Therefore
P(K|K) = 3
51
Lastly, P(A|KK) is the probability of third drawn card to be an ace, with the condition
that two kings have already been drawn Now there are four aces in left 50 cards © NCERT
not to be republished
 542
MATHEMATICS
Therefore
P(A|KK) = 4
50
By multiplication law of probability, we have
P(KKA) = P(K)   P(K|K)  P(A|KK)
= 4
3
4
2
52
51
50
5525
 
 
 
13 4  Independent Events
Consider the experiment of drawing a card from a deck of 52 playing cards, in which
the elementary events are assumed to be equally likely