When
(–)-2-bromooctane is allowed to react with sodium hydroxide,
(+)-octan-2-ol is formed with the –OH group occupying the position
opposite to what bromide had occupied Thus, SN2 reactions of optically active halides are accompanied by
inversion of configuration In case of optically active alkyl halides, SN1 reactions are
accompanied by racemisation Can you think of the reason why it
happens