Profit per hectare on crop X = Rs 10500
Profit per hectare on crop Y = Rs 9000
Therefore, total profit
= Rs (10500x + 9000y)
Corner Point
Z = 50x + 70y
(0,8)
560
(2,4)
380
(10,0)
500
Minimum
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LINEAR PROGRAMMING         517
The mathematical formulation of the problem is as follows:
Maximise
Z = 10500 x + 9000 y
subject  to the constraints:
x + y ≤ 50   (constraint related to land) (1)
20x + 10y ≤ 800 (constraint related to use of herbicide)
i e 2x + y ≤ 80