Find the number of ordered triples $(x,y,z)$ of positive real numbers such that
\[\left( x + \frac{1}{y} \right) \left( y + \frac{1}{z} \right) \left( z + \frac{1}{x} \right) = 8.\]
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Find the number of ordered triples $(x,y,z)$ of positive real numbers such that
\[\left( x + \frac{1}{y} \right) \left( y + \frac{1}{z} \right) \left( z + \frac{1}{x} \right) = 8.\]
Please reason step by step, and put your final answer within \boxed{{}}.<|im_end|>
<|im_start|>assistant

user
1
Find the number of ordered triples $(x,y,z)$ of positive real numbers such that
\[\left( x + \frac{1}{y} \right) \left( y + \frac{1}{z} \right) \left( z + \frac{1}{x} \right) = 8.\]
train