   Absolute Motion
  Cheers for any help that can be given.Neil[Edited by - neilski_2003 on April 25, 2006 6:11:12 AM]
Quote:Original post by neilski_2003As the point be is connected to the earth at a distance of 6378000 metres then v = 637800 * 7.27 *10^-5  = 463.68k m/s (which seems quite high to be honest - though checking it against the circumference seems to make it correct)Check your units again, I'm getting 463.8 m/s, which doesn't seem unreasonable.   ;  As for the acceleration - there is no acceleration tangential to the orbit path, but there is a centripetal acceleration, calculated as a = v^2/r.   Hope that helps.   ;  Hi,Thanks very much for that - i'll go back over my workings - i may well have over generalised some numbers somewhere.I'll look into the other thing about the acceleration see what i can mak of it.Oh just to check - would you agree that the velocity of A follows the same as that above just with the extra 240km added to the radius? Cheers fellaNeil   ;Quote:Original post by neilski_2003Oh just to check - would you agree that the velocity of A follows the same as that above just with the extra 240km added to the radius? Yeah, same method different radius.  rhinovirus   ;  top man.Thanks very muchNeil   