Solve for $x$: $(x-4)^3=\left(\frac18\right)^{-1}$
Question:
Solve for $x$: $(x-4)^3=\left(\frac18\right)^{-1}$
Answer:
Let's think step by step.

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Solve for $x$: $(x-4)^3=\left(\frac18\right)^{-1}$
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