Find the largest value of $c$ such that $\frac{c^2 + 6c -27}{c-3} +2c = 23$.
Question:
Find the largest value of $c$ such that $\frac{c^2 + 6c -27}{c-3} +2c = 23$.
Answer:
Let's think step by step.

user
\frac{14}{3}
Find the largest value of $c$ such that $\frac{c^2 + 6c -27}{c-3} +2c = 23$.
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