In triangle $ABC$, we have $\angle A = 90^\circ$ and $\sin B = \frac{4}{7}$.  Find $\cos C$.
Question:
In triangle $ABC$, we have $\angle A = 90^\circ$ and $\sin B = \frac{4}{7}$.  Find $\cos C$.
Answer:
Let's think step by step.

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In triangle $ABC$, we have $\angle A = 90^\circ$ and $\sin B = \frac{4}{7}$.  Find $\cos C$.
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