In triangle $ABC$, $\tan \angle CAB = \frac{22}{7}$, and the altitude from $A$ divides $\overline{BC}$ into segments of length $3$ and $17$. What is the area of triangle $ABC$?
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<|im_start|>user
In triangle $ABC$, $\tan \angle CAB = \frac{22}{7}$, and the altitude from $A$ divides $\overline{BC}$ into segments of length $3$ and $17$. What is the area of triangle $ABC$?
Please reason step by step, and put your final answer within \boxed{{}}.<|im_end|>
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user
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In triangle $ABC$, $\tan \angle CAB = \frac{22}{7}$, and the altitude from $A$ divides $\overline{BC}$ into segments of length $3$ and $17$. What is the area of triangle $ABC$?
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