In right triangle $ABC$ with $\angle A = 90^\circ$, we have $AB = 5$ and $BC = 8$.  Find $\sin B$.
Question:
In right triangle $ABC$ with $\angle A = 90^\circ$, we have $AB = 5$ and $BC = 8$.  Find $\sin B$.
Answer:
Let's think step by step.

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\frac{\sqrt{39}}{8}
In right triangle $ABC$ with $\angle A = 90^\circ$, we have $AB = 5$ and $BC = 8$.  Find $\sin B$.
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