Write SQL query to solve given problem: Which establishment has the highest number of inspections done? Give the name of the establishment and calculate for its average score per inspection.. Keep the solution inside sql tag ```sql [SQL-Query] ```
SELECT T2.name, AVG(T1.score) FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id GROUP BY T2.name ORDER BY COUNT(T2.business_id) DESC LIMIT 1