In $\triangle ABC$ we have $AB=7$, $AC=8$, and $BC=9$. Point $D$ is on the circumscribed circle of the triangle so that $\overline{AD}$ bisects $\angle BAC$. What is the value of $AD/CD$?
<|im_start|>system
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<|im_start|>user
In $\triangle ABC$ we have $AB=7$, $AC=8$, and $BC=9$. Point $D$ is on the circumscribed circle of the triangle so that $\overline{AD}$ bisects $\angle BAC$. What is the value of $AD/CD$?
Please reason step by step, and put your final answer within \boxed{{}}.<|im_end|>
<|im_start|>assistant

user
\frac{5}{3}
In $\triangle ABC$ we have $AB=7$, $AC=8$, and $BC=9$. Point $D$ is on the circumscribed circle of the triangle so that $\overline{AD}$ bisects $\angle BAC$. What is the value of $AD/CD$?
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