In the $n$th row of Pascal's Triangle where the first row is $n=0$, the arithmetic mean of the elements is $51.2$. What is the value of $n$?
Question:
In the $n$th row of Pascal's Triangle where the first row is $n=0$, the arithmetic mean of the elements is $51.2$. What is the value of $n$?
Answer:
Let's think step by step.

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In the $n$th row of Pascal's Triangle where the first row is $n=0$, the arithmetic mean of the elements is $51.2$. What is the value of $n$?
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