Let  \[f(x) =
\begin{cases}
k(x) &\text{if }x>2, \\
2+(x-2)^2&\text{if }x\leq2.
\end{cases}
\]Find the function $k(x)$ such that $f$ is its own inverse.
Question:
Let  \[f(x) =
\begin{cases}
k(x) &\text{if }x>2, \\
2+(x-2)^2&\text{if }x\leq2.
\end{cases}
\]Find the function $k(x)$ such that $f$ is its own inverse.
Answer:
Let's think step by step.

user
-\sqrt{x-2}+2
Let  \[f(x) =
\begin{cases}
k(x) &\text{if }x>2, \\
2+(x-2)^2&\text{if }x\leq2.
\end{cases}
\]Find the function $k(x)$ such that $f$ is its own inverse.
train