In right triangle $DEF$, we have $\sin D = \frac{5}{13}$ and $\sin E = 1$.  Find $\sin F$.
Question:
In right triangle $DEF$, we have $\sin D = \frac{5}{13}$ and $\sin E = 1$.  Find $\sin F$.
Answer:
Let's think step by step.

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\frac{12}{13}
In right triangle $DEF$, we have $\sin D = \frac{5}{13}$ and $\sin E = 1$.  Find $\sin F$.
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