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## InsanelyChaotic 2 years ago HOW ON EARTH DO I DO THIS??? Delete Cancel Submit

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1. AravindG
• 2 years ago
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Ofcourse you cant do it on MOON

2. InsanelyChaotic
• 2 years ago
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##### 4 Attachments
3. InsanelyChaotic
• 2 years ago
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@AravindG

4. AravindG
• 2 years ago
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Are all these 4 pics referring to same question?

5. InsanelyChaotic
• 2 years ago
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yes

6. AravindG
• 2 years ago
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I see 5 questions .Which one do you have doubt on ?

7. InsanelyChaotic
• 2 years ago
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all of them. they literally make no sense. this whole time i thought it was one problem. it wan't set up correctly in the word doc format

8. AravindG
• 2 years ago
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1. root(27)=root(3*9)

9. AravindG
• 2 years ago
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root(3*9)=root(3) *root (9)

10. AravindG
• 2 years ago
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I hope you can do it after that

11. InsanelyChaotic
• 2 years ago
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should i plug the roots into the calc?

12. InsanelyChaotic
• 2 years ago
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@AravindG

13. InsanelyChaotic
• 2 years ago
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14. AravindG
• 2 years ago
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nope for example $\sqrt{2}x-\sqrt{8} \times 3=\sqrt{2}x-\sqrt{4 \times 2} \times 3 =\sqrt{2}x-2\sqrt{2} \times 3$ $=\sqrt{2} \times (x-6)$

15. AravindG
• 2 years ago
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This is how to do these type of problems

16. InsanelyChaotic
• 2 years ago
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i just need help this makes no sense

17. InsanelyChaotic
• 2 years ago
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@Best_Mathematician

18. InsanelyChaotic
• 2 years ago
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@Aperogalics

19. InsanelyChaotic
• 2 years ago
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@Chooch146

20. Aperogalics
• 2 years ago
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@InsanelyChaotic how can i help u ????????

21. InsanelyChaotic
• 2 years ago
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With the problem listed above please. it makes no sense and i just want to cry.

22. Aperogalics
• 2 years ago
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don't cry first of all :) let us solve

23. Aperogalics
• 2 years ago
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first question |dw:1367947608900:dw| in such type of questions we have to take common now second part can be factorise so |dw:1367947718184:dw| but in square root if a no. comes twice that is a pair of two then it comes out and only one term remains i.e.|dw:1367947798491:dw| so back to question |dw:1367947833712:dw| got it if yes then tell me i will proceed to second :)

24. InsanelyChaotic
• 2 years ago
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so far so good!!:)))))))))

25. Aperogalics
• 2 years ago
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ok so let solve second one....... r u ready ??????

26. InsanelyChaotic
• 2 years ago
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|dw:1367951666372:dw|

27. Aperogalics
• 2 years ago
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ok 3*3= is a pair so we can take it out it's a property of square roots if it is cubic then a pair of three .....etc e.g.|dw:1367948458812:dw|

28. Aperogalics
• 2 years ago
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if u got redy then mention me :)

29. InsanelyChaotic
• 2 years ago
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perf:))))

30. Aperogalics
• 2 years ago
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so should we proceed??????

31. Aperogalics
• 2 years ago
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@InsanelyChaotic ?????????

32. InsanelyChaotic
• 2 years ago
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33. InsanelyChaotic
• 2 years ago
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sorry i was taking notes on your genuis work

34. Aperogalics
• 2 years ago
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k :) second question |dw:1367949085845:dw| just type so not to switch other window :)

35. InsanelyChaotic
• 2 years ago
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|dw:1367952732165:dw|

36. Aperogalics
• 2 years ago
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$3\sqrt{4xy}$

37. Aperogalics
• 2 years ago
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now |dw:1367949356565:dw|

38. Aperogalics
• 2 years ago
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try to do this :)

39. InsanelyChaotic
• 2 years ago
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dont know

40. InsanelyChaotic
• 2 years ago
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all of which is makes me is want to kill myelf

41. Aperogalics
• 2 years ago
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no it happens to me also when i start these square root and all this but now i just do it :)

42. Aperogalics
• 2 years ago
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so better not to kill urself :)

43. InsanelyChaotic
• 2 years ago
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thank you...tempting though

44. Aperogalics
• 2 years ago
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k first multiply the terms outside the square root and tell the answer :)

45. InsanelyChaotic
• 2 years ago
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okay bb

46. InsanelyChaotic
• 2 years ago
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ab^2

47. Aperogalics
• 2 years ago
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a&b are not the terms :)

48. InsanelyChaotic
• 2 years ago
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oops thats awkward

49. InsanelyChaotic
• 2 years ago
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you probably think i'm stupid

50. Aperogalics
• 2 years ago
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no i think everything is going messed up in ur mind and u r trying to solve by heart otherwise either u will leave it or you tore the paper ;)

51. InsanelyChaotic
• 2 years ago
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awww that was beautiful

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