title: Count Of Occurrences Of A 101 Pattern In A String
signature: function count_of_occurrences_of_a_101_pattern_in_a_string(s)
test_code: using Printf
  
  # SOLUTION CODE
  # ============================================
  PLACEHOLDER_CODE_BODY
  
  # TESTING CODE 
  # ============================================
  function validate_solution(actual, expected)
      return actual == expected
  end
  
  function driver(s, expected)
      try
  
          if validate_solution(PLACEHOLDER_FN_NAME(s), expected)
              return "PASSED";
          end
          return "FAILED";
      catch exception_obj
          return string(Base.typename(typeof(exception_obj)).wrapper);
      end
  end
  
  function main()
      
      result = driver("1001ab010abc01001", 2);
      @printf("TEST-0...%s\n",result);
      
      result = driver("1001010001", 3);
      @printf("TEST-1...%s\n",result);
      
      result = driver("010100010100", 3);
      @printf("TEST-2...%s\n",result);
      
      result = driver("DLCu", 0);
      @printf("TEST-3...%s\n",result);
      
      result = driver("7072430592", 0);
      @printf("TEST-4...%s\n",result);
      
      result = driver("011", 0);
      @printf("TEST-5...%s\n",result);
      
      result = driver("pnJpypYOza", 0);
      @printf("TEST-6...%s\n",result);
      
      result = driver("1037", 0);
      @printf("TEST-7...%s\n",result);
      
      result = driver("111", 0);
      @printf("TEST-8...%s\n",result);
      
      result = driver("HxK", 0);
      @printf("TEST-9...%s\n",result);
      
  end
  
  main()
source_py: def count_of_occurrences_of_a_101_pattern_in_a_string(s):
      length = len(s)
      oneSeen = False
      count = 0
      for i in range(length):
          if ((s[i] == '1') and oneSeen):
              if (s[(i - 1)] == '0'):
                  count += 1
          if ((s[i] == '1') and (oneSeen == 0)):
              oneSeen = True
          if ((s[i] != '0') and (s[i] != '1')):
              oneSeen = False
      return count
source_cpp: int count_of_occurrences_of_a_101_pattern_in_a_string(string str) {
    int len = str . size ( );
    bool oneSeen = 0;
    int count = 0;
    for ( int i = 0;
    i < len;
    i ++ ) {
      if ( str [ i ] == '1' && oneSeen == 1 ) if ( str [ i - 1 ] == '0' ) count ++;
      if ( str [ i ] == '1' && oneSeen == 0 ) {
        oneSeen = 1;
        continue;
      }
      if ( str [ i ] != '0' && str [ i ] != '1' ) oneSeen = 0;
    }
    return count;
  }