#include #include using namespace std; const int ALPHA_SIZE = 26; struct node { int count; vector child; node(int _count = 0) : count(_count), child(ALPHA_SIZE, nullptr) {} void merge(node *n) { count++; for (int i = 0; i < ALPHA_SIZE; i++) { if (n->child[i] != nullptr) { if (child[i] == nullptr) { child[i] = new node(); } child[i]->merge(n->child[i]); } } } }; class trie { node *root; template static void walk(node *n, Func f) { f(n->count); for (int i = 0; i < ALPHA_SIZE; i++) { if (n->child[i] != nullptr) { walk(n->child[i], f); } } } static void clean_up(node *n) { for (int i = 0; i < ALPHA_SIZE; i++) { if (n->child[i] != nullptr) { clean_up(n->child[i]); } } delete n; } public: trie() : root(new node()) {} ~trie() { clean_up(root); } void merge(node *n) { root->merge(n); } template void walk(Func f) const { walk(root, f); } }; long long solve() { int N, p; char c; cin >> N; vector> tries(N); for (int i = 0, M; i < N; i++) { cin >> M; auto &T = tries[i]; T.resize(M); for (int j = 1; j < M; j++) { cin >> p >> c; T[--p].child[c - 'a'] = &T[j]; } } trie merged; for (auto &T : tries) { merged.merge(&T[0]); } auto n_choose_3 = [](long long n) { return n < 3 ? 0 : n * (n - 1) * (n - 2) / 6; }; long long ans = 0; merged.walk([&](int k) { // This node is in k tries. For how many out of all N choose 3 possible // triples (T1, T2, T3) of tries is this node in at least one of the tries? // The answer is N choose 3 minus the number of triples that doesn't have // this node in any of the three tries, equal to (N - k) choose 3. ans += n_choose_3(N) - n_choose_3(N - k); }); return ans; } int main() { ios_base::sync_with_stdio(false); cin.tie(nullptr); int T; cin >> T; for (int t = 1; t <= T; t++) { cout << "Case #" << t << ": " << solve() << endl; } return 0; }