6.00.2x-pset1.py
def greedy_cow_transport(cows, limit=10):
    """
    Uses a greedy heuristic to determine an allocation of cows that attempts to
    minimize the number of spaceship trips needed to transport all the cows.
    The returned allocation of cows may or may not be optimal.
    The greedy heuristic follows the following method:

    1. As long as the current trip can fit another cow, add the largest cow
    that will fit to the trip.
    2. Once the trip is full, begin a new trip to transport the remaining cows.

    Does not mutate the given dictionary of cows.

    Parameters:
    cows - a dictionary of name (string), weight (int) pairs
    limit - weight limit of the spaceship (an int)

    Returns:
    A list of lists, with each inner list containing the names of cows
    transported on a particular trip and the overall list containing all the
    trips
    """
    cowsLeft = dict(cows)
    result = []
    while cowsLeft != {}:
        trip = []
        totalWeight = 0
        for i in sorted(cowsLeft, key=cowsLeft.get)[::-1]:
            if (totalWeight + cowsLeft[i]) <= limit:
                trip.append(i)
                totalWeight += cowsLeft[i]
                del cowsLeft[i]
        result.append(trip)
    return result

    Uses a greedy heuristic to determine an allocation of cows that attempts to
    minimize the number of spaceship trips needed to transport all the cows.
    The returned allocation of cows may or may not be optimal.
    The greedy heuristic follows the following method:

    1. As long as the current trip can fit another cow, add the largest cow
    that will fit to the trip.
    2. Once the trip is full, begin a new trip to transport the remaining cows.

    Does not mutate the given dictionary of cows.

    Parameters:
    cows - a dictionary of name (string), weight (int) pairs
    limit - weight limit of the spaceship (an int)

    Returns:
    A list of lists, with each inner list containing the names of cows
    transported on a particular trip and the overall list containing all the
    trips
    
Uses a greedy heuristic to determine an allocation of cows that attempts to
minimize the number of spaceship trips needed to transport all the cows.
The returned allocation of cows may or may not be optimal.
The greedy heuristic follows the following method.

1. As long as the current trip can fit another cow, add the largest cow
that will fit to the trip.
2. Once the trip is full, begin a new trip to transport the remaining cows.

Does not mutate the given dictionary of cows.

a dictionary of name (string), weight (int) pairs
limit - weight limit of the spaceship (an int)

A list of lists, with each inner list containing the names of cows
transported on a particular trip and the overall list containing all the
trips
Uses a greedy heuristic to determine an allocation of cows that attempts to minimize the number of spaceship trips needed to transport all the cows . The returned allocation of cows may or may not be optimal . The greedy heuristic follows the following method . 1 . As long as the current trip can fit another cow add the largest cow that will fit to the trip . 2 . Once the trip is full begin a new trip to transport the remaining cows . Does not mutate the given dictionary of cows . a dictionary of name ( string ) weight ( int ) pairs limit - weight limit of the spaceship ( an int ) A list of lists with each inner list containing the names of cows transported on a particular trip and the overall list containing all the trips
def greedy_cow_transport(cows, limit=10):
    cowsLeft = dict(cows)
    result = []
    while cowsLeft != {}:
        trip = []
        totalWeight = 0
        for i in sorted(cowsLeft, key=cowsLeft.get)[::-1]:
            if (totalWeight + cowsLeft[i]) <= limit:
                trip.append(i)
                totalWeight += cowsLeft[i]
                del cowsLeft[i]
        result.append(trip)
    return result
def greedy_cow_transport ( cows , limit = 10 ) : cowsLeft = dict ( cows ) result = [ ] while cowsLeft != { } : trip = [ ] totalWeight = 0 for i in sorted ( cowsLeft , key = cowsLeft . get ) [ : : - 1 ] : if ( totalWeight + cowsLeft [ i ] ) <= limit : trip . append ( i ) totalWeight += cowsLeft [ i ] del cowsLeft [ i ] result . append ( trip ) return result
Uses a greedy heuristic to determine an allocation of cows that attempts to
minimize the number of spaceship trips needed to transport all the cows.
Uses a greedy heuristic to determine an allocation of cows that attempts to minimize the number of spaceship trips needed to transport all the cows .
"""
    Uses a greedy heuristic to determine an allocation of cows that attempts to
    minimize the number of spaceship trips needed to transport all the cows.
    The returned allocation of cows may or may not be optimal.
    The greedy heuristic follows the following method:

    1. As long as the current trip can fit another cow, add the largest cow
    that will fit to the trip.
    2. Once the trip is full, begin a new trip to transport the remaining cows.

    Does not mutate the given dictionary of cows.

    Parameters:
    cows - a dictionary of name (string), weight (int) pairs
    limit - weight limit of the spaceship (an int)

    Returns:
    A list of lists, with each inner list containing the names of cows
    transported on a particular trip and the overall list containing all the
    trips
    """
cows
limit