# Solve for a range of values

I am trying to solve the following eqn for Tco. The ultimate goal is to Plot Tco for zb values from 0 to 12.

hc = 6109.526
qNBzn=25605.9
Solve[446265 Sin[
12/143 π (0.001958 +
zb)] == {(hc*(Tco - (569 +
4.87*^-9 (5.032*^9 - 5.03*^9 Cos[0.26 zb] +
2.60*^6 Sin[0.26 zb]))))*{1 + {((446265 Sin[
12/143 π (0.001958 + zb)])/(hc*(Tco - (569 +
4.87*^-9 (5.03*^9 - 5.03*^9 Cos[0.26 zb] +
2.6*^6 Sin[0.26 zb])))))*(1 -
qNBzn/(446265 Sin[12/143 π (0.001958 + zb)]))}^2}^(1/
2)}, Tco ]

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You should search around here ...

hc = 6109.526;
qNBzn=25605.9;
eq = {446265 Sin[12/143 π (0.001958 + zb)],
(hc*(Tco - (569 + 4.87*^-9 (5.032*^9 - 5.03*^9 Cos[0.26 zb] +
2.60*^6 Sin[0.26 zb]))))*(1 + (((446265 Sin[
12/143 π (0.001958 + zb)])/(hc*(Tco - (569 +
4.87*^-9 (5.03*^9 - 5.03*^9 Cos[0.26 zb] +
2.6*^6 Sin[0.26 zb])))))*(1 -
qNBzn/(446265 Sin[12/143 π (0.001958 + zb)])))^2)^(1/2)}

Plot3D[eq, {Tco, 500, 700}, {zb, 0, 20 Pi}, PlotStyle -> {Red, Green}, PlotPoints -> 30]


Like this:

ListLinePlot[Tco /. FindRoot[(Equal @@ eq /. zb -> #), {Tco, 1}] & /@
Range[0, 11.5, .5], PlotRange -> All]
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