Compute
\[\sum_{k = 2}^\infty \frac{k - 3}{k(k^2 - 1)}.\]
Question:
Compute
\[\sum_{k = 2}^\infty \frac{k - 3}{k(k^2 - 1)}.\]
Answer:
Let's think step by step.

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Compute
\[\sum_{k = 2}^\infty \frac{k - 3}{k(k^2 - 1)}.\]
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