If the dielectric
is now inserted, the electric field in the dielectric will be E = E0/K The potential difference will then be
0
0
1
3
(
)
(
)
4
4
E
V
E
d
d
K
=
+
0
0
1
3
3
(
)
4
4
K4
E d
V
K
+K
=
+
=
The potential difference decreases by the factor (K + 3)/4K while the
free charge Q0 on the plates remains unchanged The capacitance
thus increases
0
0
0
0
4
4
3
3
Q
Q
K
K
C
C
V
K
V
K
=
=
=
+
+
2 14  COMBINATION OF CAPACITORS
We can combine several capacitors of
capacitance C1, C2,…, Cn to obtain a system with
some effective capacitance C