In the diagram, the two triangles shown have parallel bases. What is the ratio of the area of the smaller triangle to the area of the larger triangle? Express your answer as a common fraction. [asy] path p = (0,0)--dir(-60)--dir(-120)--(0,0);
draw(p); draw(scale(3)*p);
label("4 cm",dir(-60)--dir(-120),S); label("10 cm",3*dir(-60)--3dir(-120),S);
[/asy]
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
In the diagram, the two triangles shown have parallel bases. What is the ratio of the area of the smaller triangle to the area of the larger triangle? Express your answer as a common fraction. [asy] path p = (0,0)--dir(-60)--dir(-120)--(0,0);
draw(p); draw(scale(3)*p);
label("4 cm",dir(-60)--dir(-120),S); label("10 cm",3*dir(-60)--3dir(-120),S);
[/asy]
Please reason step by step, and put your final answer within \boxed{{}}.<|im_end|>
<|im_start|>assistant

user
\dfrac{4}{25}
In the diagram, the two triangles shown have parallel bases. What is the ratio of the area of the smaller triangle to the area of the larger triangle? Express your answer as a common fraction. [asy] path p = (0,0)--dir(-60)--dir(-120)--(0,0);
draw(p); draw(scale(3)*p);
label("4 cm",dir(-60)--dir(-120),S); label("10 cm",3*dir(-60)--3dir(-120),S);
[/asy]
train