5
5
xdy
y
dx = −
9 sin1
dy
x
dx
−
=
10 ex tan y dx + (1 – ex) sec2 y dy = 0
For each of the differential equations in Exercises 11 to 14, find a particular solution
satisfying the given condition:
11 3
2
(
1) dy
x
x
x
dx
+
+
+
 = 2x2 + x; y = 1 when x = 0
12