The parabolas defined by the equations $y=x^2+4x+6$ and $y=\frac{1}{2}x^2+x+6$ intersect at points $(a,b)$ and $(c,d)$, where $c\ge a$. What is $c-a$?
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
The parabolas defined by the equations $y=x^2+4x+6$ and $y=\frac{1}{2}x^2+x+6$ intersect at points $(a,b)$ and $(c,d)$, where $c\ge a$. What is $c-a$?
Please reason step by step, and put your final answer within \boxed{{}}.<|im_end|>
<|im_start|>assistant

user
6
The parabolas defined by the equations $y=x^2+4x+6$ and $y=\frac{1}{2}x^2+x+6$ intersect at points $(a,b)$ and $(c,d)$, where $c\ge a$. What is $c-a$?
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