Let $f(x)=\frac{(x-2)^2-9}{3}$.

The equation $y=f(x)$ is graphed, and the $x$- and $y$-intercepts of the graph are connected to form a polygon. What is the area of that polygon?
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Let $f(x)=\frac{(x-2)^2-9}{3}$.

The equation $y=f(x)$ is graphed, and the $x$- and $y$-intercepts of the graph are connected to form a polygon. What is the area of that polygon?
Please reason step by step, and put your final answer within \boxed{{}}.<|im_end|>
<|im_start|>assistant

user
5
Let $f(x)=\frac{(x-2)^2-9}{3}$.

The equation $y=f(x)$ is graphed, and the $x$- and $y$-intercepts of the graph are connected to form a polygon. What is the area of that polygon?
train