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# How do you rationalize the denominator and simplify (sqrt3)/(sqrt(5c))?

Jul 4, 2017

$\frac{\sqrt{15}}{5 c}$

#### Explanation:

$\frac{\sqrt{3}}{\sqrt{5 c}}$

To rationalize the denominator, we need to multiply the top and bottom by $\sqrt{5 c}$.

$\frac{\sqrt{3} \times \sqrt{5 c}}{\sqrt{5 c} \times \sqrt{5 c}}$

$\frac{\sqrt{15 c}}{{\sqrt{5 c}}^{2}}$

The square root and the square cancel each other out, so we are left with

$\frac{\sqrt{15}}{5 c}$

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