t = 600 s  charge = current × time = 1 5 A × 600 s = 900 C
According to the reaction:
Cu2+(aq) + 2e– = Cu(s)
We require 2F or 2 × 96487 C to deposit 1 mol or 63 g of Cu For 900 C, the mass of Cu deposited
= (63 g mol–1 × 900 C)/(2 × 96487 C mol–1) = 0 2938 g