Let us try to
find out The instantaneous power supplied to the inductor is
p
i v
i
t
v
t
L
m
m
=
=
−


(
)
sin
sin
ω
ω
π
2 ×
(
)
(
)
cos
sin
m
i vm
t
t
ω
ω
= −
(
)
sin 2
2
m
i vm
ωt
= −
So, the average power over a complete cycle is
(
)
L
sin 2
2
m
i vm
P
ωt
=
−
(
)
sin 2
2
m
i vm
ωt
= −
= 0,
since the average of sin (2wt) over a complete cycle is  zero Thus, the average power supplied to an inductor over one complete
cycle is zero Example 7