# Thread: finding lengths of this shape :/

1. ## finding lengths of this shape :/

heya everyone

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have been puzzling at this for over an hour now :/ tried using simutaneous equations

$20^2 = x^2 + (a+b)^2$ - pithag..
$30^2 = y^2 + (a+b)^2$ - pithag
$x / 8 = (a + b) / b$ - height/length ratios
$y / 8 = (a + b) / a$ - height/length ratios...

where a and b is D split up into the smaller triangles...

but solving these seems very tedious..anyone that can help?

oh btw the problem is solve X Y and D

ps. the 8 is the length of the blue line. sorry its a bit sketchy
edit2: math wrapped it lol.

- pithag..
- pithag
- height/length ratios
- height/length ratios...

where a and b is D split up into the smaller triangles...
OK let d=a+b ..so b=d-a ok

now you have

$400=x^2+d^2$.......(1)

$900=y^2+d^2$....(2)

$\frac{x}{8}=\frac{d}{d-a}$...(3)

$\frac{y}{8}=\frac{d}{a}$....(4)

and from (3)

$a=\frac{d(x-8)}{x}$

sub this in equation (4)

$\frac{y}{8}=\frac{d}{\dfrac{d(x-8)}{x}}$

$y(d(x-8))=8dx$

$y=\frac{8x}{x-8}$

you continue it is now obvious right
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