There is a programming language with only four operations and one variable X:


	++X and X++ increments the value of the variable X by 1.
	--X and X-- decrements the value of the variable X by 1.


Initially, the value of X is 0.

Given an array of strings operations containing a list of operations, return the final value of X after performing all the operations.

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Example 1:

Input: operations = ["--X","X++","X++"]
Output: 1
Explanation:&nbsp;The operations are performed as follows:
Initially, X = 0.
--X: X is decremented by 1, X =  0 - 1 = -1.
X++: X is incremented by 1, X = -1 + 1 =  0.
X++: X is incremented by 1, X =  0 + 1 =  1.


Example 2:

Input: operations = ["++X","++X","X++"]
Output: 3
Explanation: The operations are performed as follows:
Initially, X = 0.
++X: X is incremented by 1, X = 0 + 1 = 1.
++X: X is incremented by 1, X = 1 + 1 = 2.
X++: X is incremented by 1, X = 2 + 1 = 3.


Example 3:

Input: operations = ["X++","++X","--X","X--"]
Output: 0
Explanation:&nbsp;The operations are performed as follows:
Initially, X = 0.
X++: X is incremented by 1, X = 0 + 1 = 1.
++X: X is incremented by 1, X = 1 + 1 = 2.
--X: X is decremented by 1, X = 2 - 1 = 1.
X--: X is decremented by 1, X = 1 - 1 = 0.


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Constraints:


	1 &lt;= operations.length &lt;= 100
	operations[i] will be either "++X", "X++", "--X", or "X--".


class Solution:
    def finalValueAfterOperations(self, operations: List[str]) -> int:
        x = 0
        for o in operations:
            if '+' in o:
                x += 1
            else:
                x -= 1
        return x
class Solution {
    public int finalValueAfterOperations(String[] operations) {
        int val = 0;
        for(int i = 0; i<operations.length; i++){
            if(operations[i].charAt(1)=='+') val++;
            else val--;
        }
        return val;
    }
}
class Solution {
public:
    int finalValueAfterOperations(vector<string>& o,int c=0) {
           for(auto &i:o) if(i=="++X" or i=="X++") c++; else c--;
           return c;
    }
};
var finalValueAfterOperations = function(operations) {
    let count = 0;
    for(let i of operations) {
        if(i === 'X++' || i === '++X') count++;
        else count--;
    }
    return count;
};
Final Value of Variable After Performing Operations