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## anonymous 5 years ago compute the integral: (8x^2+6)/(x^2+1)(x+7) Delete Cancel Submit

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1. anonymous
• 5 years ago
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It is basically $\int\limits_{}^{} 8x ^{2}+6 - \int\limits_{}^{}x ^{3}+7x ^{2}+x+7$

2. anonymous
• 5 years ago
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thank you so much

3. anonymous
• 5 years ago
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i also have another question :( compute the indefinite integral: dx/(x^2+4)^(5/2)

4. anonymous
• 5 years ago
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i am sorry, I was thinking of logarithms. Please ignore my previous answer. My integration is rusty. i'll get back to you with the correct answer.

5. anonymous
• 5 years ago
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okay

6. anonymous
• 5 years ago
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the original question is; compute the integral:$\int\limits_0{}^{1} (8x^2+6) / (x^2+1)(x+7) dx$

7. anonymous
• 5 years ago
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do you know integration by partial fractions? Understanding of that is essential to this problem http://www.math.ucdavis.edu/~kouba/CalcTwoDIRECTORY/partialfracdirectory/PartialFrac.html scroll down till you see how the partial fractions are done

8. anonymous
• 5 years ago
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thanks !

9. anonymous
• 5 years ago
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This is how to solve your problem. The numerator in this example is also a quadratic equation and the denominator is a cubic equation: http://www.math.ucdavis.edu/~kouba/CalcTwoDIRECTORY/partialfracsoldirectory/PartialFracSol2.html#SOLUTION%209

10. anonymous
• 5 years ago
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got it:)

11. anonymous
• 5 years ago
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12. anonymous
• 5 years ago
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http://openstudy.com/updates/4d948f880ffe8b0bcdc9a720 can you help me with that problem ? :(

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