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# find value of $K_1$ and $K_2$ for which $y= \large\frac{x}{K_1} $$+K_2 is a solution of differential equation y''-2y' -3y=x (a)\;(-3, -\frac{2}{9}) \\ (b)\;(\frac{-2}{9},3) \\ (c)\;(-2,3) \\ (d)\;no\; real\; K_1\;and\;K_2 Can you answer this question? ## 1 Answer 0 votes y= \large\frac{x}{K_1}$$+K_2$
$y'= \large\frac{1}{K_1}$
$y''=0$
Put in equation
$0- \large\frac{2}{K_1}$$-3\bigg( \large\frac{x}{K_1}$$+K_2\bigg) =x$
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