Find the sum of all positive real solutions  $x$ to the equation \[2\cos2x \left(\cos2x - \cos{\left( \frac{2014\pi^2}{x} \right) } \right) = \cos4x - 1,\]where $x$ is measured in radians.
Question:
Find the sum of all positive real solutions  $x$ to the equation \[2\cos2x \left(\cos2x - \cos{\left( \frac{2014\pi^2}{x} \right) } \right) = \cos4x - 1,\]where $x$ is measured in radians.
Answer:
Let's think step by step.

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Find the sum of all positive real solutions  $x$ to the equation \[2\cos2x \left(\cos2x - \cos{\left( \frac{2014\pi^2}{x} \right) } \right) = \cos4x - 1,\]where $x$ is measured in radians.
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