Write SQL query to solve given problem: List all the tires businesses that are opened everyday.. Keep the solution inside sql tag ```sql [SQL-Query] ```
SELECT DISTINCT T2.business_id FROM Categories AS T1 INNER JOIN Business_Categories AS T2 ON T1.category_id = T2.category_id INNER JOIN Business AS T3 ON T2.business_id = T3.business_id INNER JOIN Business_Hours AS T4 ON T3.business_id = T4.business_id WHERE T1.category_name = 'Tires' GROUP BY T2.business_id HAVING COUNT(day_id) = 7