title: Ways Remove One Element Binary String Xor Becomes Zero
signature: def waysRemoveOneElementBinaryStringXorBecomesZero(str: String) = {
test_code: import scala.collection.mutable.HashMap
  import scala.collection.immutable.HashSet
  
  
  // SOLUTION CODE
  // ============================================
  PLACEHOLDER_CODE_BODY
  
  
  // TESTING CODE 
  // ============================================
  def validateSolution(actual: Int , expected: Int): Boolean = {
      actual.toString == expected.toString
  }
  
  def driver(str: String, expected: Int): String = {
      try {
          if (validateSolution(PLACEHOLDER_FN_NAME(str),expected)) {
              "PASSED"
          } else{
              "FAILED"
          }
      }catch{
          case e: Exception => {e.getClass.getName}
      }
  
  }
  object QuestionEvaluator extends App {
  
      println(s"TEST-0...${driver(
        "KfcTJNP", 
        7    
      )}")   
  
  
      println(s"TEST-1...${driver(
        "05312505872", 
        1    
      )}")   
  
  
      println(s"TEST-2...${driver(
        "100111", 
        2    
      )}")   
  
  
      println(s"TEST-3...${driver(
        "tDEEhKxrQ", 
        9    
      )}")   
  
  
      println(s"TEST-4...${driver(
        "50824233019", 
        1    
      )}")   
  
  
      println(s"TEST-5...${driver(
        "10001110010", 
        5    
      )}")   
  
  
      println(s"TEST-6...${driver(
        "T SEZaNm MYQ", 
        12    
      )}")   
  
  
      println(s"TEST-7...${driver(
        "838415739", 
        1    
      )}")   
  
  
      println(s"TEST-8...${driver(
        "01110100", 
        4    
      )}")   
  
  
      println(s"TEST-9...${driver(
        "WYQiAey H", 
        9    
      )}")   
  
  }
  
source_py: def ways_remove_one_element_binary_string_xor_becomes_zero(str):
      one_count = 0
      zero_count = 0
      n = len(str)
      for i in range(0, n, 1):
          if (str[i] == '1'):
              one_count += 1
          else:
              zero_count += 1
      if ((one_count % 2) == 0):
          return zero_count
      return one_count
source_cpp: int ways_remove_one_element_binary_string_xor_becomes_zero(string str) {
    int one_count = 0, zero_count = 0;
    int n = str . length ( );
    for ( int i = 0;
    i < n;
    i ++ ) if ( str [ i ] == '1' ) one_count ++;
    else zero_count ++;
    if ( one_count % 2 == 0 ) return zero_count;
    return one_count;
  }