Solve for $x$: $$\dfrac{66-2^x}{2^x+3}=\dfrac{4-2^x}{2^{x+1}+6}$$
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Solve for $x$: $$\dfrac{66-2^x}{2^x+3}=\dfrac{4-2^x}{2^{x+1}+6}$$
Please reason step by step, and put your final answer within \boxed{{}}.<|im_end|>
<|im_start|>assistant

user
7
Solve for $x$: $$\dfrac{66-2^x}{2^x+3}=\dfrac{4-2^x}{2^{x+1}+6}$$
train