Let
D = a
b
c
d





 Then CD – AB = 0 gives
2
5
2
1
5
2
3
8
3
4
7
4
a
b
c
d
−

 


 

−

 


 


 


 

 = O
or
2
5
2
5
3
0
3
8
3
8
43
22
a
c
b
d
a
c
b
d
+
+




−




+
+




 = 0
0
0
0






or
2
5
3
2
5
3
8
43
3
8
22
a
c
b
d
a
c
b
d
+
−
+




+
−
+
−


 = 0
0
0
0






By equality of matrices, we get
2a + 5c – 3 = 0 (1)
3a + 8c – 43 = 0 (2)
2b + 5d = 0