05
Similarly,
P(E|B2) = 0 04,  P(E|B3) = 0 02 © NCERT
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 554
MATHEMATICS
Hence, by Bayes' Theorem, we have
P(B2|E) =
2
2
1
1
2
2
3
3
P(B )P(E|B )
P(B )P(E|B )+P(B )P(E|B )+P(B )P(E|B )
=
0