title: Middle Of Three Using Minimum Comparisons 2
signature: function middle_of_three_using_minimum_comparisons_2(a, b, c)
test_code: using Printf
  
  # SOLUTION CODE
  # ============================================
  PLACEHOLDER_CODE_BODY
  
  # TESTING CODE 
  # ============================================
  function validate_solution(actual, expected)
      return actual == expected
  end
  
  function driver(a, b, c, expected)
      try
  
          if validate_solution(PLACEHOLDER_FN_NAME(a, b, c), expected)
              return "PASSED";
          end
          return "FAILED";
      catch exception_obj
          return string(Base.typename(typeof(exception_obj)).wrapper);
      end
  end
  
  function main()
      
      result = driver(48, 46, 38, 46);
      @printf("TEST-0...%s\n",result);
      
      result = driver(93, 34, 11, 34);
      @printf("TEST-1...%s\n",result);
      
      result = driver(58, 78, 6, 58);
      @printf("TEST-2...%s\n",result);
      
      result = driver(13, 3, 23, 13);
      @printf("TEST-3...%s\n",result);
      
  end
  
  main()
source_py: def middle_of_three_using_minimum_comparisons_2(a, b, c):
      x = (a - b)
      y = (b - c)
      z = (a - c)
      if ((x * y) > 0):
          return b
      elif ((x * z) > 0):
          return
      else:
          return a
source_cpp: int middle_of_three_using_minimum_comparisons_2(int a, int b, int c) {
    int x = a - b;
    int y = b - c;
    int z = a - c;
    if ( x * y > 0 ) return b;
    else if ( x * z > 0 ) return c;
    else return a;
  }