Let $x$ and $y$ be positive real numbers.  Find the minimum value of
\[\left( x + \frac{1}{y} \right) \left( x + \frac{1}{y} + 2018 \right) + \left( y + \frac{1}{x} \right) \left( y + \frac{1}{x} + 2018 \right).\]
Question:
Let $x$ and $y$ be positive real numbers.  Find the minimum value of
\[\left( x + \frac{1}{y} \right) \left( x + \frac{1}{y} + 2018 \right) + \left( y + \frac{1}{x} \right) \left( y + \frac{1}{x} + 2018 \right).\]
Answer:
Let's think step by step.

user
8080
Let $x$ and $y$ be positive real numbers.  Find the minimum value of
\[\left( x + \frac{1}{y} \right) \left( x + \frac{1}{y} + 2018 \right) + \left( y + \frac{1}{x} \right) \left( y + \frac{1}{x} + 2018 \right).\]
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