





'''simple docstring'''






import functools
from typing import Any



def        UpperCamelCase__		(						__magic_name__  :   str		,       __magic_name__  :   list[str]      )				->			bool:
 '''simple docstring'''






 if not isinstance(__magic_name__		,       __magic_name__      ) or len(__magic_name__      ) == 0:
  raise ValueError("""the string should be not empty string"""      )

 if not isinstance(__magic_name__		,       __magic_name__      ) or not all(
     isinstance(__magic_name__		,       __magic_name__      ) and len(__magic_name__      ) > 0 for item in words      ):
  raise ValueError("""the words should be a list of non-empty strings"""      )

 # Build trie
 snake_case__     :					dict[str, Any]    =  {}
 snake_case__     :					Optional[Any]    =  """WORD_KEEPER"""

 for word in words:
  snake_case__     :					Any    =  trie
  for c in word:
   if c not in trie_node:
    snake_case__     :					Dict    =  {}

   snake_case__     :					Union[str, Any]    =  trie_node[c]

  snake_case__     :					Union[str, Any]    =  True

 snake_case__     :					List[Any]    =  len(__magic_name__      )

 # Dynamic programming method
 @functools.cache
 def is_breakable(__magic_name__  :   int      ) -> bool:
  if index == len_string:
   return True

  snake_case__     :					Optional[Any]    =  trie
  for i in range(__magic_name__		,       __magic_name__      ):
   snake_case__     :					Tuple    =  trie_node.get(string[i]		,       __magic_name__      )

   if trie_node is None:
    return False

   if trie_node.get(__magic_name__		,       __magic_name__      ) and is_breakable(i + 1      ):
    return True

  return False

 return is_breakable(0      )


if __name__ == "__main__":
    import doctest

    doctest.testmod()






from __future__ import annotations







def 							A__       (    lowerCamelCase    )	->						int:
				UpperCamelCase_:				Optional[Any]						=    len(lowerCamelCase    ) // 2

				# choose the middle 3 elements
				UpperCamelCase_:				Tuple						=    lst[m - 1 : m + 2]

				# if middle element is peak
				if three[1] > three[0] and three[1] > three[2]:
								return three[1]

				# if increasing, recurse on right
				elif three[0] < three[2]:
								if len(lst[:m]    ) == 2:
												m -= 1
								return peak(lst[m:]    )

				# decreasing
				else:
								if len(lst[:m]    ) == 2:
												m += 1
								return peak(lst[:m]    )


if __name__ == "__main__":
							import doctest

							doctest.testmod()






