The side lengths of a right triangle measure $x$, $x + y$ and $x - y$ units where $0 < y < x$. What is the value of $y \div x$? Express your answer as a common fraction.
Question:
The side lengths of a right triangle measure $x$, $x + y$ and $x - y$ units where $0 < y < x$. What is the value of $y \div x$? Express your answer as a common fraction.
Answer:
Let's think step by step.

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\frac{1}{4}
The side lengths of a right triangle measure $x$, $x + y$ and $x - y$ units where $0 < y < x$. What is the value of $y \div x$? Express your answer as a common fraction.
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