We shall now evaluate the value of f at these points and at the end points of the
interval [1, 5], i e , at x = 1, x = 2, x = 3 and at x = 5 So
f (1) = 2(13) – 15(12) + 36 (1) + 1 = 24
f (2) = 2(23) – 15(22) + 36 (2) + 1 = 29
f (3) = 2(33) – 15(32) + 36 (3) + 1 = 28
f (5) = 2(53) – 15(52) + 36 (5) + 1 = 56
Thus, we conclude that absolute maximum value of f on [1, 5] is 56, occurring at
x =5, and absolute  minimum value of f on [1, 5] is 24 which occurs at x = 1