If $0 < \theta < \frac{\pi}{2}$ and $\sqrt{3} \cos \theta - \sin \theta = \frac{1}{3},$ then find $\sqrt{3} \sin \theta + \cos \theta.$
Question:
If $0 < \theta < \frac{\pi}{2}$ and $\sqrt{3} \cos \theta - \sin \theta = \frac{1}{3},$ then find $\sqrt{3} \sin \theta + \cos \theta.$
Answer:
Let's think step by step.

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\frac{\sqrt{35}}{3}
If $0 < \theta < \frac{\pi}{2}$ and $\sqrt{3} \cos \theta - \sin \theta = \frac{1}{3},$ then find $\sqrt{3} \sin \theta + \cos \theta.$
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