


'''simple docstring'''







# coding=utf-8
# Copyright 2023 The HuggingFace Inc. team.
#
# Licensed under the Apache License, Version 2.0 (the "License");
# you may not use this file except in compliance with the License.
# You may obtain a copy of the License at
#
#     http://www.apache.org/licenses/LICENSE-2.0
#
# Unless required by applicable law or agreed to in writing, software
# distributed under the License is distributed on an "AS IS" BASIS,
# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
# See the License for the specific language governing permissions and
# limitations under the License.

# this script dumps information about the environment

import os
import platform
import sys


SCREAMING_SNAKE_CASE_      =			'3'

print('Python version:', sys.version)

print('OS platform:', platform.platform())
print('OS architecture:', platform.machine())

try:
 import torch

 print('Torch version:', torch.__version__)
 print('Cuda available:', torch.cuda.is_available())
 print('Cuda version:', torch.version.cuda)
 print('CuDNN version:', torch.backends.cudnn.version())
 print('Number of GPUs available:', torch.cuda.device_count())
except ImportError:
 print('Torch version:', None)

try:
 import transformers

 print('transformers version:', transformers.__version__)
except ImportError:
 print('transformers version:', None)










'''simple docstring'''







def        __lowercase						(      __SCREAMING_SNAKE_CASE = 100_0000		)				->					int:
     """simple docstring"""




     __a       =   1
     __a       =   1
     __a       =   {1: 1}

     for inputa in range(2				,  __SCREAMING_SNAKE_CASE		):
          __a       =   0
          __a       =   inputa

          while True:
               if number in counters:
                    counter += counters[number]
                    break
               if number % 2 == 0:
                    number //= 2
                    counter += 1
               else:
                    __a       =   (3 * number) + 1
                    counter += 1

          if inputa not in counters:
               __a       =   counter

          if counter > pre_counter:
               __a       =   inputa
               __a       =   counter
     return largest_number


if __name__ == "__main__":
 print(solution(int(input().strip())))






