If $\frac{60}{2^3\cdot5^8}$ is expressed as a decimal, how many non-zero digits are to the right of the decimal point?
Question:
If $\frac{60}{2^3\cdot5^8}$ is expressed as a decimal, how many non-zero digits are to the right of the decimal point?
Answer:
Let's think step by step.

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If $\frac{60}{2^3\cdot5^8}$ is expressed as a decimal, how many non-zero digits are to the right of the decimal point?
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