human
Find addresses that are linked to more than one building.
gpt
```sparql
PREFIX :     <http://example.org/ontology#>
PREFIX rdf:  <http://www.w3.org/1999/02/22-rdf-syntax-ns#>

SELECT ?addr (COUNT(?building) AS ?bCount)
WHERE {
  ?building rdf:type :Building ;
            :hasAddress ?addr .
}
GROUP BY ?addr
HAVING(COUNT(?building) > 1)
```