Find the number of ordered pairs $(x,y)$ of real numbers that satisfy
\[x^2 + 2y^2 + \frac{1}{2} \le x(2y + 1).\]
Question:
Find the number of ordered pairs $(x,y)$ of real numbers that satisfy
\[x^2 + 2y^2 + \frac{1}{2} \le x(2y + 1).\]
Answer:
Let's think step by step.

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1
Find the number of ordered pairs $(x,y)$ of real numbers that satisfy
\[x^2 + 2y^2 + \frac{1}{2} \le x(2y + 1).\]
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