Assume that we have 100 g of solution (one can start with any amount of
solution because the results obtained will be the same) Solution will
contain 20 g of ethylene glycol and 80 g of water Molar mass of C2H6O2 = 12 × 2 + 1 × 6 + 16 × 2 = 62 g mol–1 Moles of C2H6O2 = 
1
20 g
62 g mol
= 0