title: Check If All The Elements Can Be Made Of Same Parity By Inverting Adjacent Elements
signature: def checkIfAllTheElementsCanBeMadeOfSameParityByInvertingAdjacentElements(a: List[Int], n: Int) = {
test_code: import scala.collection.mutable.HashMap
  import scala.collection.immutable.HashSet
  
  
  // SOLUTION CODE
  // ============================================
  PLACEHOLDER_CODE_BODY
  
  
  // TESTING CODE 
  // ============================================
  def validateSolution(actual: Boolean , expected: Boolean): Boolean = {
      actual.toString == expected.toString
  }
  
  def driver(a: List[Int], n: Int, expected: Boolean): String = {
      try {
          if (validateSolution(PLACEHOLDER_FN_NAME(a, n),expected)) {
              "PASSED"
          } else{
              "FAILED"
          }
      }catch{
          case e: Exception => {e.getClass.getName}
      }
  
  }
  object QuestionEvaluator extends App {
  
      println(s"TEST-0...${driver(
        List(1, 1, 1, 7, 7, 8, 10, 10, 10, 14, 15, 18, 20, 23, 24, 24, 26, 30, 32, 32, 33, 36, 42, 43, 46, 48, 51, 51, 52, 53, 58, 58, 59, 59, 59, 60, 67, 71, 72, 74, 76, 77, 83, 84, 86, 90, 91), 30, 
        true    
      )}")   
  
  
      println(s"TEST-1...${driver(
        List(-90, -20, -60, -64, -24, 84, -2, -32, 28, -54, 44, -96, 52, 88, 20, -56, -2), 12, 
        true    
      )}")   
  
  
      println(s"TEST-2...${driver(
        List(0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1), 36, 
        false    
      )}")   
  
  
      println(s"TEST-3...${driver(
        List(98, 70, 24, 18, 7, 4, 78, 19, 70, 56, 99, 54, 69, 15, 88, 20, 40, 13, 19, 56, 62), 19, 
        true    
      )}")   
  
  
      println(s"TEST-4...${driver(
        List(-72, -66, -58, -20, 36, 80, 92), 6, 
        true    
      )}")   
  
  
      println(s"TEST-5...${driver(
        List(0, 1), 1, 
        true    
      )}")   
  
  
      println(s"TEST-6...${driver(
        List(6, 13, 14, 16, 21, 26, 26, 28, 29, 35, 38, 42, 47, 47, 62, 67, 77, 81, 81, 83, 84, 88, 90, 96, 97, 98), 17, 
        true    
      )}")   
  
  
      println(s"TEST-7...${driver(
        List(-48, -8, 20, 32, -90, -42, -6, -88, -72, 42, 66, -62, 82, -4, 8, 12, -22, 82, 56, 96, -54, 92, -42, 30, -18, 14, -6, -66, 34, 16, -84, -94, 48, -48, 52, -60, -92, -16), 35, 
        true    
      )}")   
  
  
      println(s"TEST-8...${driver(
        List(0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1), 14, 
        true    
      )}")   
  
  
      println(s"TEST-9...${driver(
        List(45, 86, 53, 80, 27, 45, 1, 85, 91, 93, 92, 43, 75, 86, 81, 48, 21, 34, 5, 10, 88, 42, 7, 15, 96, 85, 62, 86, 52, 37), 29, 
        true    
      )}")   
  
  }
  
source_py: def check_if_all_the_elements_can_be_made_of_same_parity_by_inverting_adjacent_elements(a, n):
      count_odd = 0
      count_even = 0
      for i in range(n):
          if (a[i] & 1):
              count_odd += 1
          else:
              count_even += 1
      if ((count_odd % 2) and (count_even % 2)):
          return False
      else:
          return True
source_cpp: bool check_if_all_the_elements_can_be_made_of_same_parity_by_inverting_adjacent_elements(vector<int> a, int n) {
    int count_odd = 0, count_even = 0;
    for ( int i = 0;
    i < n;
    i ++ ) {
      if ( a [ i ] & 1 ) count_odd ++;
      else count_even ++;
    }
    if ( count_odd % 2 && count_even % 2 ) return false;
    else return true;
  }