If $\frac{\sin (2A + B)}{\sin B} = 5,$ then find $\frac{\tan (A + B)}{\tan A}.$
Question:
If $\frac{\sin (2A + B)}{\sin B} = 5,$ then find $\frac{\tan (A + B)}{\tan A}.$
Answer:
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\frac{3}{2}
If $\frac{\sin (2A + B)}{\sin B} = 5,$ then find $\frac{\tan (A + B)}{\tan A}.$
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