Write SQL query to solve given problem: How much more votes for episode 1 than for episode 5?. Keep the solution inside sql tag ```sql [SQL-Query] ```
SELECT SUM(CASE WHEN T1.episode = 1 THEN T2.votes ELSE 0 END) - SUM(CASE WHEN T1.episode = 5 THEN T2.votes ELSE 0 END) AS diff FROM Episode AS T1 INNER JOIN Vote AS T2 ON T2.episode_id = T1.episode_id;