(1)
Differentiating both sides of equation (1) with respect to x, we get
dy
dx  =
  
 
1
2
1
2
–
sin
cos
cos
sin
ax
ax
e
bc
bx
bc
bx
c
bx
c
bx e
a
 
 
 
or
dy
dx  =
2
1
2
1
[(
)cos
(
)sin
]
eax
bc
ac
bx
ac
bc
bx
+
+
− (2)
Differentiating both sides of equation (2) with respect to x, we get
2
d y2
dx
 =
2
1
2
1
[(
) (
sin
)
(
) ( cos
)]
eax
bc
ac
b
bx
ac
bc
b
bx
 
 
 
 
+ 
2
1
2
1
[(
) cos
(
) sin
]
ax bc
ac
bx
ac
bc
bx e
a
+
+
−
=
2
2
2
2
2
1
2
1
2
1
[(
2
) sin
(
2
) cos
]
eax
a c
abc
b c
bx
a c
abc
b c
bx
−
−
+
+
−
Substituting the values of 
2
2 ,
d y dy
dx
dx
 and y in the given differential equation, we get
L H