(2)
Equation (1) is a circle with centre O at the
origin and radius 2 Equation (2) is a circle with
centre C (2, 0) and radius 2 Solving equations
(1) and (2), we have
(x –2)2 + y2 = x2 + y2
or
x2 – 4x + 4 + y2 = x2 + y2
or
x = 1 which gives y =
3
±
Thus, the points of intersection of the given
circles are A(1, 
3 ) and A′(1, –
3 ) as shown in
the Fig 8 19