Solve for $x$: $$\dfrac{66-2^x}{2^x+3}=\dfrac{4-2^x}{2^{x+1}+6}$$
Question:
Solve for $x$: $$\dfrac{66-2^x}{2^x+3}=\dfrac{4-2^x}{2^{x+1}+6}$$
Answer:
Let's think step by step.

user
7
Solve for $x$: $$\dfrac{66-2^x}{2^x+3}=\dfrac{4-2^x}{2^{x+1}+6}$$
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