Find $q(x)$ if the graph of $\frac{4x-x^3}{q(x)}$ has a hole at $x=-2$, a vertical asymptote at $x=1$, no horizontal asymptote, and $q(3) = -30$.
Question:
Find $q(x)$ if the graph of $\frac{4x-x^3}{q(x)}$ has a hole at $x=-2$, a vertical asymptote at $x=1$, no horizontal asymptote, and $q(3) = -30$.
Answer:
Let's think step by step.

user
-3(x+2)(x-1)
Find $q(x)$ if the graph of $\frac{4x-x^3}{q(x)}$ has a hole at $x=-2$, a vertical asymptote at $x=1$, no horizontal asymptote, and $q(3) = -30$.
train