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butterflyprincess Group Title H E L P : Cos (13pi/12 ) Use Half Angle ID to simplify ~ one year ago one year ago Edit Question Delete Cancel Submit

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1. butterflyprincess Group Title
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I got : -root 3 - root 6 / 4 Is that what you got..?

• one year ago
2. Venomblast Group Title
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• one year ago
3. butterflyprincess Group Title
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What do you mean? You just use that ID to simplify?

• one year ago
4. Venomblast Group Title
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but i dont what ID.

• one year ago
5. jim_thompson5910 Group Title
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$\Large \cos\left(\frac{13\pi}{12}\right) = \cos\left(\frac{1}{2}\cdot\frac{13\pi}{6}\right)$ $\Large \cos\left(\frac{13\pi}{12}\right) = -\sqrt{\frac{1+\cos\left(\cdot\frac{13\pi}{6}\right)}{2}}$ $\Large \cos\left(\frac{13\pi}{12}\right) = -\sqrt{\frac{1+\frac{\sqrt{3}}{2}}{2}}$ $\Large \cos\left(\frac{13\pi}{12}\right) = -\sqrt{\frac{1}{2}+\frac{\sqrt{3}}{4}}$ $\Large \cos\left(\frac{13\pi}{12}\right) = -\sqrt{\frac{2}{4}+\frac{\sqrt{3}}{4}}$ $\Large \cos\left(\frac{13\pi}{12}\right) = -\sqrt{\frac{2+\sqrt{3}}{4}}$ $\Large \cos\left(\frac{13\pi}{12}\right) = -\frac{\sqrt{2+\sqrt{3}}}{\sqrt{4}}$ $\Large \cos\left(\frac{13\pi}{12}\right) = -\frac{\sqrt{2+\sqrt{3}}}{2}$

• one year ago
6. butterflyprincess Group Title
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cool thnx! (:

• one year ago
7. jim_thompson5910 Group Title
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yw

• one year ago
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