love.py
def theLoveLetter(s):
    """
    This function returns the integer representing the minimum number
    of operations needed to make the string a palindrome.
    """

    alphabets = 'abcdefghijklmnopqrstuvwxyz'

    l = len(s) # length of input string

    # Sub divide the input string into two equal parts
    str1 = s[:l//2]

    # handle odd input string length
    str2 = s[l//2 if l % 2 == 0 else l//2 + 1:]

    # handle first edge case
    # if input string is already a palindrome return
    if s == s[::-1]: 
        return 0
    
    # initialize variables to hold totals of 
    # string manipulations
    part1 = 0
    part2 = 0

    # traverse through first part of the string 
    # from the string's beginning
    # while comparing current char with char from
    # second part of the string from the end

    

    for i in range(1,len(str1)+1):
        if str1[i-1] != str2[len(str2)-i]:
            # check the positions of the chars in alphabets
            if alphabets.find(str1[i-1]) < alphabets.find(str2[len(str2)-i]):
                part1 += (alphabets.find(str2[len(str2)-i]) - alphabets.find(str1[i-1]) )
            else:
                part2 += (alphabets.find(str1[i-1]) - alphabets.find(str2[len(str2)-i]))
    return part1+part2

    This function returns the integer representing the minimum number
    of operations needed to make the string a palindrome.
    
This function returns the integer representing the minimum number
of operations needed to make the string a palindrome.
This function returns the integer representing the minimum number of operations needed to make the string a palindrome .
def theLoveLetter(s):
    alphabets = 'abcdefghijklmnopqrstuvwxyz'
    l = len(s) 
    str1 = s[:l//2]
    str2 = s[l//2 if l % 2 == 0 else l//2 + 1:]
    if s == s[::-1]: 
        return 0
    part1 = 0
    part2 = 0
    for i in range(1,len(str1)+1):
        if str1[i-1] != str2[len(str2)-i]:
            if alphabets.find(str1[i-1]) < alphabets.find(str2[len(str2)-i]):
                part1 += (alphabets.find(str2[len(str2)-i]) - alphabets.find(str1[i-1]) )
            else:
                part2 += (alphabets.find(str1[i-1]) - alphabets.find(str2[len(str2)-i]))
    return part1+part2
def theLoveLetter ( s ) : alphabets = 'abcdefghijklmnopqrstuvwxyz' l = len ( s ) str1 = s [ : l // 2 ] str2 = s [ l // 2 if l % 2 == 0 else l // 2 + 1 : ] if s == s [ : : - 1 ] : return 0 part1 = 0 part2 = 0 for i in range ( 1 , len ( str1 ) + 1 ) : if str1 [ i - 1 ] != str2 [ len ( str2 ) - i ] : if alphabets . find ( str1 [ i - 1 ] ) < alphabets . find ( str2 [ len ( str2 ) - i ] ) : part1 += ( alphabets . find ( str2 [ len ( str2 ) - i ] ) - alphabets . find ( str1 [ i - 1 ] ) ) else : part2 += ( alphabets . find ( str1 [ i - 1 ] ) - alphabets . find ( str2 [ len ( str2 ) - i ] ) ) return part1 + part2
This function returns the integer representing the minimum number
of operations needed to make the string a palindrome.
This function returns the integer representing the minimum number of operations needed to make the string a palindrome .
"""
    This function returns the integer representing the minimum number
    of operations needed to make the string a palindrome.
    """ # length of input string # Sub divide the input string into two equal parts # handle odd input string length # handle first edge case # if input string is already a palindrome return # initialize variables to hold totals of  # string manipulations # traverse through first part of the string  # from the string's beginning # while comparing current char with char from # second part of the string from the end # check the positions of the chars in alphabets
s