t x, we have
1 dv
v dx
⋅
 =
(log )
log
d
dy
y
x
x
dx
dx
+
=
1
log
dy
y
x
x
dx
⋅
+
⋅
So
dv
dx  =
log
y
dy
v
x
x
dx


+




=
log
y
y
dy
x
x
x
dx


+



 (3)
Again
w = xx
Taking logarithm on both sides, we have
log w = x log x Differentiating both sides w