Solution  Considering the mesh BADB, we have
100I1 + 15Ig – 60I2 = 0
or   20I1 + 3Ig – 12I2= 0
[3 65(a)]
Considering the mesh BCDB, we have
10 (I1 – Ig) – 15Ig – 5 (I2 + Ig) = 0
10I1 – 30Ig –5I2 = 0
2I1 – 6Ig – I2 = 0
[3 65(b)]
Considering the mesh ADCEA,
60I2 + 5 (I2 + Ig) = 10
65I2 + 5Ig = 10
13I2 + Ig = 2
[3 65(c)]
Multiplying Eq