



from __future__ import annotations

from statistics import mean

def 			A_      (	__a     :				list[int] ,		__a     :				list[int] ,		__a     :				int		):

				"""simple docstring"""
				a__				      =		[0] * no_of_processes
				a__				      =		[0] * no_of_processes

				# Initialize remaining_time to waiting_time.

				for i in range(__a		):
								a__				      =		burst_time[i]
				a__				      =		[]

				a__				      =		0
				a__				      =		0

				# When processes are not completed,
				# A process whose arrival time has passed \
				# and has remaining execution time is put into the ready_process.
				# The shortest process in the ready_process, target_process is executed.

				while completed != no_of_processes:
								a__				      =		[]
								a__				      =		-1

								for i in range(__a		):
												if (arrival_time[i] <= total_time) and (remaining_time[i] > 0):
																ready_process.append(__a		)

								if len(__a		) > 0:
												a__				      =		ready_process[0]
												for i in ready_process:
																if remaining_time[i] < remaining_time[target_process]:
																				a__				      =		i
												total_time += burst_time[target_process]
												completed += 1
												a__				      =		0
												a__				      =		(
												    total_time - arrival_time[target_process] - burst_time[target_process]
												)
								else:
												total_time += 1

				return waiting_time

def 			A_      (	__a     :				list[int] ,		__a     :				int ,		__a     :				list[int]		):

				"""simple docstring"""
				a__				      =		[0] * no_of_processes
				for i in range(__a		):
								a__				      =		burst_time[i] + waiting_time[i]
				return turn_around_time


if __name__ == "__main__":
	print("""[TEST CASE 01]""")

	UpperCAmelCase							 =					4
	UpperCAmelCase							 =					[2, 5, 3, 7]
	UpperCAmelCase							 =					[0, 0, 0, 0]
	UpperCAmelCase							 =					calculate_waitingtime(arrival_time, burst_time, no_of_processes)
	UpperCAmelCase							 =					calculate_turnaroundtime(
	    burst_time, no_of_processes, waiting_time
	)

	# Printing the Result
	print("""PID\tBurst Time\tArrival Time\tWaiting Time\tTurnaround Time""")
	for i, process_id in enumerate(list(range(1, 5))):
		print(
		    f"""{process_id}\t{burst_time[i]}\t\t\t{arrival_time[i]}\t\t\t\t"""
		    f"""{waiting_time[i]}\t\t\t\t{turn_around_time[i]}"""
		)
	print(f"""\nAverage waiting time = {mean(waiting_time):.5f}""")
	print(f"""Average turnaround time = {mean(turn_around_time):.5f}""")






def 			A_      (	__a     :				Any		):

				"""simple docstring"""
				if not head:
								return True
				# split the list to two parts
				a__      ,			a__				      =		head.next, head
				while fast and fast.next:
								a__				      =		fast.next.next
								a__				      =		slow.next
				a__				      =		slow.next
				a__				      =		None  # Don't forget here! But forget still works!
				# reverse the second part
				a__				      =		None
				while second:
								a__				      =		second.next
								a__				      =		node
								a__				      =		second
								a__				      =		nxt
				# compare two parts
				# second part has the same or one less node
				while node:
								if node.val != head.val:
												return False
								a__				      =		node.next
								a__				      =		head.next
				return True

def 			A_      (	__a     :				int		):

				"""simple docstring"""
				if not head or not head.next:
								return True

				# 1. Get the midpoint (slow)
				a__				      =		a__				      =		a__				      =		head
				while fast and fast.next:
								a__      ,			a__				      =		fast.next.next, slow.next

				# 2. Push the second half into the stack
				a__				      =		[slow.val]
				while slow.next:
								a__				      =		slow.next
								stack.append(slow.val		)

				# 3. Comparison
				while stack:
								if stack.pop() != cur.val:
												return False
								a__				      =		cur.next

				return True




def 			A_      (	__a     :				Any		):

				"""simple docstring"""
				if not head or not head.next:
								return True
				a__				      =		{}
				a__				      =		0
				while head:
								if head.val in d:
												d[head.val].append(__a		)
								else:
												a__				      =		[pos]
								a__				      =		head.next
								pos += 1
				a__				      =		pos - 1
				a__				      =		0
				for v in d.values():
								if len(__a		) % 2 != 0:
												middle += 1
								else:
												a__				      =		0
												for i in range(0 ,		len(__a		)		):
																if v[i] + v[len(__a		) - 1 - step] != checksum:
																				return False
																step += 1
								if middle > 1:
												return False
				return True

