If $n$ is a multiple of three, what is the remainder when $(n + 4) + (n + 6) + (n + 8)$ is divided by $9$?
Question:
If $n$ is a multiple of three, what is the remainder when $(n + 4) + (n + 6) + (n + 8)$ is divided by $9$?
Answer:
Let's think step by step.

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If $n$ is a multiple of three, what is the remainder when $(n + 4) + (n + 6) + (n + 8)$ is divided by $9$?
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