An ordered pair of digits $(a, b)$ is such that $4a5,b32$ is a multiple of 66. Find $a+b$.
Question:
An ordered pair of digits $(a, b)$ is such that $4a5,b32$ is a multiple of 66. Find $a+b$.
Answer:
Let's think step by step.

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An ordered pair of digits $(a, b)$ is such that $4a5,b32$ is a multiple of 66. Find $a+b$.
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