In right triangle $ABC$ with $\angle B = 90^\circ$, we have $$2\sin A = 3\cos A.$$What is $\sin A$?
Question:
In right triangle $ABC$ with $\angle B = 90^\circ$, we have $$2\sin A = 3\cos A.$$What is $\sin A$?
Answer:
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\frac{3\sqrt{13}}{13}
In right triangle $ABC$ with $\angle B = 90^\circ$, we have $$2\sin A = 3\cos A.$$What is $\sin A$?
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