title: Maximum Number Of Squares That Can Be Fit In A Right Angle Isosceles Triangle
signature: maximumNumberOfSquaresThatCanBeFitInARightAngleIsoscelesTriangle(b, m) {
test_code: import 'dart:convert';
  
  // SOLUTION CODE
  // ============================================
  PLACEHOLDER_CODE_BODY
  
  // TESTING CODE 
  // ============================================
  bool validateSolution(double actual, double expected){
      return (actual - expected).abs() < 1e-09;
  }
  
  String driver(b, m, double expected){
      try
      {
          if (validateSolution(PLACEHOLDER_FN_NAME(b, m), expected)){
              return "PASSED";
          }
          return "FAILED";
      }catch(exception_object){
          return exception_object.runtimeType.toString();
      }
  }
  
  int main() {
  
      print("TEST-0...${driver(
          40, 74, 
          -0.1241782322863404)
      }");
  
      print("TEST-1...${driver(
          38, 35, 
          0.04653061224489791)
      }");
  
      print("TEST-2...${driver(
          47, 71, 
          -0.11188256298353501)
      }");
  
      print("TEST-3...${driver(
          52, 29, 
          0.7110582639714625)
      }");
  
      print("TEST-4...${driver(
          21, 9, 
          1.5555555555555558)
      }");
  
      print("TEST-5...${driver(
          50, 33, 
          0.3902662993572084)
      }");
  
      print("TEST-6...${driver(
          8, 82, 
          -0.04402141582391434)
      }");
  
      print("TEST-7...${driver(
          56, 80, 
          -0.10500000000000001)
      }");
  
      print("TEST-8...${driver(
          93, 5, 
          163.68000000000004)
      }");
  
      print("TEST-9...${driver(
          21, 90, 
          -0.08944444444444444)
      }");
  
      return 0;
  }
source_py: def maximum_number_of_squares_that_can_be_fit_in_a_right_angle_isosceles_triangle(b, m):
      return ((((b / m) - 1) * (b / m)) / 2)
source_cpp: int maximum_number_of_squares_that_can_be_fit_in_a_right_angle_isosceles_triangle(int b, int m) {
    return ( b / m - 1 ) * ( b / m ) / 2;
  }