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# How would you prepare 250. mL of a 0.175 M solution of Cobalt(II) Chloride from the solid and distilled water?

Mar 15, 2018

Consider that solutions are solutes dissolved in solvent.

Here, our solute is cobalt (II) chloride and our solvent is distilled water.

The volume of solute is generally ignored, so we would dissolve,

$250 \text{mL" * "L"/(10^3"mL") * 0.175"M" * (129.9"g")/"mol" approx 5.68"g}$

of cobalt (II) chloride in approximately $250 \text{mL}$ of distilled water to create the solution in the lab.

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