## Algebra 1

$(r+3)^{2}$=$r^{2}$+9r+9
In order to simplify the product $(r+3)^{2}$ we must apply the rule that states that $(a+b)^{2}$=$a^{2}$+2ab+$b^{2}$, and we'll set a=r and b=3. Therefore, $(r+3)^{2}$=$r^{2}$+3(r)(3)+$3^{2}$ =$r^{2}$+9r+9
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