f2 = –20 cm, u 2 = + (30 – 8) cm = +  22 cm which gives,
v2 = – 220 cm The parallel incident beam appears to diverge
from a point 216 cm from the centre of the two-lens system (ii) Let the parallel beam be incident from the left on the concave
lens  first: f1 = – 20 cm, u1 = – ¥, give v1 = – 20 cm This image
becomes a real object for the second lens: f2 = + 30 cm, u2 =
– (20 + 8) cm = – 28 cm which gives, v2 = – 420 cm