Compute the positive integer $x$ such that
\[4x^3 - 41x^2 + 10x = 1989.\]
Question:
Compute the positive integer $x$ such that
\[4x^3 - 41x^2 + 10x = 1989.\]
Answer:
Let's think step by step.

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13
Compute the positive integer $x$ such that
\[4x^3 - 41x^2 + 10x = 1989.\]
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