In triangle $ABC,$ $D$ is on $\overline{AB}$ such that $AD:DB = 3:2,$ and $E$ is on $\overline{BC}$ such that $BE:EC = 3:2.$  If lines $DE$ and $AC$ intersect at $F,$ then find $\frac{DE}{EF}.$
Question:
In triangle $ABC,$ $D$ is on $\overline{AB}$ such that $AD:DB = 3:2,$ and $E$ is on $\overline{BC}$ such that $BE:EC = 3:2.$  If lines $DE$ and $AC$ intersect at $F,$ then find $\frac{DE}{EF}.$
Answer:
Let's think step by step.

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\frac{1}{2}
In triangle $ABC,$ $D$ is on $\overline{AB}$ such that $AD:DB = 3:2,$ and $E$ is on $\overline{BC}$ such that $BE:EC = 3:2.$  If lines $DE$ and $AC$ intersect at $F,$ then find $\frac{DE}{EF}.$
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