Thus:
x (Nitrogen)  =  
H
p (nitrogen)
K
 = 0 987bar
76,480 bar  = 1 29 × 10–5
As 1 litre of water contains 55 5 mol of it, therefore if n represents
number of moles of N2 in solution,
x (Nitrogen) = 
 mol 
 mol
n+55