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# Calculate the molar mass of each of the following:$$\begin{array}{llll}{\text { (a) } \operatorname{Sr}(\mathrm{OH})_{2}} & {\text { (b) } \mathrm{N}_{2} \mathrm{O}_{3}} & {\text { (c) } \mathrm{NaClO}_{3}} & {\text { (d) } \mathrm{Cr}_{2} \mathrm{O}_{3}}\end{array}$$

## a) $\operatorname{Mr}\left(\operatorname{Sr}(\mathrm{OH})_{2}\right)=121,62 \mathrm{g} / \mathrm{mol}$b) $\operatorname{Mr}\left(\mathrm{N}_{2} \mathrm{O}_{3}\right)=76,02 \mathrm{g} / \mathrm{mol}$c) $\operatorname{Mr}\left(\mathrm{NaClO}_{3}\right)=106,44 \mathrm{g} / \mathrm{mol}$d) $\operatorname{Mr}\left(\mathrm{Cr}_{2} \mathrm{O}_{3}\right)=98 \mathrm{g} / \mathrm{mol}$

#### Topics

Chemical reactions and Stoichiometry

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### Video Transcript

All right, so we have to found him with a mass off difference. Ah, chemical compound. The first real strong Liam hydroxide. So for finding money mess off different chemical compound which first did you found out about the mass off the individual elements. So far stronger anyway, 87.62 you can find from a testicle off from your periodic table. And if I lost, you were 16 hydrogen, everyone. So we have one strong. Um so we're 87.62 Ah, and then we have to hydroxide, which means we have two unit off oxygen and hydrogen, so we have to times 16 plus one. All right, so when you Yeah. When? When we looked at all the number together, we would have to over or on the mass. Ah, you would be corresponding to our strong hydroxide. Okay. When we follow the same coagulation, we should be able to find the west of it are the second commas and 203 ny Dinei Children try oxide. So we have Ah, we have to know nitrogen So naturally minutes roughly. Ah, about ah, look, a task book of our 14. So actually, I'm with other two. We have 14 town times, two plus three times 16 and then we should be able to find a 76 gram per mo for and two or three and then we'll phone. We have any CEO three. So we have sodium while their mother mass will be foreign 23 Cory with for five or six when we were 16 times for you. So I can just are cold later able to find it, Find out that is one those six Grampa Monroe and therefore crew die chromium um oxide Ah, for chromium Ah, we have favorites you for Quimper more from your passbook And then we have two of them from Mumbai to you and therefore oxygen were 16 someone by three and imagine to get over years to 105 grand per mo

University of Toronto

#### Topics

Chemical reactions and Stoichiometry

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