Solution will
contain 20 g of ethylene glycol and 80 g of water Molar mass of C2H6O2 = 12 × 2 + 1 × 6 + 16 × 2 = 62 g mol–1 Moles of C2H6O2 = 
1
20 g
62 g mol
= 0 322 mol
Moles of water = 
-1
80 g
18 g mol
 = 4