# Sergey Finsky

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bio website location Minsk, Belarus age 21 member for 2 years, 4 months seen 12 mins ago profile views 24

I like math and computer science.

# 52 Actions

 Jan30 asked Induced representation, Ind(Res(U)) Jan6 accepted Cantor-Bendixson theorem proof Jan5 asked Cantor-Bendixson theorem proof Dec23 comment Number of representable as sum of 2 squares Yes, it'd be nice if somebody posted whole proof, because it's know quite straightforward. But thank you very much, I would never expect to see asymptotics for this problem, thought, there'll be only some bounds. Dec23 accepted Number of representable as sum of 2 squares Dec23 revised Number of representable as sum of 2 squares added 6 characters in body Dec23 comment Number of representable as sum of 2 squares Sure, I meant $\Omega$. Thank you. Dec23 asked Number of representable as sum of 2 squares Dec23 comment Asymptotics with prime of form 4k+3 Yes, but in the paper we consider $L$-function, which is but it's definition a series (not finite), so we have to somehow jump from the infinite series to finite. (It's easy to do when the convergence in series is uniform, but it's obviously not the case) I mean, your previous comment is obviously true, but why $\sum_{p \equiv a \mod d \le n} \frac{1}{p} \sim \frac{\log(\log(n))}{\phi (d)}$. Do you see what I mean? Dec23 comment Asymptotics with prime of form 4k+3 Thank you very much for your answer, but I have one question left: in papers it's proven that $\sum_{p \equiv a \pmod d} \frac{1}{p^{s}} \sim \dfrac1{\phi(d)}\sum_{p} \frac{1}{p^{s}}$ when $s \to +1$. But how does original problem follows from this? (It is not obvious) Dec22 accepted Asymptotics with prime of form 4k+3 Dec22 revised Asymptotics with prime of form 4k+3 there was a mistake in sum of prime fractions Dec22 comment Asymptotics with prime of form 4k+3 Thank you, sure I did. =) Dec22 asked Asymptotics with prime of form 4k+3 Dec4 accepted Asymptotics of exponential integral Dec4 asked Asymptotics of exponential integral Nov23 comment Lebesgue measure is invariant under isometry Thank you guys very much. I just want to supply your beautiful answers with some links. proof that translation invariant measure is Lebesgue measure up to a constant factor Nov22 asked Lebesgue measure is invariant under isometry Nov18 awarded Supporter Nov18 accepted Closed surjective map
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