If logb p = β and logb q = γ, then bβ = p and bγ = q But then bα = pq = bβbγ = bβ + γ
which implies α = β + γ, i e ,
logb pq = logb p + logb q
Rationalised 2023-24
CONTINUITY AND DIFFERENTIABILITY
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A particularly interesting and important consequence of this is when p = q