   pointer to char
  this workschar *p ;p="xat";cout << p <<endl;i thought you need something like thischar *p=new char[10];   
  "xat" is a string that gets compiled as an array of chars: [x, a, t, \0]when you say char* p="xat";, thet p is the address of the char xthe cout function prints a string that is located at address p. Note that if you compile a string "xat" that a null character (\0) automaticly is added. This means that the string ends here. If there was no null character the program would crash.   ;  Use std::string, there aren't many reasons to use character arrays in C++.Using Modern C++ to Eliminate Memory Problems;  hii was doing some win32 stuff and it doesn't like stringif it is a constant then this shouldn't work but it doeschar *p ;p="xbbat";cout << p <<endl;p="xbbat";cout << p <<endl;;  Win32 is a C-API.  To use std::string with a C-API you need to invoke the c_str() member function whenever you want to pass the string to a function which takes a const char * argument, i.e.:std::string className = "MyWindowClass";std::string windowName = "My Window";CreateWindow(className.c_str(), windowName.c_str(), /*remaining parameters*/);Use std::string."xat" is a contant string.  It has type const char[4].  When you compile your program the executable will contain the bytes 'x', 'a', 't', and '\0', somewhere within the executable image.  When you do char * p = "xat"; you are making p point to the first of those bytes within the executable image.  You are also invoking a special clause in the C++ Standard which allows the conversion of a const char[] to a char *.  Normally a const char[] would be converted to a const char *, but for legacy reasons C++ allows the more lenient conversion.  The bytes that p points are still const however, so attempting to write to them (i.e. *p = 'c';) is undefined behaviour.Is is only the characters themselves which are constant though, not the pointer, which is why the pointer can then be made to point to other things.  If the pointer itself was const then your latest code would fail to compile:const char * p const = "xbbat"; // both the pointer and what it points to are constcout << p << endl;p = "xbbat"; // error - a constant pointer cannot be re-bound.cout << p << endl;Σnigma   