)
i e ˆ
ˆ
x i
+y j
 =
ˆ
ˆ
ˆ
(3
2
)
( 4
3 )
(1
5
)
i
j
k
+
λ
+
−
λ
+
+
λ
Equating the like coefficients of 
ˆ
ˆ
,ˆ
and
i
j
k , we have
x = 3 + 2 λ
y = 4 – 3 λ
0 = 1 + 5 λ
Solving the above equations, we get
x = 13
23
and
5
5
y =
Hence, the coordinates of the required point are 


5,0
135,23 Miscellaneous Exercise on Chapter 11
1