Write SQL query to solve given problem: By what percentage is the average salary of Trainees higher than the minimum salary of this postion?. Keep the solution inside sql tag ```sql [SQL-Query] ```
SELECT 100 * (AVG(CAST(REPLACE(SUBSTR(T1.salary, 4), ',', '') AS REAL)) - CAST(REPLACE(SUBSTR(T2.minsalary, 4), ',', '') AS REAL)) / CAST(REPLACE(SUBSTR(T2.minsalary, 4), ',', '') AS REAL) AS per FROM employee AS T1  INNER JOIN position AS T2  ON T1.positionID = T2.positionID WHERE T2.positiontitle = 'Trainee'