Example 2 8 A slab of material of dielectric constant K has the same
area as the plates of a parallel-plate capacitor but has a thickness
(3/4)d, where d is the separation of the plates How is the capacitance
changed when the slab is inserted between the plates Solution Let  E0 = V0/d be the electric field between the plates when
there is no dielectric and the potential difference is V0