anchor.diff:  
   
   
  -;;
   ;; Exercise 3.12 [m]
   ;;
   ;; Write a single expression using 'format' that will take a list of
  
positive.code:   ((lambda (x)
       ((lambda (x y) (+ x y))  x (* x x))) 
     6))
  
  
  
  
negative.code: (defun length10 (lst)
    (reduce #'(lambda (elem) (count (list elem)))))
  
  
  
  ;;
  ;; Exercise 3.10 [m]
  ;
  