Write SQL query to solve given problem: Among the incidents reported in Harrison, what percentage are disorderly conduct?. Keep the solution inside sql tag ```sql [SQL-Query] ```
SELECT COUNT(CASE WHEN T3.title = 'Disorderly Conduct' THEN T2.report_no END) * 100.0 / COUNT(T2.report_no) AS per FROM District AS T1 INNER JOIN Crime AS T2 ON T2.district_no = T1.district_no INNER JOIN FBI_Code AS T3 ON T3.fbi_code_no = T2.fbi_code_no WHERE T1.district_name = 'Harrison'