title: Breaking Number First Part Integral Division Second Power 10
signature: function breakingNumberFirstPartIntegralDivisionSecondPower10($n) {
test_code: <?php
  
  
  // SOLUTION CODE 
  // ============================================
  PLACEHOLDER_CODE_BODY
  
  // TESTING CODE 
  // ============================================
  function validateSolution($actual, $expected){
      return serialize($actual) == serialize($expected);
  }
  
  function driver($n, $expected){
      try{
        if (validateSolution(PLACEHOLDER_FN_NAME($n), $expected)){
          return "PASSED";
        }
        return "FAILED";
      }
      catch (Exception $exception_obj) {
        return get_class($exception_obj);
      }
  }
  
  function main(){
      printf("TEST-0...%s\n",driver(
        "ZCoQhuM", 
        0));
      
      printf("TEST-1...%s\n",driver(
        "2674377254", 
        0));
      
      printf("TEST-2...%s\n",driver(
        "11", 
        1));
      
      printf("TEST-3...%s\n",driver(
        "LbuGlvRyWAPBpo", 
        0));
      
      printf("TEST-4...%s\n",driver(
        "26382426486138", 
        0));
      
      printf("TEST-5...%s\n",driver(
        "111010111010", 
        2));
      
      printf("TEST-6...%s\n",driver(
        "hUInqJXNdbfP", 
        0));
      
      printf("TEST-7...%s\n",driver(
        "5191", 
        0));
      
      printf("TEST-8...%s\n",driver(
        "1110101101", 
        1));
      
      printf("TEST-9...%s\n",driver(
        "2202200", 
        2));
      
  }
  
  main();
  ?>
source_py: def breaking_number_first_part_integral_division_second_power_10(N):
      length = len(N)
      l = int((length / 2))
      count = 0
      for i in range((l + 1)):
          s = N[0:(0 + i)]
          l1 = len(s)
          t = N[i:(l1 + i)]
          try:
              if ((s[0] == '0') or (t[0] == '0')):
                  continue
          except:
              continue
          if (s == t):
              count += 1
      return count
source_cpp: int breaking_number_first_part_integral_division_second_power_10(string N) {
    int len = N . length ( );
    int l = ( len ) / 2;
    int count = 0;
    for ( int i = 1;
    i <= l;
    i ++ ) {
      string s = N . substr ( 0, i );
      int l1 = s . length ( );
      string t = N . substr ( i, l1 );
      if ( s [ 0 ] == '0' || t [ 0 ] == '0' ) continue;
      if ( s . compare ( t ) == 0 ) count ++;
    }
    return count;
  }