// Replay Value // Solution by Jacob Plachta #define DEBUG 0 #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; #define LL long long #define LD long double #define PR pair #define Fox(i,n) for (i=0; i=0; i--) #define FoxR1(i,n) for (i=n; i>0; i--) #define FoxRI(i,a,b) for (i=b; i>=a; i--) #define Foxen(i,s) for (i=s.begin(); i!=s.end(); i++) #define Min(a,b) a=min(a,b) #define Max(a,b) a=max(a,b) #define Sz(s) int((s).size()) #define All(s) (s).begin(),(s).end() #define Fill(s,v) memset(s,v,sizeof(s)) #define pb push_back #define mp make_pair #define x first #define y second template T Abs(T x) { return(x<0 ? -x : x); } template T Sqr(T x) { return(x*x); } string plural(string s) { return(Sz(s) && s[Sz(s)-1]=='x' ? s+"en" : s+"s"); } const int INF = (int)1e9; const LD EPS = 1e-12; const LD PI = acos(-1.0); #if DEBUG #define GETCHAR getchar #else #define GETCHAR getchar_unlocked #endif bool Read(int &x) { char c,r=0,n=0; x=0; for(;;) { c=GETCHAR(); if ((c<0) && (!r)) return(0); if ((c=='-') && (!r)) n=1; else if ((c>='0') && (c<='9')) x=x*10+c-'0',r=1; else if (r) break; } if (n) x=-x; return(1); } #define LIM 52 #define MOD 1000000007 int dyn[2][LIM][LIM][LIM][LIM]; // dyn[i][a][b][c][d] = number of ways such that: // i = laser index // a = lowest Up // b = highest Down // c = lowest Right in regions 1/2 // d = highest Right in region 3 int N; vector cy; void ReadY(int &y) { Read(y),cy.pb(y); } void CompY(int &y) { y=lower_bound(All(cy),y)-cy.begin(); } void Flip(int &v) { v=N+1-v; } void Add(int &a,int b) { a+=b; if (a>=MOD) a-=MOD; } int main() { if (DEBUG) freopen("in.txt","r",stdin); // vars int T,t; int YA,YB; int i,a,b,c,d,y,r,v,m,ans; int A,B; PR P[LIM]; // testcase loop Read(T); Fox1(t,T) { // init cy.clear(); // input Read(N),ReadY(YA),ReadY(YB); Fox(i,N) Read(P[i].x),ReadY(P[i].y); // compress y-coordinates sort(All(cy)); CompY(YA),CompY(YB); Fox(i,N) CompY(P[i].y); // mirror y-axis such that B is below A if (YAYA ? 1 : (y>YB ? 2 : 3)); // perform transitions Fox(a,N+2) Fox(b,N+2) Fox(c,N+2) Fox(d,N+2) if (v=dyn[A][a][b][c][d]) { // up if (y>=d) Add(dyn[B][min(a,y)][b][c][d],v); // down if (y<=c) Add(dyn[B][a][max(b,y)][c][d],v); // left if ((r==1 && y>=b) || (r>1 && y<=a)) Add(dyn[B][a][b][c][d],v); // right if (r<3) Add(dyn[B][a][b][min(c,y)][d],v); else Add(dyn[B][a][b][c][max(d,y)],v); } } // compute answer ans=1; Fox(i,N) ans=(LL)ans*4%MOD; v=0; Fox(a,N+2) Fox(b,N+2) Fox(c,N+2) Fox(d,N+2) Add(v,dyn[B][a][b][c][d]); ans=(ans-v+MOD)%MOD; // output printf("Case #%d: %d\n",t,ans); } return(0); }