Algebra: A Combined Approach (4th Edition)

$(3x+2)(2x-5)$
$6x^{2}−11x−10$ First, identify two numbers that multiply with each other to become -60, the product of the constant and coefficient of $x^{2}$ (6 × -10) and add together to become -11, the coefficient of x. From inspection, we identify these numbers as 4 and -15. Secondly split the coefficient of x into the sum of the two above numbers. $6x^{2}−11x−10$ $=6x^{2}+(4-15)x−10$ $=6x^{2}+4x-15x−10$ Factorize by grouping to find the answer. $6x^{2}+4x-15x−10$ $=2x(3x+2)-5(3x+2)$ $=(3x+2)(2x-5)$
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