In right triangle $ABC$ with $\angle A = 90^\circ$, we have $AB = 6$ and $BC = 10$.  Find $\cos A$.
Question:
In right triangle $ABC$ with $\angle A = 90^\circ$, we have $AB = 6$ and $BC = 10$.  Find $\cos A$.
Answer:
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In right triangle $ABC$ with $\angle A = 90^\circ$, we have $AB = 6$ and $BC = 10$.  Find $\cos A$.
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