Find the least positive four-digit solution $r$ of the congruence $r^2 + 4r + 4 \equiv r^2 + 2r + 1 \pmod{55} $.
Question:
Find the least positive four-digit solution $r$ of the congruence $r^2 + 4r + 4 \equiv r^2 + 2r + 1 \pmod{55} $.
Answer:
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Find the least positive four-digit solution $r$ of the congruence $r^2 + 4r + 4 \equiv r^2 + 2r + 1 \pmod{55} $.
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