The sum $10 e^{2 \pi i/11} + 10 e^{15 \pi i/22}$ is expressed as $re^{i \theta}.$  Enter the ordered pair $(r, \theta).$
Question:
The sum $10 e^{2 \pi i/11} + 10 e^{15 \pi i/22}$ is expressed as $re^{i \theta}.$  Enter the ordered pair $(r, \theta).$
Answer:
Let's think step by step.

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\left( 10 \sqrt{2}, \frac{19 \pi}{44} \right)
The sum $10 e^{2 \pi i/11} + 10 e^{15 \pi i/22}$ is expressed as $re^{i \theta}.$  Enter the ordered pair $(r, \theta).$
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