





from __future__ import annotations




def        lowerCAmelCase_       (							UpperCamelCase_    ,						UpperCamelCase_     )   ->						list[int]:
       assert len(UpperCamelCase_     ) == len(UpperCamelCase_     )

       UpperCamelCase_      				=     len(UpperCamelCase_     )
       UpperCamelCase_      				=     list(range(UpperCamelCase_     )     )
       UpperCamelCase_      				=     [-1] * n  # who the donor has donated to
       UpperCamelCase_      				=     [-1] * n  # who the recipient has received from
       UpperCamelCase_      				=     [0] * n

       while unmatched_donors:
              UpperCamelCase_      				=     unmatched_donors[0]
              UpperCamelCase_      				=     donor_pref[donor]
              UpperCamelCase_      				=     donor_preference[num_donations[donor]]
              num_donations[donor] += 1
              UpperCamelCase_      				=     recipient_pref[recipient]
              UpperCamelCase_      				=     rec_record[recipient]

              if prev_donor != -1:
                     if rec_preference.index(UpperCamelCase_     ) > rec_preference.index(UpperCamelCase_     ):
                            UpperCamelCase_      				=     donor
                            UpperCamelCase_      				=     recipient
                            unmatched_donors.append(UpperCamelCase_     )
                            unmatched_donors.remove(UpperCamelCase_     )
              else:
                     UpperCamelCase_      				=     donor
                     UpperCamelCase_      				=     recipient
                     unmatched_donors.remove(UpperCamelCase_     )
       return donor_record








def        lowerCAmelCase_       (							UpperCamelCase_    ,						UpperCamelCase_     )   ->						list:
       UpperCamelCase_      				=     sorted(UpperCamelCase_    ,						key=lambda UpperCamelCase_     : value[2]    ,						reverse=UpperCamelCase_     )

       # Create a list of size equal to the maximum deadline
       # and initialize it with -1
       UpperCamelCase_      				=     max(UpperCamelCase_    ,						key=lambda UpperCamelCase_     : value[1]     )[1]
       UpperCamelCase_      				=     [-1] * max_deadline

       # Finding the maximum profit and the count of jobs
       UpperCamelCase_      				=     0
       UpperCamelCase_      				=     0
       for job in jobs:
              # Find a free time slot for this job
              # (Note that we start from the last possible slot)
              for i in range(job[1] - 1    ,						-1    ,						-1     ):
                     if time_slots[i] == -1:
                            UpperCamelCase_      				=     job[0]
                            count += 1
                            max_profit += job[2]
                            break
       return [count, max_profit]


if __name__ == "__main__":
     import doctest

     doctest.testmod()

