In isosceles triangle $\triangle ABC$ we have $AB=AC=4$.  The altitude from $B$ meets $\overline{AC}$ at $H$.  If $AH=3(HC)$ then determine $BC$.
Question:
In isosceles triangle $\triangle ABC$ we have $AB=AC=4$.  The altitude from $B$ meets $\overline{AC}$ at $H$.  If $AH=3(HC)$ then determine $BC$.
Answer:
Let's think step by step.

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2\sqrt{2}
In isosceles triangle $\triangle ABC$ we have $AB=AC=4$.  The altitude from $B$ meets $\overline{AC}$ at $H$.  If $AH=3(HC)$ then determine $BC$.
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