Therefore,       I =
2
2
–
x
t
t
e dt
e
e
−
−
= −
=
∫
Substituting the value of I in equation (2), we get
2
2
x
y e
−
 =
2
2 + C
 
 
x
e
or
y =
2
2
1
C
x
e
− + (3)
Now (3) represents the equation of family of curves But we are interested in
finding a particular member of the family passing through (0, 1) Substituting x = 0 and
y = 1 in equation (3) we get
1 = – 1 + C