1. ## Normal Probability Distributions....

I am totally lost....

I changed the problem around a bit, but it is similar in form to this, on my homework.

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How would I go about solving this?

Thanks,
Thomas

2. the absolute value of something |Z|, is always equal to Z or -Z.

So
$P(|Z| > 1) = P(Z > 1) + P(-Z > 1)$
ie, the absolute value of Z is greater than one if Z>1, or -Z > 1.

try applying this to your problem and post again if you are stuck.
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