26)
Here n1 and n2 are the number of moles of solvent and solute
respectively present in the solution For dilute solutions n2 < < n1,
hence neglecting n2 in the denominator we have
10
1
0
1
p
p
p

= 
2
1
n
n
(1 27)
or
10
1
0
1
 -  
 
p
p
p
= 
2
1
2
1
w  × 
 × w
M
M
(1 28)
Here w1 and w2 are the masses and M1 and M2 are the molar masses
of the solvent and solute respectively