It can be calculated
by using the equation:
Lm (S cm2 mol–1) = 
1
3
 (S cm
) × 1000 (cm /L)
molarity (mol/L)


Both type of units are used in literature and are related to each
other by the equations:
1 S m2mol–1
= 104 S cm2mol–1   or
1 S cm2mol–1 = 10–4 S m2mol–1 Resistance of a conductivity cell filled with 0 1 mol L–1 KCl solution is
100 W If the resistance of the same cell when filled with 0