Write SQL query to solve given problem: From 2003 to 2004, how many customers have paid more than three times?. Keep the solution inside sql tag ```sql [SQL-Query] ```
SELECT COUNT(customernumber) FROM ( SELECT customernumber FROM payments WHERE STRFTIME('%Y', paymentDate) >= '2003' AND STRFTIME('%Y', paymentDate) <= '2004' GROUP BY customernumber HAVING COUNT(customernumber) > 3 ) T