Three positive integers $a$, $b$, and $c$ satisfy $a\cdot b\cdot c=8!$ and $a<b<c$.  What is the smallest possible value of $c-a$?
Question:
Three positive integers $a$, $b$, and $c$ satisfy $a\cdot b\cdot c=8!$ and $a<b<c$.  What is the smallest possible value of $c-a$?
Answer:
Let's think step by step.

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Three positive integers $a$, $b$, and $c$ satisfy $a\cdot b\cdot c=8!$ and $a<b<c$.  What is the smallest possible value of $c-a$?
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