Solution Since the direction ratios of the normal to the plane are 2, –3, 4; the direction
cosines of it are
2
2
2
2
2
2
2
2
2
2
3
4
,
,
2
( 3)
4
2
( 3)
4
2
( 3)
4
−
+ −
+
+ −
+
+ −
+
 , i e , 
2
3
4
,
,
29
29
29
−
Hence, dividing the equation 2x – 3y + 4z – 6 = 0 i e