If $a = \log 9$ and $b = \log 16,$ compute
\[4^{a/b} + 3^{b/a}.\]
Question:
If $a = \log 9$ and $b = \log 16,$ compute
\[4^{a/b} + 3^{b/a}.\]
Answer:
Let's think step by step.

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If $a = \log 9$ and $b = \log 16,$ compute
\[4^{a/b} + 3^{b/a}.\]
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