What is the greatest digit that can be placed in the circle so that the six-digit number is divisible by 4? $$3\:5\:2\:9 \bigcirc 2$$
Question:
What is the greatest digit that can be placed in the circle so that the six-digit number is divisible by 4? $$3\:5\:2\:9 \bigcirc 2$$
Answer:
Let's think step by step.

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What is the greatest digit that can be placed in the circle so that the six-digit number is divisible by 4? $$3\:5\:2\:9 \bigcirc 2$$
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