anchor.diff:  Then you may think that _docatch2_ is associated on the outer doTry because of how the code is formatted.
   But it is **not**, both __docatch1__ and __docatch2__ are in the inner doTry, and the outer doTry has no catch blocks.
   
  -So in this example the route will throw the 1st exception which is then handled in __docatch1__ which
  -then throw a 2nd exception, that is not caught.
  +So in this example the route will throw the 1st exception which is then handled in __docatch1__ which then throw a 2nd exception, that is not caught.
   
   So what you must do is to end the doCatch block correct (notice how we use `doEndTry()` two times) as shown below:
   
  
positive.code: ----
  
  And by using the `doEndTry()` we can end the block correctly, and an XML representation of the route would be as follows:
  [source,xml]
  ----
  <?xml version="1.0" encoding="UTF-8" standalone="yes"?>
  <route xmlns="http://camel.apache.org/schema/spring">
      <from uri="direct:test"/>
      <doTry>
          <doTry>
  
negative.code:     </doTry>
  </route>
  ----
  