If $e^{i \alpha} = \frac{3}{5}  +\frac{4}{5} i$ and $e^{i \beta} = -\frac{12}{13} + \frac{5}{13} i,$ then find $\sin (\alpha + \beta).$
Question:
If $e^{i \alpha} = \frac{3}{5}  +\frac{4}{5} i$ and $e^{i \beta} = -\frac{12}{13} + \frac{5}{13} i,$ then find $\sin (\alpha + \beta).$
Answer:
Let's think step by step.

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-\frac{33}{65}
If $e^{i \alpha} = \frac{3}{5}  +\frac{4}{5} i$ and $e^{i \beta} = -\frac{12}{13} + \frac{5}{13} i,$ then find $\sin (\alpha + \beta).$
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