Compute the value of $k$ such that the equation
\[\frac{x + 2}{kx - 1} = x\]has exactly one solution.
Question:
Compute the value of $k$ such that the equation
\[\frac{x + 2}{kx - 1} = x\]has exactly one solution.
Answer:
Let's think step by step.

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Compute the value of $k$ such that the equation
\[\frac{x + 2}{kx - 1} = x\]has exactly one solution.
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