Solution Since R1
 and R2 are equivalence relations, (a, a) ∈ R1, and (a, a) ∈ R2 ∀ a ∈ A This implies that (a, a) ∈ R1 ∩ R2, ∀ a, showing R1 ∩ R2 is reflexive Further,
(a, b) ∈ R1 ∩ R2 ⇒ (a, b) ∈ R1 and (a, b) ∈ R2 ⇒ (b, a) ∈ R1 and (b, a) ∈ R2 ⇒
(b, a) ∈ R1 ∩ R2, hence, R1 ∩ R2 is symmetric Similarly, (a, b) ∈ R1 ∩ R2 and
(b, c) ∈ R1 ∩ R2 ⇒ (a, c) ∈ R1 and (a, c) ∈ R2 ⇒ (a, c) ∈ R1 ∩ R2