34)
Therefore, the net reaction at the cathode may be written as the sum
of (2 33) and (2 34) and we have
H2O (l ) + e– ® ½H2(g) + OH–
(2 35)
At the anode the following oxidation reactions are possible:
Cl– (aq) ® ½ Cl2 (g) + e–
(
)
o
Ecell
 = 1