Find the center of the circle with equation $x^2 + 14x + y^2 - 6y + 53 = 0$.
Question:
Find the center of the circle with equation $x^2 + 14x + y^2 - 6y + 53 = 0$.
Answer:
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(-7, 3)
Find the center of the circle with equation $x^2 + 14x + y^2 - 6y + 53 = 0$.
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