(iii)
Let A = 2
2
4
0






 and B = 
1
1
2
0





 Then, it is easy to verify that A = 2B Also
|A| = 0 – 8 = – 8 and |B| = 0 – 2 = – 2 Observe that, |A| = 4(– 2) = 22|B| or |A| = 2n|B|, where n = 2 is the order of
square matrices A and B