What is the area, in square units, of the triangle bounded by $y = 0$, $y = x + 4$ and $x + 3y = 12$?
Question:
What is the area, in square units, of the triangle bounded by $y = 0$, $y = x + 4$ and $x + 3y = 12$?
Answer:
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What is the area, in square units, of the triangle bounded by $y = 0$, $y = x + 4$ and $x + 3y = 12$?
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