(c) The power dissipated in the circuit is
2
P
I R
=
Now, I
=im
=


 =
2
1
2
283
5
40A
Therefore, 
A
W
(40 )2
3
4800
P =
×
Ω =
(d) Power factor =
�
�
cos
cos –53 1
0 6
� �
� �
Example 7 9 Suppose the frequency of the source in the previous
example can be varied