# Math Help - solving equations?

1. ## solving equations?

how would I solve these?

2. ## no see

the first one you can cross multiply

$x\sqrt{23} = 8\sqrt{6}$

$x=\frac{8\sqrt{6}}{\sqrt{23}}$

the second simlifies to

$\frac{x^2}{2}$

4. I fixed it.

5. [quote=bigwave;426920]the first one you can cross multiply

$x\sqrt{23} = 8\sqrt{6}$

$x=\frac{8\sqrt{6}}{\sqrt{23}}$

okay.

6. $\frac{\sqrt{3x^8}}{\sqrt{12x^2}}$

$\sqrt{\frac{3x^8}{12x^2}}$

$\sqrt{\frac{x^4}{4}}$

$\frac{x^2}{2}$

Edit: bigwave, it's not $\frac{x^3}{2}$, it's $\frac{x^2}{2}$
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