What is the value of $b$ if $-x^2+bx-5<0$ only when $x\in (-\infty, 1)\cup(5,\infty)$?
Question:
What is the value of $b$ if $-x^2+bx-5<0$ only when $x\in (-\infty, 1)\cup(5,\infty)$?
Answer:
Let's think step by step.

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What is the value of $b$ if $-x^2+bx-5<0$ only when $x\in (-\infty, 1)\cup(5,\infty)$?
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