Now, since
the potential difference across AB is  Q/C1, across BC is Q/C2, across
CD is  Q/C3 , we have
1
2
3
500 V
Q
Q
Q
C
C
C
+
+
= Also, Q¢/C4 = 500 V This gives for the given value of the capacitances,
3
10
500
F
1 7
10
C
3
Q
V
−
=
×
µ
=
×
 and
3
500
10 F
5