If $\sqrt{400}=\sqrt{81}+\sqrt{n}$, then what is the value of $n$?
Question:
If $\sqrt{400}=\sqrt{81}+\sqrt{n}$, then what is the value of $n$?
Answer:
Let's think step by step.

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If $\sqrt{400}=\sqrt{81}+\sqrt{n}$, then what is the value of $n$?
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