Estimate the heat released by the substance in
aligning its dipoles along the new direction of the field For simplicity,
assume 100% polarisation of the sample Solution   Here, dipole moment of each molecules = 10–29 C m
As 1 mole of the substance contains 6 × 1023 molecules,
total dipole moment of all the molecules, p = 6 × 1023 × 10–29 C m
    = 6 × 10–6
 C m
Initial potential energy, Ui = –pE cos q = –6×10–6×106 cos 0° = –6 J
Final potential energy (when q = 60°), Uf = –6 × 10–6 × 106 cos 60° = –3 J
Change in potential energy = –3 J – (–6J) = 3 J
So, there is loss in potential energy This must be the energy released
by the substance in the form of heat in aligning its dipoles