\frac{2}{5}
Question:
In triangle $LMN$, we have $\angle M = 90^\circ$, $MN = 2$, and $LM = \sqrt{21}$. What is $\sin L$?
Answer:
Let's think step by step.

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\frac{2}{5}
In triangle $LMN$, we have $\angle M = 90^\circ$, $MN = 2$, and $LM = \sqrt{21}$. What is $\sin L$?
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