Let $a$ and $b$ be real numbers. The function $h(x)=ax+b$ satisfies $h(1)=5$ and $h(-1)=1$.  What is $h(6)$?
Question:
Let $a$ and $b$ be real numbers. The function $h(x)=ax+b$ satisfies $h(1)=5$ and $h(-1)=1$.  What is $h(6)$?
Answer:
Let's think step by step.

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Let $a$ and $b$ be real numbers. The function $h(x)=ax+b$ satisfies $h(1)=5$ and $h(-1)=1$.  What is $h(6)$?
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