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chadandtricia_2009 Group Title What is the factored form of the expression? k2 – 9h2 A. (k + 3h)(k + 3h) B. h2(k + 3)(k – 3) C. (k + 3h)(k – 3h) D. (k – 3h2)(k + 3) 2 years ago 2 years ago Edit Question Delete Cancel Submit

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1. doubledrive
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A

• 2 years ago
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can you show me how you got that please?

• 2 years ago
3. zeesbrat3
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A

• 2 years ago
4. doubledrive
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Nevermind, C

• 2 years ago
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i don't understand how to do it

• 2 years ago
6. doubledrive
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K*K=K2 +3*-3=-9 H*H=H2

• 2 years ago
7. Calcmathlete
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It is C. You have to first recognize the fact that this is a difference in squares pattern. $a^{2} - b^{2} = (a + b)(a - b)$

• 2 years ago
8. doubledrive
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Which becomes k2-9h2

• 2 years ago
9. Calcmathlete
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If you want to factor it without the pattern, then find factors of -9 that add up to 0. These factors are -3 and 3. THerefore, (k + 3h)(k – 3h)

• 2 years ago
10. zeesbrat3
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In this problem you are dealing with perfect squares, so it was easier just to square root them. However, that only works if all of them are actually perfect squares. If you don't know what a perfect square is, it is a number multiplied by itself.

• 2 years ago
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so what do I plug into the pattern?

• 2 years ago
12. Calcmathlete
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a = k b = 3h See how k is squared and 3h is squared as well? k^2 = k^2 3^2h^2 = 9h^2

• 2 years ago
13. zeesbrat3
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$K timesK =K ^{2} 3h\times3h=9h /sqrt{9}=3$

• 2 years ago
14. zeesbrat3
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sorry, it didnt space out like I planned..

• 2 years ago
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ok got it now.

• 2 years ago
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thanks alot all of you

• 2 years ago
17. myininaya
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@zeesbrat3 and @doubledrive In the future, please don't just give the answer (sometimes people just want to cheat and that is not what OpenStudy is about.) Please guide the user so that the person can come to the answer themselves. Also @chadandtricia_2009 thanks for asking for an explanation. :)

• 2 years ago
18. myininaya
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And that message goes to anyone I miss that didn't know the new CoC. thanks.

• 2 years ago
19. doubledrive
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@myininaya for your information, i answered the question and i explained it.

• 2 years ago
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