21), we obtain
ln k2 – ln k1 = 
a
1
E
RT  – 
a
2
E
RT
ln k
k
E
R
T
T
2
1
1
2
1
1
=
−




a
log kk
E
R T
T
2
1
1
2
2 303
1
1
=
−




a
(3 22)
log kk
E
T
T
T T
2
1
2
1
1
2
=2 303
−




a
R
Solution
Solution
Solution
Solution
Solution
Solution
Solution
Solution
Solution
Solution
Example 3