Let $x^2+bx+c = 0$ be a quadratic whose roots are each two more than the roots of $3x^2-5x-7$. What is $c$?
Question:
Let $x^2+bx+c = 0$ be a quadratic whose roots are each two more than the roots of $3x^2-5x-7$. What is $c$?
Answer:
Let's think step by step.

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Let $x^2+bx+c = 0$ be a quadratic whose roots are each two more than the roots of $3x^2-5x-7$. What is $c$?
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