how to calculate percentage error in kinetic energy?
To get the percentage error divide the above by m v^2; 1 + (em/m) + 2 (ev/v) + 2 (em/m) (ev/v) + (ev/v)^2 + (em/m) (ev/v)^2 . 0Take mass M and speed V as central values, then KE = (1/2)MV^2 but you have M±0.02M and V±0.03V so the smallest KE is (1/2)(M-0.02M)(V-0.03V)^2 and the greatest KE is (1/2)(M+0.02M)(V+0.03V)^2.