0 S cm2 mol–1
respectively Calculate L
0  for HAc 
mHAc
 
= 
+
–
H
Ac



 
+
–
–
+
–
+
H
Cl
Ac
Na
Cl
Na






 
 
 
 
 
 
= 






HCl
NaAc
NaCl
m
m
m








= (425 9 + 91