Write SQL query to solve given problem: List the name and city of starting stations which has an above-average duration trips.. Keep the solution inside sql tag ```sql [SQL-Query] ```
SELECT DISTINCT T1.start_station_name, T2.city FROM trip AS T1 INNER JOIN station AS T2 ON T2.name = T1.start_station_name WHERE T1.duration > ( SELECT AVG(T1.duration) FROM trip AS T1 LEFT JOIN station AS T2 ON T2.name = T1.start_station_name )