Write SQL query to solve given problem: List the store ID of the films with a rental rate greater than the 60% of average rental rate of all listed films.. Keep the solution inside sql tag ```sql [SQL-Query] ```
SELECT T2.store_id FROM film AS T1 INNER JOIN inventory AS T2 ON T1.film_id = T2.film_id WHERE T1.rental_rate > ( SELECT AVG(T1.rental_rate) * 0.6 FROM film AS T1 )