Write SQL query to solve given problem: Among all the employees, how many percent more for the publishers than designers?. Keep the solution inside sql tag ```sql [SQL-Query] ```
SELECT CAST(SUM(CASE WHEN T2.job_desc = 'publisher' THEN 1 ELSE 0 END) - SUM(CASE WHEN T2.job_desc = 'designer' THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(T1.job_id) FROM employee AS T1 INNER JOIN jobs AS T2 ON T1.job_id = T2.job_id