Write SQL query to solve given problem: What is the criteria name of the university ID 32 in 2015?. Keep the solution inside sql tag ```sql [SQL-Query] ```
SELECT T1.criteria_name FROM ranking_criteria AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.ranking_criteria_id WHERE T2.university_id = 32 AND T2.year = 2015