The answer is in
affirmative and an example of such a function is
y  = f(x) = 10x Our claim is that this function f grows faster than fn (x) = xn for any positive integer n For example, we can prove that 10x grows faster than f100 (x) = x100 For large values
of x like x = 103, note that f100 (x) = (103)100 = 10300 whereas f(103) = 
10103
= 101000