1. ## Simplifying another expression

$\frac{(-4)^2x^2(yz)^4}{-16xy^{-4}z}$

So:

$\frac{-16x^2y^4z^4}{-16xy{-4}z}$

Then:

$xy^8z^3$

However, I'm told the correct answer is $-xy^8z^3$

Why $-x$ instead of $x$ ?

2. Remember, when you square a negative number, the result is always positive. In your numerator, you have (-4)². The answer to that is 16, not -16.

I think you got it from here.

3. Oh. You are absolutely right! I completely forgot about that.
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