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## ajprincess 3 years ago Note to the viewers: This is nt a question. I made a mistake in certain portion of my previous post which was a tutorial on trigonometric identities and this is the correct version of it. Delete Cancel Submit

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1. ajprincess
• 3 years ago
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jst a moment then.

2. ajprincess
• 3 years ago
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$sin(A+B)=sinAcosB+cosAsinB$ $cos(A+B)=cosAcosB-sinAsinB$ $sin(A-B)=sinAcosB-cosAsinB$ $cos(A-B)=cosAcosB+sinAsinB$

3. Valpey
• 3 years ago
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You can also write: $sin(A\pm B)=sinAcosB\pm cosAsinB$ $cos(A\pm B)=cosAcosB\mp sinAsinB$

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