In right triangle $FGH$ with $\angle H = 90^\circ$, we have $FG = 17$ and $HG = 15$.  Find $\sin G$.
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In right triangle $FGH$ with $\angle H = 90^\circ$, we have $FG = 17$ and $HG = 15$.  Find $\sin G$.
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user
\frac{8}{17}
In right triangle $FGH$ with $\angle H = 90^\circ$, we have $FG = 17$ and $HG = 15$.  Find $\sin G$.
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