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## Study23 Group Title Please help me with this limit!!! 2 years ago 2 years ago Edit Question Delete Cancel Submit

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1. Study23
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$$\ \Huge \lim_{h \rightarrow 0} \ \frac{(2+h)^3-8}{h} .$$ Do I just multiply h/h, to get 1 on the denominator??

• 2 years ago
2. satellite73
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no you multiply out

• 2 years ago
3. satellite73
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$$(2+h)^3=...$$

• 2 years ago
4. satellite73
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then subtract 8 and the usual miracle will occur everything without an $$h$$ will be gone, so you can factor an $$h$$ out of the numerator, cancel with the $$h$$ in the denominator, then replace $$h$$ by 0

• 2 years ago
5. Study23
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How do I expand the trinomial?

• 2 years ago
6. satellite73
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?

• 2 years ago
7. satellite73
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if you do not know that $$(a+b)^2=a^3+3a^2b+3ab^2+a^3$$ then you have the annoying task of multiplying by hand $(2+h)(2+h)(2+h)$

• 2 years ago
8. satellite73
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one more time $(a+b)^3=a^3+3a^2b+3ab^2+b^3$

• 2 years ago
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