title: Program To Check If A Given Number Is Lucky All Digits Are Different
signature: pub fn program_to_check_if_a_given_number_is_lucky_all_digits_are_different(n: i32) -> i32 {
test_code: use std::collections::HashMap;
  use std::collections::HashSet;
  use std::cmp::*;
  use std::collections::*;
  use std::fmt::*; 
  
  
  // SOLUTION CODE
  // ============================================
  PLACEHOLDER_CODE_BODY
  
  // TESTING CODE 
  // ============================================
  pub fn validate_solution(actual: i32, expected: i32)->bool{
  return actual==expected
  }
  pub fn driver(n: i32, expected: i32)->String{
      if validate_solution(PLACEHOLDER_FN_NAME(n), expected) {
        return "PASSED".to_string();
      };
      return "FAILED".to_string();
  
  }
  
  fn main() {
      println!("TEST-0...{}", driver(
        474, 
        0
      ));
      
      println!("TEST-1...{}", driver(
        9445, 
        0
      ));
      
      println!("TEST-2...{}", driver(
        90, 
        0
      ));
      
      println!("TEST-3...{}", driver(
        30, 
        0
      ));
      
      println!("TEST-4...{}", driver(
        37453, 
        0
      ));
      
      println!("TEST-5...{}", driver(
        27, 
        0
      ));
      
      println!("TEST-6...{}", driver(
        2400, 
        0
      ));
      
      println!("TEST-7...{}", driver(
        98, 
        0
      ));
      
      println!("TEST-8...{}", driver(
        46, 
        0
      ));
      
      println!("TEST-9...{}", driver(
        722, 
        0
      ));
      
  }
source_py: def program_to_check_if_a_given_number_is_lucky_all_digits_are_different(n):
      ar = ([0] * 10)
      while (n > 0):
          digit = math.floor((n % 10))
          if ar[digit]:
              return 0
          ar[digit] = 1
          n = (n / 10)
      return 1
source_cpp: bool program_to_check_if_a_given_number_is_lucky_all_digits_are_different(int n) {
    bool arr [ 10 ];
    for ( int i = 0;
    i < 10;
    i ++ ) arr [ i ] = false;
    while ( n > 0 ) {
      int digit = n % 10;
      if ( arr [ digit ] ) return false;
      arr [ digit ] = true;
      n = n / 10;
    }
    return true;
  }