Since $\sin \left( -\frac{\pi}{6} \right) = -\frac{1}{2},$ $\arcsin \left( -\frac{1}{2} \right) = \boxed{-\frac{\pi}{6}}.$
Question:
Compute $\arcsin \left( -\frac{1}{2} \right).$  Express your answer in radians.
Answer:
Let's think step by step.

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-\frac{\pi}{6}
Compute $\arcsin \left( -\frac{1}{2} \right).$  Express your answer in radians.
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