3
Example 2 3
Solution
Solution
Solution
Solution
Solution
Electrical work done in one second is equal to electrical potential
multiplied by total charge passed If we want to obtain maximum work
from a galvanic cell then charge has to be passed reversibly The
reversible work done by a galvanic cell is equal to decrease in its Gibbs
energy and therefore, if the emf of the cell is E and nF is the amount
of charge passed and DrG is the Gibbs energy of the reaction, then
DrG = – nFE(cell)
(2