If two numbers will be randomly chosen without replacement from $\{3, 4, 5, 6\}$, what is the probability that their product will be a multiple of 9? Express your answer as a common fraction.
Question:
If two numbers will be randomly chosen without replacement from $\{3, 4, 5, 6\}$, what is the probability that their product will be a multiple of 9? Express your answer as a common fraction.
Answer:
Let's think step by step.

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\frac{1}{6}
If two numbers will be randomly chosen without replacement from $\{3, 4, 5, 6\}$, what is the probability that their product will be a multiple of 9? Express your answer as a common fraction.
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