your turning circle. Given circumference = 2*pi*r,radius = d/(2*pi);;Quote:Original post by PrintFDebuggerI'm guessing NM is Newton meters, the SI Torque unit? strange...Sorry I should have explained it better, NM is nautical miles.Quote:Anyway, work out how many seconds it takes the car to turn 360 degrees.t(full rotation) = 360 / degrees per second;work out how far the car travels in this time.d = speed*t;Note speed is in m/s. Conversion shouldn't be too tricky.That distance should be the circumference of your turning circle. Given circumference = 2*pi*r,radius = d/(2*pi);Thanks for that,FFMG   