Two events A and B will be independent, if
(A) A and B are mutually exclusive
(B) P(A′B′) = [1 – P(A)] [1 – P(B)]
(C) P(A) = P(B)
(D) P(A) + P(B) = 1
13 5  Bayes' Theorem
Consider that there are two bags I and II Bag I contains 2 white and 3 red balls and
Bag II contains 4 white and 5 red balls One ball is drawn at random from one of the
bags