Altitudes $\overline{AX}$ and $\overline{BY}$ of acute triangle $ABC$ intersect at $H$.  If $\angle AHB = 132^\circ$, then what is $\angle ACB$?
Question:
Altitudes $\overline{AX}$ and $\overline{BY}$ of acute triangle $ABC$ intersect at $H$.  If $\angle AHB = 132^\circ$, then what is $\angle ACB$?
Answer:
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48^\circ
Altitudes $\overline{AX}$ and $\overline{BY}$ of acute triangle $ABC$ intersect at $H$.  If $\angle AHB = 132^\circ$, then what is $\angle ACB$?
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