Here's the question you clicked on:

55 members online
• 0 viewing

## anonymous one year ago Factor x^2-12x+36-49y^2 Delete Cancel Submit

• This Question is Closed
1. anonymous
• one year ago
Best Response
You've already chosen the best response.
0

I have x^2+24x-49y^2 so far

2. anonymous
• one year ago
Best Response
You've already chosen the best response.
0

$a^2-b^2=\left( a+b \right)\left( a-b \right)$ $x^2-12x+36-49y^2=\left( x-6 \right)^2-\left( 7y \right)^2=?$

3. anonymous
• one year ago
Best Response
You've already chosen the best response.
0

um x^2-12x-36-49y^2

4. anonymous
• one year ago
Best Response
You've already chosen the best response.
0

I'm lost

5. jim_thompson5910
• one year ago
Best Response
You've already chosen the best response.
1

Hint: $\Large (x-6)^2 - (7y)^2$ $\Large ({\color{red}{x-6}})^2 - ({\color{blue}{7y}})^2$ $\Large ({\color{red}{a}})^2 - ({\color{blue}{b}})^2 = ({\color{red}{a}}-{\color{blue}{b}})({\color{red}{a}}+{\color{blue}{b}})$

6. jim_thompson5910
• one year ago
Best Response
You've already chosen the best response.
1

$\Large x^2 - 12x + 36 = (x-6)^2$ $\Large 49y^2 = (7y)^2$

7. anonymous
• one year ago
Best Response
You've already chosen the best response.
0

Would that be all?

8. jim_thompson5910
• one year ago
Best Response
You've already chosen the best response.
1

no there's one more step

9. anonymous
• one year ago
Best Response
You've already chosen the best response.
0

Hit me :)

10. jim_thompson5910
• one year ago
Best Response
You've already chosen the best response.
1

use the difference of squares rule to factor $\Large (x-6)^2 - (7y)^2$

11. anonymous
• one year ago
Best Response
You've already chosen the best response.
0

(x-6)^2=x^-12x-36 right? (7y)^2=49y^2 right?

12. jim_thompson5910
• one year ago
Best Response
You've already chosen the best response.
1

you're going backwards though

13. jim_thompson5910
• one year ago
Best Response
You've already chosen the best response.
1

what I'm aiming for is to go from this $\Large ({\color{red}{x-6}})^2 - ({\color{blue}{7y}})^2$ to this $\Large ({\color{red}{x-6}}-{\color{blue}{7y}})({\color{red}{x-6}}+{\color{blue}{7y}})$ I used the difference of squares rule

14. jim_thompson5910
• one year ago
Best Response
You've already chosen the best response.
1

it's like saying x^2 - 64 factors to (x-8)(x+8)

15. anonymous
• one year ago
Best Response
You've already chosen the best response.
0

Oh!! I get it now haha :D Thank you!

16. jim_thompson5910
• one year ago
Best Response
You've already chosen the best response.
1

np

17. Not the answer you are looking for?
Search for more explanations.

• Attachments:

Find more explanations on OpenStudy

##### spraguer (Moderator) 5→ View Detailed Profile

23

• Teamwork 19 Teammate
• Problem Solving 19 Hero
• You have blocked this person.
• ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.
{"extraction_info": {"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 1, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0, "math_score": 0.9999910593032837, "perplexity": 26401.042613791506}, "config": {"markdown_headings": true, "markdown_code": true, "boilerplate_config": {"ratio_threshold": 0.18, "absolute_threshold": 10, "end_threshold": 15, "enable": true}, "remove_buttons": true, "remove_image_figures": true, "remove_link_clusters": true, "table_config": {"min_rows": 2, "min_cols": 3, "format": "plain"}, "remove_chinese": true, "remove_edit_buttons": true, "extract_latex": true}, "warc_path": "s3://commoncrawl/crawl-data/CC-MAIN-2016-44/segments/1476988722459.85/warc/CC-MAIN-20161020183842-00435-ip-10-171-6-4.ec2.internal.warc.gz"}