Write SQL query to solve given problem: How many more stars in percentage are there for the repository of solution "1" than solution "2"?. Keep the solution inside sql tag ```sql [SQL-Query] ```
SELECT CAST(SUM(CASE WHEN T2.Id = 1 THEN T1.Stars ELSE 0 END) - SUM(CASE WHEN T2.Id = 2 THEN T1.Stars ELSE 0 END) AS REAL) * 100 / SUM(CASE WHEN T2.Id = 2 THEN T1.Stars ELSE 0 END) FROM Repo AS T1 INNER JOIN Solution AS T2 ON T1.Id = T2.RepoId