Find the center of the circle with equation $x^2 - 2x + y^2 - 4y - 28 = 0$.
Question:
Find the center of the circle with equation $x^2 - 2x + y^2 - 4y - 28 = 0$.
Answer:
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(1, 2)
Find the center of the circle with equation $x^2 - 2x + y^2 - 4y - 28 = 0$.
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