title: Count Ways Divide Circle Using N Non Intersecting Chords
signature: long long countWaysDivideCircleUsingNNonIntersectingChords(int a) {
test_code: #include <algorithm>
  #include <assert.h>
  #include <cstdlib>
  #include <iostream>
  #include <map>
  #include <set>
  #include <string>
  #include <tuple> 
  #include <unordered_map>
  #include <vector>
  #include <math.h>
  #include <cmath>
  #include <bits/stdc++.h>
  #include <numeric>
  #include <functional>
  
  using namespace std;
  
  // SOLUTION CODE
  // ============================================
  PLACEHOLDER_CODE_BODY
  
  // TESTING CODE 
  // ============================================
  bool validateSolution(long long actual, long long expected){
      return actual == expected;
  }
  
  string driver(int a, long long expected){
      try
      {
          if (validateSolution(PLACEHOLDER_FN_NAME(a), expected)){
              return "PASSED";
          }
          return "FAILED";
      }
      catch (const std::overflow_error& exception_obj)
      {
          return typeid(exception_obj).name();
      }
      catch (const std::runtime_error& exception_obj)
      {
          return typeid(exception_obj).name();
      }
      catch (const std::exception& exception_obj)
      {
          return typeid(exception_obj).name();
      }
      catch (...)
      {
          return "UNK_ERROR";
      }
  }
  
  int main() {
      string result = "";
  
      result = driver(32, 55534064877048198); 
      cout << "TEST-" << 0 << "..."
           <<  result
           << "\n";
  
      result = driver(32, 55534064877048198); 
      cout << "TEST-" << 1 << "..."
           <<  result
           << "\n";
  
      result = driver(31, 14544636039226909); 
      cout << "TEST-" << 2 << "..."
           <<  result
           << "\n";
  
      result = driver(29, 1002242216651368); 
      cout << "TEST-" << 3 << "..."
           <<  result
           << "\n";
  
      return 0;
  }
source_py: def count_ways_divide_circle_using_n_non_intersecting_chords(A):
      n = (2 * A)
      dpArray = ([0] * (n + 1))
      dpArray[0] = 1
      dpArray[2] = 1
      for i in range(4, (n + 1), 2):
          for j in range(0, (i - 1), 2):
              dpArray[i] += (dpArray[j] * dpArray[((i - 2) - j)])
      return int(dpArray[n])
source_cpp: int count_ways_divide_circle_using_n_non_intersecting_chords(int A) {
    int n = 2 * A;
    int dpArray [ n + 1 ] = {
      0 };
      dpArray [ 0 ] = 1;
      dpArray [ 2 ] = 1;
      for ( int i = 4;
      i <= n;
      i += 2 ) {
        for ( int j = 0;
        j < i - 1;
        j += 2 ) {
          dpArray [ i ] += ( dpArray [ j ] * dpArray [ i - 2 - j ] );
        }
      }
      return dpArray [ n ];
    }