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## moser90 3 years ago Solve the system of equations using matrices. Use Gauss-Jordan elimination 3x-7y-7z = 7 6x+4y-3z=67 -6x-3y+z=-62 Delete Cancel Submit

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1. across
• 3 years ago
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Hint:$\begin{bmatrix} 3 & -7 & -7\\ 6 & 4 & -3\\ -6 & -3 & 1 \end{bmatrix}\begin{bmatrix} x\\ y\\ z \end{bmatrix}=\begin{bmatrix} 7\\ 67\\ -62 \end{bmatrix}.$

2. moser90
• 3 years ago
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so does x = 7

3. nincompoop
• 3 years ago
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hmm

4. nincompoop
• 3 years ago
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did you use Michael Jordan Elimination method to arrive at x=7?

5. moser90
• 3 years ago
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the book I am using is really confusing it says I have to get 1 on top but I don't know how

6. nincompoop
• 3 years ago
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7. moser90
• 3 years ago
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I see how to do it when the number is 0 or 1 but I don't know how to start with the 3

8. psi9epsilon
• 3 years ago
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@across almost gave you the cramers rule use it to find values of x, y, and z

9. nincompoop
• 3 years ago
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10. moser90
• 3 years ago
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okay I used that but my answers I think are what is confusing me these are my choices a. {(7,1,7)} b. {14,7,-7)} c. {(-7,7,14)} d. {(7,7,1)}

11. across
• 3 years ago
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If you have choices, all you have to do is substitute, I mean, slam-dunk them and check!

12. moser90
• 3 years ago
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I did that and none of them equal up

13. moser90
• 3 years ago
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that is the way they are

14. Hero
• 3 years ago
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I'm interested in knowing that this Michael Jordan method is

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