Find the center of the circle with equation $x^2 + 14x + y^2 - 6y + 53 = 0$.
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Find the center of the circle with equation $x^2 + 14x + y^2 - 6y + 53 = 0$.
Please reason step by step, and put your final answer within \boxed{{}}.<|im_end|>
<|im_start|>assistant

user
(-7, 3)
Find the center of the circle with equation $x^2 + 14x + y^2 - 6y + 53 = 0$.
train