Find the distance between the planes $x - 3y + 3z = 8$ and $2x - 6y + 6z = 2.$
Question:
Find the distance between the planes $x - 3y + 3z = 8$ and $2x - 6y + 6z = 2.$
Answer:
Let's think step by step.

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\frac{7 \sqrt{19}}{19}
Find the distance between the planes $x - 3y + 3z = 8$ and $2x - 6y + 6z = 2.$
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