Solve for $x$: $$\left(\frac{1}{25}\right)^{x + 2} = 125^{-x}.$$
Question:
Solve for $x$: $$\left(\frac{1}{25}\right)^{x + 2} = 125^{-x}.$$
Answer:
Let's think step by step.

user
x = 4
Solve for $x$: $$\left(\frac{1}{25}\right)^{x + 2} = 125^{-x}.$$
train