In right triangle $PQR$, we have $\angle Q = \angle R$ and $PR = 6\sqrt{2}$.  What is the area of $\triangle PQR$?
Question:
In right triangle $PQR$, we have $\angle Q = \angle R$ and $PR = 6\sqrt{2}$.  What is the area of $\triangle PQR$?
Answer:
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In right triangle $PQR$, we have $\angle Q = \angle R$ and $PR = 6\sqrt{2}$.  What is the area of $\triangle PQR$?
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