In equilateral triangle $ABC,$ let points $D$ and $E$ trisect $\overline{BC}$.  Find $\sin \angle DAE.$
Question:
In equilateral triangle $ABC,$ let points $D$ and $E$ trisect $\overline{BC}$.  Find $\sin \angle DAE.$
Answer:
Let's think step by step.

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\frac{3 \sqrt{3}}{14}
In equilateral triangle $ABC,$ let points $D$ and $E$ trisect $\overline{BC}$.  Find $\sin \angle DAE.$
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