So it is a solution of the differential equation (3) Let a and b be given some particular values say a = 2 and 
4
b
=π
, then we get a
function
y = φ1(x) = 2sin
4
x
π
⎛
⎞
+
⎜
⎟
⎝
⎠ (5)
When this function and its derivative are substituted in equation (3) again
L H