This means aα = p, bβ = p and bγ = a Substituting the third equation in the first one, we have
(bγ)α = bγα = p
Using this in the second equation, we get
bβ = p = bγα
which implies
β = αγ or α = β
γ But then
loga p = log
log
b
b
p
a
(2)
Another interesting property of the log function is its effect on products Let
logb pq = α