title: Number Of Substrings With Odd Decimal Value In A Binary String
signature: func numberOfSubstringsWithOddDecimalValueInABinaryString(s string) int {
test_code: package main
  
  import (
      "fmt"
      "reflect"
      "math"
      "sort"
  )
  
  // SOLUTION CODE
  // ===================================
  PLACEHOLDER_CODE_BODY
  
  // TESTING CODE
  // ===================================
  func validateSolution(actual int, expected int) bool {
      return reflect.DeepEqual(actual,expected)
  }
  
  func driver(s string, expected int) string {
      if validateSolution(PLACEHOLDER_FN_NAME(s),expected) {
              return "PASSED"
      }
      return "FAILED"
  
  }
  
  func main() {
  
      // Use imports to avoid undefined errors
      var _ = reflect.DeepEqual
      _ = math.Abs
      _ = sort.Sort
      result := ""
      result = driver("OGiOkJF", 0)
      fmt.Printf("TEST-0...%s\n", result)
      
      result = driver("517376", 1)
      fmt.Printf("TEST-1...%s\n", result)
      
      result = driver("11", 3)
      fmt.Printf("TEST-2...%s\n", result)
      
      result = driver("Ze", 0)
      fmt.Printf("TEST-3...%s\n", result)
      
      result = driver("8763644247018", 1)
      fmt.Printf("TEST-4...%s\n", result)
      
      result = driver("00111010001", 15)
      fmt.Printf("TEST-5...%s\n", result)
      
      result = driver("HGwkBKUOVu", 0)
      fmt.Printf("TEST-6...%s\n", result)
      
      result = driver("652", 0)
      fmt.Printf("TEST-7...%s\n", result)
      
      result = driver("101000011110", 21)
      fmt.Printf("TEST-8...%s\n", result)
      
      result = driver("kvdpG ", 0)
      fmt.Printf("TEST-9...%s\n", result)
      
          
  }
source_py: def number_of_substrings_with_odd_decimal_value_in_a_binary_string(s):
      n = len(s)
      auxArr = [0 for i in range(n)]
      if (s[0] == '1'):
          auxArr[0] = 1
      for i in range(0, n):
          if (s[i] == '1'):
              auxArr[i] = (auxArr[(i - 1)] + 1)
          else:
              auxArr[i] = auxArr[(i - 1)]
      count = 0
      for i in range((n - 1), (- 1), (- 1)):
          if (s[i] == '1'):
              count += auxArr[i]
      return count
source_cpp: int number_of_substrings_with_odd_decimal_value_in_a_binary_string(string s) {
    int n = s . length ( );
    int auxArr [ n ] = {
      0 };
      if ( s [ 0 ] == '1' ) auxArr [ 0 ] = 1;
      for ( int i = 1;
      i < n;
      i ++ ) {
        if ( s [ i ] == '1' ) auxArr [ i ] = auxArr [ i - 1 ] + 1;
        else auxArr [ i ] = auxArr [ i - 1 ];
      }
      int count = 0;
      for ( int i = n - 1;
      i >= 0;
      i -- ) if ( s [ i ] == '1' ) count += auxArr [ i ];
      return count;
    }