The operation $\Diamond$ is defined by $a\Diamond b=ab^2-b+1$.  What is the value of $(-1)\Diamond 6$?
Question:
The operation $\Diamond$ is defined by $a\Diamond b=ab^2-b+1$.  What is the value of $(-1)\Diamond 6$?
Answer:
Let's think step by step.

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The operation $\Diamond$ is defined by $a\Diamond b=ab^2-b+1$.  What is the value of $(-1)\Diamond 6$?
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