Given that $a$ is a multiple of $1428$, find the greatest common divisor of $a^2+9a+24$ and $a+4$.
Question:
Given that $a$ is a multiple of $1428$, find the greatest common divisor of $a^2+9a+24$ and $a+4$.
Answer:
Let's think step by step.

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Given that $a$ is a multiple of $1428$, find the greatest common divisor of $a^2+9a+24$ and $a+4$.
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