Given that $\sin A+\sin B=1$ and $\cos A+\cos B= \frac{3}{2}$, what is the value of $\cos(A-B)$?
Question:
Given that $\sin A+\sin B=1$ and $\cos A+\cos B= \frac{3}{2}$, what is the value of $\cos(A-B)$?
Answer:
Let's think step by step.

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\frac{5}{8}
Given that $\sin A+\sin B=1$ and $\cos A+\cos B= \frac{3}{2}$, what is the value of $\cos(A-B)$?
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