Two cones have the same volume. If one has a base with radius 3 times as large as the other's and a height of 24 inches, how many inches tall is the other?

Note: The volume of a cone is $\frac{1}{3} \pi r^2 h,$ where $r$ is the radius and $h$ is the height.
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Two cones have the same volume. If one has a base with radius 3 times as large as the other's and a height of 24 inches, how many inches tall is the other?

Note: The volume of a cone is $\frac{1}{3} \pi r^2 h,$ where $r$ is the radius and $h$ is the height.
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Two cones have the same volume. If one has a base with radius 3 times as large as the other's and a height of 24 inches, how many inches tall is the other?

Note: The volume of a cone is $\frac{1}{3} \pi r^2 h,$ where $r$ is the radius and $h$ is the height.
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