## Calculus: Early Transcendentals 8th Edition

a. $\frac{dA}{dt} = 2\pi r \times \frac{dr}{dt}$ b. $\frac{dA}{dt} = 60\pi m^2/s$
a. $A(r) = \pi r^2$ $\frac{dA}{dt} = \frac{d(\pi r^2)}{dt}$ $\frac{dA}{dt} = 2\pi r \times \frac{dr}{dt}$ b.$\frac{dA}{dt} = 2\pi r \times \frac{dr}{dt}$ $\frac{dA}{dt} = 2\pi (30) \times (1)$ $\frac{dA}{dt} = 60\pi m^2/s$
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