Solution Let x and y be the number of items M and N respectively Total profit on the production = Rs (600 x + 400 y)
Mathematical formulation of the given problem is as follows:
Maximise Z = 600 x + 400 y
subject to the constraints:
x + 2y ≤ 12 (constraint on Machine I) (1)
2x + y ≤ 12 (constraint on Machine II) (2)
x + 5
4  y ≥ 5 (constraint on Machine III)