Find the constant $c$ such that $$(x^2-4x+3)(x+5) - (x^2+4x-5)(x-c)=0$$ for all $x.$
Question:
Find the constant $c$ such that $$(x^2-4x+3)(x+5) - (x^2+4x-5)(x-c)=0$$ for all $x.$
Answer:
Let's think step by step.

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Find the constant $c$ such that $$(x^2-4x+3)(x+5) - (x^2+4x-5)(x-c)=0$$ for all $x.$
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