This image becomes
a virtual object for the second lens f2 = –20 cm, u 2 = + (30 – 8) cm = +  22 cm which gives,
v2 = – 220 cm The parallel incident beam appears to diverge
from a point 216 cm from the centre of the two-lens system (ii) Let the parallel beam be incident from the left on the concave
lens  first: f1 = – 20 cm, u1 = – ¥, give v1 = – 20 cm