If
\[\cos 41^\circ + \sin 41^\circ = \sqrt{2} \sin A,\]where $0^\circ < A < 90^\circ,$ compute the degree measure of $A.$
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<|im_start|>user
If
\[\cos 41^\circ + \sin 41^\circ = \sqrt{2} \sin A,\]where $0^\circ < A < 90^\circ,$ compute the degree measure of $A.$
Please reason step by step, and put your final answer within \boxed{{}}.<|im_end|>
<|im_start|>assistant

user
86^\circ
If
\[\cos 41^\circ + \sin 41^\circ = \sqrt{2} \sin A,\]where $0^\circ < A < 90^\circ,$ compute the degree measure of $A.$
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