Thus, the centre of the
circle is (4, 0) and radius is 4 Its intersection
with the parabola y2 = 4x gives
x2 + 4x = 8x
or
x2 – 4x = 0
or
x (x – 4) = 0
or
x = 0, x = 4
Thus, the points of intersection of these
two curves are O(0,0) and P(4,4) above the
x-axis From the Fig 8 16, the required area of
the region OPQCO included between these
two curves above x-axis is
= (area of the region OCPO) + (area of the region PCQP)
= 
4
8
0
4
ydx
ydx
+
∫
∫
= 
4
8
2
2
0
4
2
4
(
4)
x dx
x
dx
+
−
−
∫
∫
   (Why