If
\[\cos 41^\circ + \sin 41^\circ = \sqrt{2} \sin A,\]where $0^\circ < A < 90^\circ,$ compute the degree measure of $A.$
Question:
If
\[\cos 41^\circ + \sin 41^\circ = \sqrt{2} \sin A,\]where $0^\circ < A < 90^\circ,$ compute the degree measure of $A.$
Answer:
Let's think step by step.

user
86^\circ
If
\[\cos 41^\circ + \sin 41^\circ = \sqrt{2} \sin A,\]where $0^\circ < A < 90^\circ,$ compute the degree measure of $A.$
train