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## Barrelracing one year ago Solve x2 + 2x + 9 = 0 A) X=-2 + or - 4i squareroot 2 b) x= -2 + or - 2i squareroot 2 c) x= -1 + or - 4i squareroot 2 d) x = -1 + or - 2i squareroot 2 Delete Cancel Submit

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1. anonymous
• one year ago
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$Given: x^2 + 2x + 9 = 0\\ as\ discriminant\ of\ this\ eq\, D= 2^2-4.1.9=4-36=-32<0\\hence\ its\ roots\ are\ imaginary\\use\ quadratic\ formula\\x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\\ here\ a=1,\ b=2,\ c=9\\we\ have\ x=\frac{ -2 \pm \sqrt{2^2-4.1.9} }{ 2.1 }\\x=\frac{ -2 \pm \sqrt{4-36} }{ 2}\\x=\frac{ -2 \pm \sqrt{-32} }{ 2}\\x=\frac{ -2 \pm \sqrt{2.i^2.4.4} }{ 2}\\x=\frac{ -2 \pm i4\sqrt{2} }{ 2 }\\x=-1\pm\ i2\sqrt{2}$

2. anonymous
• one year ago
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@Barrelracing option d correct

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