What is the largest integer $n$ for which $\binom{8}{3} + \binom{8}{4} = \binom{9}{n}$?
Question:
What is the largest integer $n$ for which $\binom{8}{3} + \binom{8}{4} = \binom{9}{n}$?
Answer:
Let's think step by step.

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What is the largest integer $n$ for which $\binom{8}{3} + \binom{8}{4} = \binom{9}{n}$?
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