There is an equal number of clownfish and blowfish, which means there are 100 fish / 2 = <<100/2=50>>50 blowfish.

Since some stay in their tanks, there are 50 blowfish – 26 blowfish = <<50-26=24>>24 blowfish in the display tank.

There were the same amount of clownfish until 24 clownfish / 3 = <<24/3=8>>8 clownfish swam back to their own tank.

This leaves 24 clownfish – 8 clownfish = <<24-8=16>>16 clownfish in the display tank.

# Answer

16
Question:
An aquarium holds an equal number of clownfish and blowfish. 26 of the blowfish stay in their own tank, and the remaining blowfish swim into a display tank.  An equal number of clownfish join the blowfish in the display tank, but then a third of these clownfish swim back into their own tank.  If the aquarium holds a combined total of 100 fish, how many clownfish are now in the display tank?
Answer:
Let's think step by step.

user
16
An aquarium holds an equal number of clownfish and blowfish. 26 of the blowfish stay in their own tank, and the remaining blowfish swim into a display tank.  An equal number of clownfish join the blowfish in the display tank, but then a third of these clownfish swim back into their own tank.  If the aquarium holds a combined total of 100 fish, how many clownfish are now in the display tank?
train