Rationalised 2023-24
34
Physics
Flux through the Gaussian surface
=
flux through the curved cylindrical part of the surface
=
E × 2prl
The surface includes charge equal to l l Gauss’s law then gives
E × 2prl = ll/e0
i e ,E  = 
0
2
r
ελ
π
Vectorially, E at any point is given by
0
ˆ
2
r
ελ
=
π
E
n
(1