Evaluate $\frac{3+x(3+x)-3^2}{x-3+x^2}$ for $x=-2$.
Question:
Evaluate $\frac{3+x(3+x)-3^2}{x-3+x^2}$ for $x=-2$.
Answer:
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Evaluate $\frac{3+x(3+x)-3^2}{x-3+x^2}$ for $x=-2$.
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