title: Count Of Pairs Satisfying The Given Condition
signature: countOfPairsSatisfyingTheGivenCondition :: Integer -> Integer -> Integer
  countOfPairsSatisfyingTheGivenCondition a b = 
test_code: import Text.Printf
  import Control.Exception (catch, SomeException)
  import Data.Typeable
  import qualified Data.List as List
  import qualified Data.Map as Map
  import qualified Data.Set as Set
  
  -- SOLUTION CODE
  -- ============================================
  
  PLACEHOLDER_CODE_BODY
  
  -- TESTING CODE 
  -- ============================================
  validateSolution :: Integer -> Integer -> Bool
  validateSolution actual expected = do
      actual == expected
  
  
  driver :: Integer -> Integer -> Integer -> String
  driver a b expected = do
      if (validateSolution (PLACEHOLDER_FN_NAME a b) expected)
          then "PASSED"
      else "FAILED"
  
  main = do
      printf "TEST-0...%s\n" (driver (31) (91) (31) )
  
      printf "TEST-1...%s\n" (driver (72) (85) (72) )
  
      printf "TEST-2...%s\n" (driver (23) (49) (23) )
  
      printf "TEST-3...%s\n" (driver (42) (32) (42) )
  
      printf "TEST-4...%s\n" (driver (13) (7) (0) )
  
      printf "TEST-5...%s\n" (driver (93) (5) (0) )
  
      printf "TEST-6...%s\n" (driver (33) (32) (33) )
  
      printf "TEST-7...%s\n" (driver (94) (76) (94) )
  
      printf "TEST-8...%s\n" (driver (60) (60) (60) )
  
      printf "TEST-9...%s\n" (driver (11) (26) (11) )
  
source_py: def count_of_pairs_satisfying_the_given_condition(a, b):
      s = str(b)
      i = 0
      while (i < len(s)):
          if (s[i] != '9'):
              break
          i += 1
      result = 0
      if (i == len(s)):
          result = (a * len(s))
      else:
          result = (a * (len(s) - 1))
      return result
source_cpp: int count_of_pairs_satisfying_the_given_condition(int a, int b) {
    string s = to_string ( b );
    int i;
    for ( i = 0;
    i < s . length ( );
    i ++ ) {
      if ( s [ i ] != '9' ) break;
    }
    int result;
    if ( i == s . length ( ) ) result = a * s . length ( );
    else result = a * ( s . length ( ) - 1 );
    return result;
  }