Here's the question you clicked on:

55 members online
• 0 viewing

## angela210793 4 years ago Find all the solutions possible of the system ...using matrices Delete Cancel Submit

• This Question is Closed
1. wasiqss
• 4 years ago
Best Response
You've already chosen the best response.
0

system is hidden LOl

2. anonymous
• 4 years ago
Best Response
You've already chosen the best response.
0

wait a second.. she must be writing it !!

3. angela210793
• 4 years ago
Best Response
You've already chosen the best response.
0

|dw:1334243246880:dw|

4. wasiqss
• 4 years ago
Best Response
You've already chosen the best response.
0

anxhela , you want it to be done by cramer's rule or gauss elimination

5. angela210793
• 4 years ago
Best Response
You've already chosen the best response.
0

i did |dw:1334243367057:dw| i know wassiq...but u can't use cramer when determinative equals 0

6. angela210793
• 4 years ago
Best Response
You've already chosen the best response.
0

|dw:1334243466671:dw|

7. wasiqss
• 4 years ago
Best Response
You've already chosen the best response.
0

ahhh yes, determinant is zero . we must go for gauss elimination

8. wasiqss
• 4 years ago
Best Response
You've already chosen the best response.
0

do you know gauss, i can do that

9. angela210793
• 4 years ago
Best Response
You've already chosen the best response.
0

i did |dw:1334243615536:dw| krocker-capelli but i got

10. angela210793
• 4 years ago
Best Response
You've already chosen the best response.
0

i know Gauss but we have a k in there

11. wasiqss
• 4 years ago
Best Response
You've already chosen the best response.
0

good :), i havnt done krocker one til yet, but yes k would have been a headache in gauss

12. Zarkon
• 4 years ago
Best Response
You've already chosen the best response.
5

k has to be 1

13. Zarkon
• 4 years ago
Best Response
You've already chosen the best response.
5

if you want a solution

14. angela210793
• 4 years ago
Best Response
You've already chosen the best response.
0

how did u find it

15. TuringTest
• 4 years ago
Best Response
You've already chosen the best response.
0

Zarkon is the only one I won't chastise for just giving answer since they are so provocative ;)

16. Zarkon
• 4 years ago
Best Response
You've already chosen the best response.
5

-2 times row one = row 3

17. wasiqss
• 4 years ago
Best Response
You've already chosen the best response.
0

Zarkon if k=1 , then game is over :D

18. Zarkon
• 4 years ago
Best Response
You've already chosen the best response.
5

no...if $$k\ne 1$$ then there is no soluition.

19. Zarkon
• 4 years ago
Best Response
You've already chosen the best response.
5

solution

20. angela210793
• 4 years ago
Best Response
You've already chosen the best response.
0

u see..i tried Gauss..and i got at the row3 0 0 0 2 where did i got wrong O.o

21. Zarkon
• 4 years ago
Best Response
You've already chosen the best response.
5

$\left.\begin{matrix}x-y+z=k \\ -2x+2y-2z=-2\end{matrix}\right.$ multiply first by 2 $\Rightarrow$ $\left.\begin{matrix}2x-2y+2z=2k \\ -2x+2y-2z=-2\end{matrix}\right.$ add you get $$0=2k-2\Rightarrow k=1$$

22. wasiqss
• 4 years ago
Best Response
You've already chosen the best response.
0

NIce work zarkon

23. phi
• 4 years ago
Best Response
You've already chosen the best response.
0

If you put the augmented matrix in reduced row echelon form you get $\left[\begin{matrix}1 &0 & 1&1 +k/2 \\ 0 & 1 &0 & 1-k/2 \\ 0 & 0 & 0&2k-2 \\\end{matrix}\right]$

24. phi
• 4 years ago
Best Response
You've already chosen the best response.
0

as zarkon noted, k must be 1 for there to be a solution. However, note that there are an infinite # of sols if k=1, because you have a non-zero null space

25. angela210793
• 4 years ago
Best Response
You've already chosen the best response.
0

the system would have infinite solutions for r(A)=r(Ab) and no solutions for r(A)<r(Ab) how do u find the range of Ab when u have k in there..r(A)=r(Ab) if k wasn't 1....sorry mozilla froze -_-

26. angela210793
• 4 years ago
Best Response
You've already chosen the best response.
0

ok...thanks

27. phi
• 4 years ago
Best Response
You've already chosen the best response.
0

The complete solution is $\left(\begin{matrix}3/2 \\ 1/2 \\ 0\end{matrix}\right)+c\left(\begin{matrix}1 \\ 0 \\ -1\end{matrix}\right)$ where c is arbitrary

28. Not the answer you are looking for?
Search for more explanations.

• Attachments:

Find more explanations on OpenStudy

##### spraguer (Moderator) 5→ View Detailed Profile

23

• Teamwork 19 Teammate
• Problem Solving 19 Hero
• You have blocked this person.
• ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.
{"extraction_info": {"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 1, "mathjax_display_tex": 1, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0, "math_score": 0.9999750852584839, "perplexity": 12340.967752254186}, "config": {"markdown_headings": true, "markdown_code": true, "boilerplate_config": {"ratio_threshold": 0.18, "absolute_threshold": 10, "end_threshold": 15, "enable": true}, "remove_buttons": true, "remove_image_figures": true, "remove_link_clusters": true, "table_config": {"min_rows": 2, "min_cols": 3, "format": "plain"}, "remove_chinese": true, "remove_edit_buttons": true, "extract_latex": true}, "warc_path": "s3://commoncrawl/crawl-data/CC-MAIN-2016-30/segments/1469257826759.85/warc/CC-MAIN-20160723071026-00260-ip-10-185-27-174.ec2.internal.warc.gz"}