Suppose $\sqrt{1 + \sqrt{2y-3}} = \sqrt{6}$; find $y$.
Question:
Suppose $\sqrt{1 + \sqrt{2y-3}} = \sqrt{6}$; find $y$.
Answer:
Let's think step by step.

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Suppose $\sqrt{1 + \sqrt{2y-3}} = \sqrt{6}$; find $y$.
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