e ,
x1 =
29
2k , y1 = 
1
3
4
,
29
29
k
k
z
−
=
Fig 11 11
© NCERT
not to be republished
 MATHEMATI CS
482
Substituting these in the equation of the plane, we get k = 
29
6 Hence, the foot of the perpendicular is 12
18 24
,
,
29
29
29
−
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