If $\sin x,$ $\cos x,$ $\tan x$ form a geometric sequence, in this order, then find $\cot^6 x - \cot^2 x.$
Question:
If $\sin x,$ $\cos x,$ $\tan x$ form a geometric sequence, in this order, then find $\cot^6 x - \cot^2 x.$
Answer:
Let's think step by step.

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If $\sin x,$ $\cos x,$ $\tan x$ form a geometric sequence, in this order, then find $\cot^6 x - \cot^2 x.$
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