If $10^{51} - 9$ is written as an integer in standard form, what is the sum of the integer's digits?
Question:
If $10^{51} - 9$ is written as an integer in standard form, what is the sum of the integer's digits?
Answer:
Let's think step by step.

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If $10^{51} - 9$ is written as an integer in standard form, what is the sum of the integer's digits?
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