There are 5+2 = <<5+2=7>>7 huskies and pitbulls

7 huskies and pitbulls had 3 pups each for a total of 3*7 = <<7*3=21>>21 pups

Each golden retriever had 2 more pups each than the huskies who had 3 each so each golden retriever had 3+2 = <<3+2=5>>5 pups

4 golden retrievers had 5 pups each for a total of 20 pups

There are a total of 21+20 = <<21+20=41>>41 pups

There are a total of 5+2+4 = <<5+2+4=11>>11 adult dogs

There are 41-11 = <<41-11=30>>30 more pups than adult dogs

# Answer

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Question:
James has five huskies, two pitbulls and four golden retrievers, all female. They became pregnant and each golden retriever had two more pups than each husky. If the huskies and pitbulls had 3 pups each, How many more pups than adult dogs are there in total?
Answer:
Let's think step by step.

user
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James has five huskies, two pitbulls and four golden retrievers, all female. They became pregnant and each golden retriever had two more pups than each husky. If the huskies and pitbulls had 3 pups each, How many more pups than adult dogs are there in total?
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