

class 					__lowercase  :





							"""simple docstring"""

							def __init__(					self    ,						__UpperCAmelCase = ""    ,						__UpperCAmelCase = False						)		->       None:
														# Mapping from the first character of the prefix of the node
														A      :					dict[str, RadixNode]      		=					{}

														# A node will be a leaf if the tree contains its word
														A      :					List[str]      		=					is_leaf

														A      :					Any      		=					prefix




							def       snake_case			(					self    ,						__UpperCAmelCase						)		->       tuple[str, str, str]:
														A      :					Dict      		=					0
														for q, w in zip(self.prefix    ,						__UpperCAmelCase						):
																					if q != w:
																												break

																					x += 1

														return self.prefix[:x], self.prefix[x:], word[x:]




							def       snake_case			(					self    ,						__UpperCAmelCase						)		->       None:
														for word in words:
																					self.insert(__UpperCAmelCase						)




							def       snake_case			(					self    ,						__UpperCAmelCase						)		->       None:
														# Case 1: If the word is the prefix of the node
														# Solution: We set the current node as leaf
														if self.prefix == word:
																					A      :					Optional[Any]      		=					True

														# Case 2: The node has no edges that have a prefix to the word
														# Solution: We create an edge from the current node to a new one
														# containing the word
														elif word[0] not in self.nodes:
																					A      :					Union[str, Any]      		=					RadixNode(prefix=__UpperCAmelCase    ,						is_leaf=__UpperCAmelCase						)

														else:
																					A      :					List[Any]      		=					self.nodes[word[0]]
																					A		,		A		,		A      :					Tuple      		=					incoming_node.match(
																					    __UpperCAmelCase						)

																					# Case 3: The node prefix is equal to the matching
																					# Solution: We insert remaining word on the next node
																					if remaining_prefix == "":
																												self.nodes[matching_string[0]].insert(__UpperCAmelCase						)

																					# Case 4: The word is greater equal to the matching
																					# Solution: Create a node in between both nodes, change
																					# prefixes and add the new node for the remaining word
																					else:
																												A      :					Any      		=					remaining_prefix

																												A      :					Union[str, Any]      		=					self.nodes[matching_string[0]]
																												A      :					Union[str, Any]      		=					RadixNode(__UpperCAmelCase    ,						__UpperCAmelCase						)
																												A      :					List[str]      		=					aux_node

																												if remaining_word == "":
																																			A      :					Dict      		=					True
																												else:
																																			self.nodes[matching_string[0]].insert(__UpperCAmelCase						)




							def       snake_case			(					self    ,						__UpperCAmelCase						)		->       bool:
														A      :					Optional[Any]      		=					self.nodes.get(word[0]    ,						__UpperCAmelCase						)
														if not incoming_node:
																					return False
														else:
																					A		,		A		,		A      :					Optional[int]      		=					incoming_node.match(
																					    __UpperCAmelCase						)
																					# If there is remaining prefix, the word can't be on the tree
																					if remaining_prefix != "":
																												return False
																					# This applies when the word and the prefix are equal
																					elif remaining_word == "":
																												return incoming_node.is_leaf
																					# We have word remaining so we check the next node
																					else:
																												return incoming_node.find(__UpperCAmelCase						)




							def       snake_case			(					self    ,						__UpperCAmelCase						)		->       bool:
														A      :					Dict      		=					self.nodes.get(word[0]    ,						__UpperCAmelCase						)
														if not incoming_node:
																					return False
														else:
																					A		,		A		,		A      :					List[Any]      		=					incoming_node.match(
																					    __UpperCAmelCase						)
																					# If there is remaining prefix, the word can't be on the tree
																					if remaining_prefix != "":
																												return False
																					# We have word remaining so we check the next node
																					elif remaining_word != "":
																												return incoming_node.delete(__UpperCAmelCase						)
																					else:
																												# If it is not a leaf, we don't have to delete
																												if not incoming_node.is_leaf:
																																			return False
																												else:
																																			# We delete the nodes if no edges go from it
																																			if len(incoming_node.nodes						) == 0:
																																										del self.nodes[word[0]]
																																										# We merge the current node with its only child
																																										if len(self.nodes						) == 1 and not self.is_leaf:
																																																	A      :					Tuple      		=					list(self.nodes.values()						)[0]
																																																	A      :					int      		=					merging_node.is_leaf
																																																	self.prefix += merging_node.prefix
																																																	A      :					Tuple      		=					merging_node.nodes
                    # If there is more than 1 edge, we just mark it as non-leaf
																																			elif len(incoming_node.nodes						) > 1:
																																										A      :					List[Any]      		=					False
																																			# If there is 1 edge, we merge it with its child
																																			else:
																																										A      :					Dict      		=					list(incoming_node.nodes.values()						)[0]
																																										A      :					Optional[int]      		=					merging_node.is_leaf
																																										incoming_node.prefix += merging_node.prefix
																																										A      :					int      		=					merging_node.nodes

																																			return True






							def       snake_case			(					self    ,						__UpperCAmelCase = 0						)		->       None:
														if self.prefix != "":
																					print('''-''' * height    ,						self.prefix    ,						'''  (leaf)''' if self.is_leaf else ''''''						)

														for value in self.nodes.values():
																					value.print_tree(height + 1						)






def        snake_case__		(    ):
							A      :					Optional[Any]      		=					'''banana bananas bandana band apple all beast'''.split()
							A      :					Union[str, Any]      		=					RadixNode()
							root.insert_many(lowerCamelCase_		)

							assert all(root.find(lowerCamelCase_		) for word in words		)
							assert not root.find('''bandanas'''		)
							assert not root.find('''apps'''		)
							root.delete('''all'''		)
							assert not root.find('''all'''		)
							root.delete('''banana'''		)
							assert not root.find('''banana'''		)
							assert root.find('''bananas'''		)

							return True






def        snake_case__		(    ):
							assert test_trie()






def        snake_case__		(    ):
							A      :					Dict      		=					RadixNode()
							A      :					Optional[int]      		=					'''banana bananas bandanas bandana band apple all beast'''.split()
							root.insert_many(lowerCamelCase_		)

							print('''Words:'''     ,				lowerCamelCase_		)
							print('''Tree:'''		)
							root.print_tree()


if __name__ == "__main__":
		main()









import string
from math import logaa






def        snake_case__		(    lowerCamelCase_     ,				lowerCamelCase_		):
							A      :					List[str]      		=					document.translate(
							    str.maketrans(''''''     ,				''''''     ,				string.punctuation		)		).replace('''\n'''     ,				''''''		)
							A      :					Optional[int]      		=					document_without_punctuation.split(''' '''		)  # word tokenization
							return len([word for word in tokenize_document if word.lower() == term.lower()]		)






def        snake_case__		(    lowerCamelCase_     ,				lowerCamelCase_		):
							A      :					Dict      		=					corpus.lower().translate(
							    str.maketrans(''''''     ,				''''''     ,				string.punctuation		)		)  # strip all punctuation and replace it with ''
							A      :					Dict      		=					corpus_without_punctuation.split('''\n'''		)
							A      :					List[Any]      		=					term.lower()
							return (len([doc for doc in docs if term in doc]		), len(lowerCamelCase_		))






def        snake_case__		(    lowerCamelCase_     ,				lowerCamelCase_     ,				lowerCamelCase_=False		):
							if smoothing:
														if n == 0:
																					raise ValueError('''log10(0) is undefined.'''		)
														return round(1 + logaa(n / (1 + df)		)     ,				3		)

							if df == 0:
														raise ZeroDivisionError('''df must be > 0'''		)
							elif n == 0:
														raise ValueError('''log10(0) is undefined.'''		)
							return round(logaa(n / df		)     ,				3		)






def        snake_case__		(    lowerCamelCase_     ,				lowerCamelCase_		):
							return round(tf * idf     ,				3		)






