Let $f(x) = x^3 + bx + c.$  If $(x - 1)^2$ is a factor of $f(x),$ then find the ordered pair $(b,c).$
Question:
Let $f(x) = x^3 + bx + c.$  If $(x - 1)^2$ is a factor of $f(x),$ then find the ordered pair $(b,c).$
Answer:
Let's think step by step.

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(-3,2)
Let $f(x) = x^3 + bx + c.$  If $(x - 1)^2$ is a factor of $f(x),$ then find the ordered pair $(b,c).$
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