For $1 \le n \le 100$, how many integers are there such that $\frac{n}{n+1}$ is a repeating decimal?
Question:
For $1 \le n \le 100$, how many integers are there such that $\frac{n}{n+1}$ is a repeating decimal?
Answer:
Let's think step by step.

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For $1 \le n \le 100$, how many integers are there such that $\frac{n}{n+1}$ is a repeating decimal?
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