The least common multiple of two positive integers is $7!$, and their greatest common divisor is $9$. If one of the integers is $315$, then what is the other?

(Note that $7!$ means $7\cdot6\cdot5\cdot4\cdot3\cdot2\cdot 1$.)
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
The least common multiple of two positive integers is $7!$, and their greatest common divisor is $9$. If one of the integers is $315$, then what is the other?

(Note that $7!$ means $7\cdot6\cdot5\cdot4\cdot3\cdot2\cdot 1$.)
Please reason step by step, and put your final answer within \boxed{{}}.<|im_end|>
<|im_start|>assistant

user
144
The least common multiple of two positive integers is $7!$, and their greatest common divisor is $9$. If one of the integers is $315$, then what is the other?

(Note that $7!$ means $7\cdot6\cdot5\cdot4\cdot3\cdot2\cdot 1$.)
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