Given two non-negative integers low and high. Return the count of odd numbers between low and high&nbsp;(inclusive).

&nbsp;
Example 1:

Input: low = 3, high = 7
Output: 3
Explanation: The odd numbers between 3 and 7 are [3,5,7].

Example 2:

Input: low = 8, high = 10
Output: 1
Explanation: The odd numbers between 8 and 10 are [9].

&nbsp;
Constraints:


	0 &lt;= low &lt;= high&nbsp;&lt;= 10^9

class Solution:
    def countOdds(self, low: int, high: int) -> int:        
        total_nums = high - low
        
        answer = total_nums // 2
        
        if low % 2 == 1 and high % 2 == 1:
            return answer + 1
        
        if low % 2 == 1:
            answer = answer + 1
            
        if high % 2 == 1:
            answer = answer + 1
        
        return answer
class Solution {
    public int countOdds(int low, int high) {
        if(low%2==0 && high%2==0){
            return (high-low)/2;
        }
        return (high-low)/2+1;
    }
}
class Solution {
public:
    int countOdds(int low, int high) {
        if (low%2 == 0 && high%2 == 0 ){
            return (high - low)/2;
        }
        else{
            return (high - low)/2 + 1;
        }

    }
};
var countOdds = function(low, high) {
    let total = 0;
    for (let i = low; i <= high; i++) {
        if (i % 2 !== 0) {
            total++;
        }
    }
    return total;
};
Count Odd Numbers in an Interval Range