title: Program To Check If A Given Number Is Lucky All Digits Are Different
signature: function program_to_check_if_a_given_number_is_lucky_all_digits_are_different(n)
test_code: using Printf
  
  # SOLUTION CODE
  # ============================================
  PLACEHOLDER_CODE_BODY
  
  # TESTING CODE 
  # ============================================
  function validate_solution(actual, expected)
      return actual == expected
  end
  
  function driver(n, expected)
      try
  
          if validate_solution(PLACEHOLDER_FN_NAME(n), expected)
              return "PASSED";
          end
          return "FAILED";
      catch exception_obj
          return string(Base.typename(typeof(exception_obj)).wrapper);
      end
  end
  
  function main()
      
      result = driver(474, 0);
      @printf("TEST-0...%s\n",result);
      
      result = driver(9445, 0);
      @printf("TEST-1...%s\n",result);
      
      result = driver(90, 0);
      @printf("TEST-2...%s\n",result);
      
      result = driver(30, 0);
      @printf("TEST-3...%s\n",result);
      
      result = driver(37453, 0);
      @printf("TEST-4...%s\n",result);
      
      result = driver(27, 0);
      @printf("TEST-5...%s\n",result);
      
      result = driver(2400, 0);
      @printf("TEST-6...%s\n",result);
      
      result = driver(98, 0);
      @printf("TEST-7...%s\n",result);
      
      result = driver(46, 0);
      @printf("TEST-8...%s\n",result);
      
      result = driver(722, 0);
      @printf("TEST-9...%s\n",result);
      
  end
  
  main()
source_py: def program_to_check_if_a_given_number_is_lucky_all_digits_are_different(n):
      ar = ([0] * 10)
      while (n > 0):
          digit = math.floor((n % 10))
          if ar[digit]:
              return 0
          ar[digit] = 1
          n = (n / 10)
      return 1
source_cpp: bool program_to_check_if_a_given_number_is_lucky_all_digits_are_different(int n) {
    bool arr [ 10 ];
    for ( int i = 0;
    i < 10;
    i ++ ) arr [ i ] = false;
    while ( n > 0 ) {
      int digit = n % 10;
      if ( arr [ digit ] ) return false;
      arr [ digit ] = true;
      n = n / 10;
    }
    return true;
  }