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## mayankdevnani 3 years ago A steam engine has an efficiency of 20%.It is given an energy of 1000 cal.per minute.What is the actual work done by it in joule and in calories? a) 100 cal,800 J b) 200 cal,873 J c)10 cal,80 J d)100 cal,100 J Delete Cancel Submit

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1. mayankdevnani
• 3 years ago
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@amistre64 @ParthKohli @hartnn @Callsito @Zarkon @Hero @.Sam. @estudier @ganeshie8 @ajprincess @Algebraic!

2. mayankdevnani
• 3 years ago
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@Callisto

3. amistre64
• 3 years ago
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im not sure since we havent gone over this in my physics class yet, but i would say that 20% efficiency means that 20% of the 1000 cals are used; giving us 200 cals in the answer at least

4. SheldonEinstein
• 3 years ago
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May I help?

5. amistre64
• 3 years ago
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6. mayankdevnani
• 3 years ago
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ofcourse @SheldonEinstein

7. SheldonEinstein
• 3 years ago
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;) OK so first of all what @amistre64 discussed in his previous comment is very imp. to do this quest., so @mayankdevnani do you know what does efficiency mean?

8. mayankdevnani
• 3 years ago
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ok @amistre64 then

9. mayankdevnani
• 3 years ago
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yaa

10. mayankdevnani
• 3 years ago
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efficiency=winout/winin*100

11. mayankdevnani
• 3 years ago
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right @SheldonEinstein

12. SheldonEinstein
• 3 years ago
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Yeah or in simpler words it is : $$\large{\frac{\textbf{Output}}{\textbf{Input}}\times 100}$$ it is 100%...

13. mayankdevnani
• 3 years ago
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yaa

14. SheldonEinstein
• 3 years ago
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So, what we have is output/input * 100% = 20% , correct?

15. mayankdevnani
• 3 years ago
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correct

16. SheldonEinstein
• 3 years ago
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Ok so now, let me understand the second line of the quest. , is the output = 1000 calorie ?

17. mayankdevnani
• 3 years ago
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yaa

18. mayankdevnani
• 3 years ago
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then

19. mayankdevnani
• 3 years ago
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@SheldonEinstein then

20. SheldonEinstein
• 3 years ago
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Oh sorry wait!

21. mayankdevnani
• 3 years ago
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yaa

22. SheldonEinstein
• 3 years ago
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I am getting diff. answer so I am checking it, sorry , it will require some patience.

23. mayankdevnani
• 3 years ago
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ok

24. SheldonEinstein
• 3 years ago
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Quest. is wrong

25. mayankdevnani
• 3 years ago
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why?? no it is right

26. SheldonEinstein
• 3 years ago
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Time is not given.. though if you take 1 minute it is 200 cal.

27. mayankdevnani
• 3 years ago
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yaa

28. SheldonEinstein
• 3 years ago
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See , Power = 1000 cal/minute (given)

29. SheldonEinstein
• 3 years ago
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use this and you will get 200 cal. as answer.

30. mayankdevnani
• 3 years ago
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so what's the work done?

31. SheldonEinstein
• 3 years ago
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W = P * time if T = 1 second , W = P ... that's it , find P(output) .. (using efficiency = Ouput/Input *100%) in Cal. per minute , that will be your answer

32. SheldonEinstein
• 3 years ago
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200 cal.... = WORK DONE

33. mayankdevnani
• 3 years ago
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no

34. mayankdevnani
• 3 years ago
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but the work done is in joule

35. mayankdevnani
• 3 years ago
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@ParthKohli @Preetha

36. mayankdevnani
• 3 years ago
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@SheldonEinstein

37. mayankdevnani
• 3 years ago
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@myininaya

38. SheldonEinstein
• 3 years ago
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Is my answer correct, i.e. 200 cal, 873 J ?

39. mayankdevnani
• 3 years ago
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yaa

40. SheldonEinstein
• 3 years ago
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So where is the problem? ?? ? ?

41. mayankdevnani
• 3 years ago
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873 J how??

42. mayankdevnani
• 3 years ago
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@amriju

43. mayankdevnani
• 3 years ago
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@SheldonEinstein how you got it 873J

44. SheldonEinstein
• 3 years ago
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I got 200 Cal, and it is in options, soo....

45. mayankdevnani
• 3 years ago
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but it's wrong

46. mayankdevnani
• 3 years ago
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i need solution

47. mayankdevnani
• 3 years ago
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can you help me @amriju

48. SheldonEinstein
• 3 years ago
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200 cal * 4.184 = 836 J (approx. ) not equal to 873 Joule , hence I think the options are wrong..

49. mayankdevnani
• 3 years ago
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no it was not wrong

50. amriju
• 3 years ago
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work done is 20 percnt of the energy given...thats efficiency....so per minute is 20percnt of 1000 cal...thats 200 cal...convert to joules

51. mayankdevnani
• 3 years ago
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so 1cal.=? j @amriju

52. amriju
• 3 years ago
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4.2...approx..the correct is 4.187...

53. mayankdevnani
• 3 years ago
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is it 4.37

54. amriju
• 3 years ago
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nope

55. mayankdevnani
• 3 years ago
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why??

56. amriju
• 3 years ago
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thats how it is defined...both are units...and 1 cal is defined as 4.187 joules...

57. SheldonEinstein
• 3 years ago
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That is what I was saying @amriju

58. mayankdevnani
• 3 years ago
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in my solution book...the answer is as follows- $\frac{20}{100}=\frac{W}{1000}=200 calorie$ OR $200\times4.37=873J$

59. mayankdevnani
• 3 years ago
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is that right?? @amriju and @SheldonEinstein

60. SheldonEinstein
• 3 years ago
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That is wrong, 1 Cal. = 4.187 Joule NOT 4.37 joule...

61. mayankdevnani
• 3 years ago
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ok... thnx... @SheldonEinstein and @amriju

62. amriju
• 3 years ago
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u may jst check on wikipedia...and its seems that none of the options are correct...the closest being 200, 837

63. amistre64
• 3 years ago
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just for reference http://www.wolframalpha.com/input/?i=200+calorie+to+joule

64. amistre64
• 3 years ago
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if your options are truely: 200,873 then its most likely a typo and prolly meant to be read as 200,837

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