In $\triangle XYZ$, we have $\angle X = 90^\circ$ and $\tan Z = 3$.  What is $\cos Z$?
Question:
In $\triangle XYZ$, we have $\angle X = 90^\circ$ and $\tan Z = 3$.  What is $\cos Z$?
Answer:
Let's think step by step.

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\frac{\sqrt{10}}{10}
In $\triangle XYZ$, we have $\angle X = 90^\circ$ and $\tan Z = 3$.  What is $\cos Z$?
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