If $y= \frac{x^2+2x+8}{x-4}$, at what value of $x$ will there be a vertical asymptote?
Question:
If $y= \frac{x^2+2x+8}{x-4}$, at what value of $x$ will there be a vertical asymptote?
Answer:
Let's think step by step.

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If $y= \frac{x^2+2x+8}{x-4}$, at what value of $x$ will there be a vertical asymptote?
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