def points(self, amount=100, start=0.0, end=1.0, segments=None):
        """ Returns an iterator with a list of calculated points for the path.
            To omit the last point on closed paths: end=1-1.0/amount
        """
        # Originally from nodebox-gl
        if len(self._elements) == 0:
            raise PathError("The given path is empty")
        n = end - start
        d = n
        if amount > 1:
            # The delta value is divided by amount-1, because we also want the last point (t=1.0)
            # If we don't use amount-1, we fall one point short of the end.
            # If amount=4, we want the point at t 0.0, 0.33, 0.66 and 1.0.
            # If amount=2, we want the point at t 0.0 and 1.0.
            d = float(n) / (amount - 1)
        for i in xrange(int(amount)):
            yield self.point(start + d * i, segments)
def points(self, amount=100, start=0.0, end=1.0, segments=None):
        """ Returns an iterator with a list of calculated points for the path.
            To omit the last point on closed paths: end=1-1.0/amount
        """
        # Originally from nodebox-gl
        if len(self._elements) == 0:
            raise PathError("The given path is empty")
        n = end - start
        d = n
        if amount > 1:
            # The delta value is divided by amount-1, because we also want the last point (t=1.0)
            # If we don't use amount-1, we fall one point short of the end.
            # If amount=4, we want the point at t 0.0, 0.33, 0.66 and 1.0.
            # If amount=2, we want the point at t 0.0 and 1.0.
            d = float(n) / (amount - 1)
        for i in xrange(int(amount)):
            yield self.point(start + d * i, segments)
def points ( self , amount = 100 , start = 0.0 , end = 1.0 , segments = None ) : # Originally from nodebox-gl if len ( self . _elements ) == 0 : raise PathError ( "The given path is empty" ) n = end - start d = n if amount > 1 : # The delta value is divided by amount-1, because we also want the last point (t=1.0) # If we don't use amount-1, we fall one point short of the end. # If amount=4, we want the point at t 0.0, 0.33, 0.66 and 1.0. # If amount=2, we want the point at t 0.0 and 1.0. d = float ( n ) / ( amount - 1 ) for i in xrange ( int ( amount ) ) : yield self . point ( start + d * i , segments )
Returns an iterator with a list of calculated points for the path.
            To omit the last point on closed paths: end=1-1.0/amount
Returns an iterator with a list of calculated points for the path . To omit the last point on closed paths : end = 1 - 1 . 0 / amount