In triangle $ABC,$ $\sin A = \frac{3}{5}$ and $\sin B = \frac{24}{25}.$  Enter all the possible values of $\sin C,$ separated by commas.
Question:
In triangle $ABC,$ $\sin A = \frac{3}{5}$ and $\sin B = \frac{24}{25}.$  Enter all the possible values of $\sin C,$ separated by commas.
Answer:
Let's think step by step.

user
\frac{3}{5}, \frac{117}{125}
In triangle $ABC,$ $\sin A = \frac{3}{5}$ and $\sin B = \frac{24}{25}.$  Enter all the possible values of $\sin C,$ separated by commas.
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