Clearly, we have to find P (KKA)
Now
P(K) = 4
52
Also, P (K|K) is the probability of second king with the condition that one king has
already been drawn Now there are three kings in (52 − 1) = 51 cards Therefore
P(K|K) = 3
51
Lastly, P(A|KK) is the probability of third drawn card to be an ace, with the condition
that two kings have already been drawn Now there are four aces in left 50 cards