17 = 
2
2
2
0
0
3
4
(6
3 )
x dx
x dx
−
−
−
∫
∫
(Why )
= 
2
2
2
2
–1
0
0
4
3
3
4
sin
6
2
2
2
2
x
x
x
x
x



−
+
−
−








= 
–1
2
12
3
0
2sin
(1)
12
2
2

 

×
+
−
−

 


 

π
3
2
6
2
=
×
×
−
 = 3π – 6
Fig 8 17
370
MATHEMATICS
Example 9 Using integration find the area of region bounded by the triangle whose
vertices are (1, 0), (2, 2) and (3, 1)