Two non-zero real numbers, $a$ and $b$, satisfy $ab=a-b$. Find the smallest possible value of: $\frac{a}{b}+\frac{b}{a}-ab$.
Question:
Two non-zero real numbers, $a$ and $b$, satisfy $ab=a-b$. Find the smallest possible value of: $\frac{a}{b}+\frac{b}{a}-ab$.
Answer:
Let's think step by step.

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Two non-zero real numbers, $a$ and $b$, satisfy $ab=a-b$. Find the smallest possible value of: $\frac{a}{b}+\frac{b}{a}-ab$.
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