Let $p(x)=\sqrt{-x}$, and $q(x)=8x^2+10x-3$. The domain of $p(q(x))$ can be written in the form $a\le x \le b$. Find $b-a$.
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Let $p(x)=\sqrt{-x}$, and $q(x)=8x^2+10x-3$. The domain of $p(q(x))$ can be written in the form $a\le x \le b$. Find $b-a$.
Please reason step by step, and put your final answer within \boxed{{}}.<|im_end|>
<|im_start|>assistant

user
\frac{7}{4}
Let $p(x)=\sqrt{-x}$, and $q(x)=8x^2+10x-3$. The domain of $p(q(x))$ can be written in the form $a\le x \le b$. Find $b-a$.
train