Write SQL query to solve given problem: If a married employee has a western name style, what is the probability of him or her working as a store contact?. Keep the solution inside sql tag ```sql [SQL-Query] ```
SELECT CAST(COUNT(IIF(T1.PersonType = 'SC', T1.PersonType, NULL)) AS REAL) / COUNT(T1.PersonType) FROM Person AS T1 INNER JOIN Employee AS T2 WHERE T1.PersonType = 'SC' AND T1.NameStyle = 0 AND T2.MaritalStatus = 'M'