You are given an m x n integer grid accounts where accounts[i][j] is the amount of money the i​​​​​​​​​​​th​​​​ customer has in the j​​​​​​​​​​​th​​​​ bank. Return the wealth that the richest customer has.

A customer's wealth is the amount of money they have in all their bank accounts. The richest customer is the customer that has the maximum wealth.

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Example 1:

Input: accounts = [[1,2,3],[3,2,1]]
Output: 6
Explanation:
1st customer has wealth = 1 + 2 + 3 = 6
2nd customer has wealth = 3 + 2 + 1 = 6
Both customers are considered the richest with a wealth of 6 each, so return 6.


Example 2:

Input: accounts = [[1,5],[7,3],[3,5]]
Output: 10
Explanation: 
1st customer has wealth = 6
2nd customer has wealth = 10 
3rd customer has wealth = 8
The 2nd customer is the richest with a wealth of 10.

Example 3:

Input: accounts = [[2,8,7],[7,1,3],[1,9,5]]
Output: 17


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Constraints:


	m ==&nbsp;accounts.length
	n ==&nbsp;accounts[i].length
	1 &lt;= m, n &lt;= 50
	1 &lt;= accounts[i][j] &lt;= 100


class Solution:
    def maximumWealth(self, accounts: List[List[int]]) -> int:
        return max(map(sum, accounts))
class Solution {
    public int maximumWealth(int[][] accounts) {
        int res = 0;
        for(int i =0;i<accounts.length;i++){
            int temp = 0;
            for(int j = 0;j<accounts[i].length;j++){
                temp+=accounts[i][j];
            }
            res = Math.max(res,temp);
        }
        return res;
    }
}
class Solution {
public:
    int maximumWealth(vector<vector<int>>& accounts) {
           int maxWealth = 0;
        for (auto account : accounts) {
            int currentSum = 0;
            for (int x : account) currentSum += x;
            if (currentSum > maxWealth) maxWealth = currentSum;
        }
        return maxWealth;
    }
};
var maximumWealth = function(accounts) {
        var res = 0;
        for(var i =0;i<accounts.length;i++){
            var temp = 0;
            for(var j = 0;j<accounts[i].length;j++){
                temp+=accounts[i][j];
            }
            res = Math.max(res,temp);
        }
        return res;
};
Richest Customer Wealth