title: Count Possible Paths Top Left Bottom Right Nxm Matrix 2
signature: long long countPossiblePathsTopLeftBottomRightNxmMatrix2(int p, int q) {
test_code: #include <algorithm>
  #include <assert.h>
  #include <cstdlib>
  #include <iostream>
  #include <map>
  #include <set>
  #include <string>
  #include <tuple> 
  #include <unordered_map>
  #include <vector>
  #include <math.h>
  #include <cmath>
  #include <bits/stdc++.h>
  #include <numeric>
  #include <functional>
  
  using namespace std;
  
  // SOLUTION CODE
  // ============================================
  PLACEHOLDER_CODE_BODY
  
  // TESTING CODE 
  // ============================================
  bool validateSolution(long long actual, long long expected){
      return actual == expected;
  }
  
  string driver(int p, int q, long long expected){
      try
      {
          if (validateSolution(PLACEHOLDER_FN_NAME(p, q), expected)){
              return "PASSED";
          }
          return "FAILED";
      }
      catch (const std::overflow_error& exception_obj)
      {
          return typeid(exception_obj).name();
      }
      catch (const std::runtime_error& exception_obj)
      {
          return typeid(exception_obj).name();
      }
      catch (const std::exception& exception_obj)
      {
          return typeid(exception_obj).name();
      }
      catch (...)
      {
          return "UNK_ERROR";
      }
  }
  
  int main() {
      string result = "";
  
      result = driver(70, 5, 1088430); 
      cout << "TEST-" << 0 << "..."
           <<  result
           << "\n";
  
      result = driver(9, 59, 5743572120); 
      cout << "TEST-" << 1 << "..."
           <<  result
           << "\n";
  
      result = driver(54, 1, 1); 
      cout << "TEST-" << 2 << "..."
           <<  result
           << "\n";
  
      return 0;
  }
source_py: def count_possible_paths_top_left_bottom_right_nxm_matrix_2(p, q):
      dp = [1 for i in range(q)]
      for i in range((p - 1)):
          for j in range(1, q):
              dp[j] += dp[(j - 1)]
      return dp[(q - 1)]
source_cpp: int count_possible_paths_top_left_bottom_right_nxm_matrix_2(int m, int n) {
    int dp [ n ] = {
      1 };
      dp [ 0 ] = 1;
      for ( int i = 0;
      i < m;
      i ++ ) {
        for ( int j = 1;
        j < n;
        j ++ ) {
          dp [ j ] += dp [ j - 1 ];
        }
      }
      return dp [ n - 1 ];
    }