Given a string path, which is an absolute path (starting with a slash '/') to a file or directory in a Unix-style file system, convert it to the simplified canonical path.

In a Unix-style file system, a period '.' refers to the current directory, a double period '..' refers to the directory up a level, and any multiple consecutive slashes (i.e. '//') are treated as a single slash '/'. For this problem, any other format of periods such as '...' are treated as file/directory names.

The canonical path should have the following format:


	The path starts with a single slash '/'.
	Any two directories are separated by a single slash '/'.
	The path does not end with a trailing '/'.
	The path only contains the directories on the path from the root directory to the target file or directory (i.e., no period '.' or double period '..')


Return the simplified canonical path.

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Example 1:

Input: path = "/home/"
Output: "/home"
Explanation: Note that there is no trailing slash after the last directory name.


Example 2:

Input: path = "/../"
Output: "/"
Explanation: Going one level up from the root directory is a no-op, as the root level is the highest level you can go.


Example 3:

Input: path = "/home//foo/"
Output: "/home/foo"
Explanation: In the canonical path, multiple consecutive slashes are replaced by a single one.


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Constraints:


	1 &lt;= path.length &lt;= 3000
	path consists of English letters, digits, period '.', slash '/' or '_'.
	path is a valid absolute Unix path.


class Solution:
   def simplifyPath(self, path: str) -> str:
   	stack = []
   	
   	i = 0
       while i < len(path):
           if path[i] == '/':
               i += 1
               continue

           else:
               cur = ''
               while i < len(path) and path[i] != '/':
                   cur += path[i]
                   i += 1

               if cur == '..':
                   if stack:
                       stack.pop()
               elif cur == '.' or cur == '':
                   i += 1
                   continue
               else:
                    stack.append(cur)

       return '/' + '/'.join(stack)
class Solution {
    public String simplifyPath(String path) {
        String[] paths = path.split("/");
        Stack<String> st=new Stack<>();
        for(String dir:paths){
            if(dir.equals(".") || dir.length()==0) continue;
            else{
                if(!st.isEmpty() && dir.equals(".."))
                    st.pop();
                else if(st.isEmpty() && dir.equals(".."))
                    continue;
                else st.push(dir);
            }
        }
        StringBuilder sb=new StringBuilder();
        if(st.isEmpty()) return "/";
        for(String s:st){
            sb.append("/"); sb.append(s);
        }
        return sb.toString();
    }
}
                    // Please upvote if it helps
class Solution {
public:
    string simplifyPath(string path) {

        stack<string> st;
        string res;

        for(int i = 0; i<path.size(); ++i)
        {
            if(path[i] == '/')
                continue;
            string temp;
            // iterate till we doesn't traverse the whole string and doesn't encounter the last /
            while(i < path.size() && path[i] != '/')
            {
                // add path to temp string
                temp += path[i];
                ++i;
            }
            if(temp == ".")
                continue;
            // pop the top element from stack if exists
            else if(temp == "..")
            {
                if(!st.empty())
                    st.pop();
            }
            else
            // push the directory file name to stack
                st.push(temp);
        }

        // adding all the stack elements to res
        while(!st.empty())
        {
            res = "/" + st.top() + res;
            st.pop();
        }

        // if no directory or file is present
        if(res.size() == 0)
            return "/";

        return res;
    }
};
var simplifyPath = function(path) {
    let stack=[];
    path=path.split("/")
    for(let i=0;i<path.length;i++){
        if(path[i]==="" || path[i]===".")continue;
        if(path[i]===".."){
            stack.pop();
        }else{
            stack.push(path[i]);
        }
    }
    //edge case
    if(stack.length===0)return "/"
    //edge case

    let string="";
    for(let j=0;j<stack.length;j++){
        string+="/"+stack[j];
    }
    return string;
};
Simplify Path