def get_version_naive(cls, name, ignore=''):
        """ Checks a string for a possible version of an object (no prefix, no suffix) without filtering date out
            Assumes only up to 4 digit padding

        :param name: str, string that represents a possible name of an object
        :return: (float, int, list(str), None), gets the version number then the string matches
        """
        match = cls._get_regex_search(name, cls.REGEX_VERSION.format(SEP=cls.REGEX_SEPARATORS), ignore=ignore)

        if match is not None:
            if len(match) > 1:
                for m in match:
                    m.update({'version': int(m['match'].upper().replace('V', ''))})
                compound_version = '.'.join([str(m['version']) for m in match])
                compound_version = float(compound_version) if compound_version.count('.') == 1 else compound_version
                return {'compound_matches': match,
                        'compound_version': compound_version,
                        'pattern': match[0]['pattern'],
                        'input': match[0]['input']}

            elif len(match) == 1:
                match = match[0]
                match.update({'version': int(match['match'].upper().replace('V', ''))})
                return match

        return None