In triangle $ABC,$
\[(b \sin C)(b \cos C + c \cos B) = 42.\]Compute the area of triangle $ABC.$
Question:
In triangle $ABC,$
\[(b \sin C)(b \cos C + c \cos B) = 42.\]Compute the area of triangle $ABC.$
Answer:
Let's think step by step.

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In triangle $ABC,$
\[(b \sin C)(b \cos C + c \cos B) = 42.\]Compute the area of triangle $ABC.$
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