Find constants $A,$ $B,$ $C,$ and $D$ so that
\[\frac{x^3 + 3x^2 - 12x + 36}{x^4 - 16} = \frac{A}{x - 2} + \frac{B}{x + 2} + \frac{Cx + D}{x^2 + 4}.\]Enter the ordered quadruple $(A,B,C,D).$
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Find constants $A,$ $B,$ $C,$ and $D$ so that
\[\frac{x^3 + 3x^2 - 12x + 36}{x^4 - 16} = \frac{A}{x - 2} + \frac{B}{x + 2} + \frac{Cx + D}{x^2 + 4}.\]Enter the ordered quadruple $(A,B,C,D).$
Please reason step by step, and put your final answer within \boxed{{}}.<|im_end|>
<|im_start|>assistant

user
(1,-2,2,-3)
Find constants $A,$ $B,$ $C,$ and $D$ so that
\[\frac{x^3 + 3x^2 - 12x + 36}{x^4 - 16} = \frac{A}{x - 2} + \frac{B}{x + 2} + \frac{Cx + D}{x^2 + 4}.\]Enter the ordered quadruple $(A,B,C,D).$
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