By partial fractions,
$$\frac{7x-2}{x^2-4} = \frac{A}{x-2} + \frac{B}{x+2}.$$Find $A+B$.
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By partial fractions,
$$\frac{7x-2}{x^2-4} = \frac{A}{x-2} + \frac{B}{x+2}.$$Find $A+B$.
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7
By partial fractions,
$$\frac{7x-2}{x^2-4} = \frac{A}{x-2} + \frac{B}{x+2}.$$Find $A+B$.
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