The length of a rectangle is $3x+10$ feet and its width is $x+12$ feet.  If the perimeter of the rectangle is 76 feet, how many square feet are in the area of the rectangle?
Question:
The length of a rectangle is $3x+10$ feet and its width is $x+12$ feet.  If the perimeter of the rectangle is 76 feet, how many square feet are in the area of the rectangle?
Answer:
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The length of a rectangle is $3x+10$ feet and its width is $x+12$ feet.  If the perimeter of the rectangle is 76 feet, how many square feet are in the area of the rectangle?
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