The parabolas $y = (x + 1)^2$ and $x + 4 = (y - 3)^2$ intersect at four points.  All four points lie on a circle of radius $r.$  Find $r^2.$
Question:
The parabolas $y = (x + 1)^2$ and $x + 4 = (y - 3)^2$ intersect at four points.  All four points lie on a circle of radius $r.$  Find $r^2.$
Answer:
Let's think step by step.

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\frac{13}{2}
The parabolas $y = (x + 1)^2$ and $x + 4 = (y - 3)^2$ intersect at four points.  All four points lie on a circle of radius $r.$  Find $r^2.$
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