A triangle has vertices at coordinates $(1, 2), (7, 10)$ and $(1, 12)$.  What is the number of units in the length of the shortest side of the triangle?
Question:
A triangle has vertices at coordinates $(1, 2), (7, 10)$ and $(1, 12)$.  What is the number of units in the length of the shortest side of the triangle?
Answer:
Let's think step by step.

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2\sqrt{10}
A triangle has vertices at coordinates $(1, 2), (7, 10)$ and $(1, 12)$.  What is the number of units in the length of the shortest side of the triangle?
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