






SCREAMING_SNAKE_CASE__      :			dict[tuple[int, int, int], int]							=		{}

def      __lowercase					( snake_case,  snake_case,  snake_case ):







				"""simple docstring"""






				if late == 3 or absent == 2:
								return 0

				# if we have no days left, and have not failed any other rules,
				# we have a prize string
				if days == 0:
								return 1

				# No easy solution, so now we need to do the recursive calculation

				# First, check if the combination is already in the cache, and
				# if yes, return the stored value from there since we already
				# know the number of possible prize strings from this point on
				__magic_name__		:List[str]        =      (days, absent, late)
				if key in cache:
								return cache[key]

				# now we calculate the three possible ways that can unfold from
				# this point on, depending on our attendance today

				# 1) if we are late (but not absent), the "absent" counter stays as
				# it is, but the "late" counter increases by one
				__magic_name__		:Union[str, Any]        =      _calculate(days - 1,  snake_case,  late + 1 )

				# 2) if we are absent, the "absent" counter increases by 1, and the
				# "late" counter resets to 0
				__magic_name__		:Optional[int]        =      _calculate(days - 1,  absent + 1,  0 )

				# 3) if we are on time, this resets the "late" counter and keeps the
				# absent counter
				__magic_name__		:Optional[int]        =      _calculate(days - 1,  snake_case,  0 )

				__magic_name__		:Tuple        =      state_late + state_absent + state_ontime

				__magic_name__		:List[Any]        =      prizestrings
				return prizestrings

def      __lowercase					( snake_case = 3_0 ):







				"""simple docstring"""






				return _calculate(snake_case,  absent=0,  late=0 )


if __name__ == "__main__":
					print(solution())














SCREAMING_SNAKE_CASE__      :			str							=		"""Alexander Joslin"""

import operator as op

from .stack import Stack

def      __lowercase					( snake_case ):







				"""simple docstring"""






				__magic_name__		:Optional[int]        =      {'''*''': op.mul, '''/''': op.truediv, '''+''': op.add, '''-''': op.sub}

				__magic_name__		:Stack[int]        =      Stack()
				__magic_name__		:Stack[str]        =      Stack()

				for i in equation:
								if i.isdigit():
												# RULE 1
												operand_stack.push(int(snake_case ) )
								elif i in operators:
												# RULE 2
												operator_stack.push(snake_case )
								elif i == ")":
												# RULE 4
												__magic_name__		:Optional[int]        =      operator_stack.peek()
												operator_stack.pop()
												__magic_name__		:List[str]        =      operand_stack.peek()
												operand_stack.pop()
												__magic_name__		:Optional[Any]        =      operand_stack.peek()
												operand_stack.pop()

												__magic_name__		:Optional[int]        =      operators[opr](snake_case,  snake_case )
												operand_stack.push(snake_case )

    # RULE 5
				return operand_stack.peek()


if __name__ == "__main__":
					SCREAMING_SNAKE_CASE__      :			Any							=		"""(5 + ((4 * 2) * (2 + 3)))"""
					# answer = 45
					print(f"{equation} = {dijkstras_two_stack_algorithm(equation)}")






