Compute $\frac{x^6-16x^3+64}{x^3-8}$ when $x=6$.
Question:
Compute $\frac{x^6-16x^3+64}{x^3-8}$ when $x=6$.
Answer:
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Compute $\frac{x^6-16x^3+64}{x^3-8}$ when $x=6$.
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