Solution If y ≠ 0, the given differential equation can be written as
dy2
y  = – 4x dx (1)
Integrating both sides of equation (1), we get
y∫dy2
 =
4 x dx
− ∫
or
−y1
 = – 2x2 + C
or
y =
212
x −C (2)
Substituting y = 1 and x = 0 in equation (2), we get,  C = – 1 Now substituting the value of C in equation (2), we get the particular solution of the
given differential equation as 
212
1
y
x
=
+