9 1 10 2
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
  
193
512
=
(iii) P(at most six heads) = P(X ≤ 6)
= P (X = 0) + P (X = 1) + P (X = 2) + P (X = 3)
+ P (X = 4) + P (X = 5) + P (X = 6)
=
10
10
10
10
10
10
10
1
2
3
1
1
1
1
C
C
C
2
2
2
2
⎛
⎞
⎛
⎞
⎛
⎞
⎛
⎞
+
+
+
⎜
⎟
⎜
⎟
⎜
⎟
⎜
⎟
⎝
⎠
⎝
⎠
⎝
⎠
⎝
⎠
+ 
10
10
10
10
10
10
4
5
6
1
1
1
C
C
C
2
2
2
⎛
⎞
⎛
⎞
⎛
⎞
+
+
⎜
⎟
⎜
⎟
⎜
⎟
⎝
⎠
⎝
⎠
⎝
⎠
= 848
53
1024
64
=
Example 32 Ten eggs are drawn successively with replacement from a lot containing
10% defective eggs