It should be noted that because of the symmetry of the network, the
great power of Kirchhoff’s rules has not been very apparent in Example 3 5 In a general network, there will be no such simplification due to symmetry,
and only by application of Kirchhoff’s rules to junctions and closed loops
(as many as necessary to solve the unknowns in the network) can we
handle the problem This will be illustrated in Example 3