This does not
mean that the field of the electric dipole is zero Since the charge q and
–q are separated by some distance, the electric fields due to them, when
added, do not exactly cancel out However, at distances much larger than
the separation of the two charges forming a dipole (r >> 2a), the fields
due to q and –q nearly cancel out The electric field due to a dipole
therefore falls off, at large distance, faster than like 1/r 2 (the dependence
on r of the field due to a single charge q)