anchor.diff:  
   ! x(3) corresponds to the harmonic oscillator pseudo-frequency
     ind(3) = 3        ! Has both an upper and lower bound
  -  bl(3)  = 400.     ! Lower bound is 400 cm^-1
  +  bl(3)  = 180.     ! Lower bound is 180 cm^-1
     bu(3)  = 4000.    ! Upper bound is 4000 cm^-1
   
   !  Define the initial guess for the solution
  
positive.code:   bu(6)  = 600.    ! Upper bound is 600 cm^-1
  
  !  Define the initial guess for the solution
    x(1) = 1000.0 !Barrier Height
    x(2) = 80.0 !Hind. Freq
    x(3) = 2000.0 !Barrier Height
    x(4) = 150.0 !Hind. Freq
    x(5) = 3000.0 !Barrier Height
    x(6) = 300.0 !Hind. Freq
  
negative.code: 
  ! x(2) corresponds to the first harmonic oscillator pseudo-frequency
    ind(2) = 3        ! Has both an upper and lower bound
    bl(2)  = 180.     ! Lower bound is 180 cm^-1
    bu(2)  = 4000.    ! Upper bound is 4000 cm^-1
  
  ! x(3) corresponds to the second harmonic oscillator pseudo-frequency
    ind(3) = 3        ! Has both an upper and lower bound
    bl(3)  = 180.     ! Lower bound is 180 cm^-1
    bu(3)  = 4000.    ! Upper bound is 4000 cm^-1
  
  ! x(4) corresponds to the degeneracy of the first hindered rotor
  