# The phase difference between two points separated by 1 m in a wave of frequency 120hz is 90 degree .The wave velocity will be …....?

Arun
25757 Points
5 years ago
Dear Gaurav

Path difference $\Delta$ = $\lambda \phi$/2$\pi$

1 = ($\lambda$/2$\pi$) * ($\pi$/2)
$\lambda$ = 4 m

Hence
V = n* $\lambda$ = 120*4 = 480 m/sec.

Regards
Rishi Sharma
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