Solve \[\frac{2x+4}{x^2+4x-5}=\frac{2-x}{x-1}\]for $x$.
Question:
Solve \[\frac{2x+4}{x^2+4x-5}=\frac{2-x}{x-1}\]for $x$.
Answer:
Let's think step by step.

user
-6
Solve \[\frac{2x+4}{x^2+4x-5}=\frac{2-x}{x-1}\]for $x$.
train