If a DC voltage is applied to the two electrodes, then
Cu 2+ ions discharge at the cathode (negatively charged) and the following
reaction takes place:
Cu2+(aq) + 2e– ® Cu (s)
(2 28)
Copper metal is deposited on the cathode At the anode, copper is
converted into Cu2+ ions by the reaction:
Cu(s) ® Cu2+(s) + 2e–
(2 29)
Thus copper is dissolved (oxidised) at anode and deposited
(reduced) at cathode