Let it be denoted by X Clearly, X
can take the values 0, 1, or 2 Now, since the draws are done with replacement, therefore, the two draws form
independent experiments Therefore,
P(X = 0) = P(non-ace and non-ace)
= P(non-ace) × P(non-ace)
= 48
48
144
52
52
169
×
=
P(X = 1) = P(ace and non-ace or non-ace and ace)
= P(ace and non-ace) + P(non-ace and ace)
= P(ace)