If $\frac{\cos 3x}{\cos x} = \frac{1}{3},$ then determine $\frac{\sin 3x}{\sin x}.$
Question:
If $\frac{\cos 3x}{\cos x} = \frac{1}{3},$ then determine $\frac{\sin 3x}{\sin x}.$
Answer:
Let's think step by step.

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\frac{7}{3}
If $\frac{\cos 3x}{\cos x} = \frac{1}{3},$ then determine $\frac{\sin 3x}{\sin x}.$
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