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## anonymous one year ago Please Help! I Need Explanation & Help On How To Do This!!!! Medal and Fan?!?! Delete Cancel Submit

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1. anonymous
• one year ago
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√(8x+1)=5

2. anonymous
• one year ago
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i need to solve for x and identify if it is an extraneous solution.

3. anonymous
• one year ago
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Is it $$\huge \sqrt{8x+1}=5$$ ?

4. anonymous
• one year ago
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yes

5. anonymous
• one year ago
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$$\huge (\sqrt{8x+1})^2=(5)^2$$

6. anonymous
• one year ago
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where did you get the power of 2?

7. anonymous
• one year ago
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So you square both sides to remove the radical sign.

8. anonymous
• one year ago
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ohhhh nvm wait

9. anonymous
• one year ago
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i understand why lol

10. anonymous
• one year ago
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It would now be: $$\huge 8x+1=25$$

11. anonymous
• one year ago
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so x equals 3??

12. anonymous
• one year ago
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Yes! To check if it's an extraneous solution, plug in $$\huge x=3$$ to the equation.

13. anonymous
• one year ago
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$$\huge \sqrt{8(3)+1}=5; x=3$$

14. anonymous
• one year ago
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whats the difference between non extraneous and extraneous?

15. anonymous
• one year ago
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extraneous: not a real solution non extraneous: real solution / the x/root is true

16. anonymous
• one year ago
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$$\huge \sqrt{24+1}=5$$ $$\huge \sqrt{25}=5$$ Is this true?

17. anonymous
• one year ago
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yeah

18. anonymous
• one year ago
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ok thank you so much!!!

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