Return a pointer to the user with this name in
 * the list starting with head. Return NULL if no such user exists.
 *
 * NOTE: You'll likely need to cast a (const User *) to a (User *)
 * to satisfy the prototype without warnings.
 */
User *find_user(const char *name, const User *head) {
    //const User *curr = head;
    while (head != NULL) {
        if (strcmp(head->name,name) == 0) {
            return  (User *)head;
            break;
        }
        head = head->next; 
    }
    return NULL;
}
Is this right?