1. ## help dividing polynomials?

how to solve this?

2. Originally Posted by deekay930
how to solve this?

hi
$\displaystyle \frac{2x^2y+8x^2y^3+y}{4xy}=\frac{2x^2y}{4xy}+\fra c{8x^2y^3}{4xy}+\frac{y}{4xy}=2x+8xy^2+\frac{1}{4x }$

3. Originally Posted by Raoh
hi
$\displaystyle \frac{2x^2y+8x^2y^3+y}{4xy}=\frac{2x^2y}{4xy}+\fra c{8x^2y^3}{4xy}+\frac{y}{4xy}=2x+8xy^2+\frac{1}{4x }$
i think i made a mistake

4. Originally Posted by Raoh
i think i made a mistake
$\displaystyle \frac{2x^2y+8x^2y^3+y}{4xy}=4xy(\frac{1}{2}x+2xy)+ y$
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