title: Number Of Binary Trees For Given Preorder Sequence Length
signature: class Solution {
  
      public Integer numberOfBinaryTreesForGivenPreorderSequenceLength(Integer n) {
test_code: import static java.util.Map.entry;  
  import java.util.*;
  import java.lang.*;
  // TESTING CODE 
  // ============================================
  class QuestionEvaluator {
      public static String validateSolution(Integer n, Integer expected){
          try{
              Driver driver = new Driver();
              if (driver.run(n,expected)){
                  return "PASSED";
              }
              return "FAILED";
              
          } catch (Exception exception_obj){
              return exception_obj.getClass().getSimpleName();
          }
  
      }
      public static void main(String[] args) {
          String result;
          result = validateSolution(15, 9694845);
          System.out.println(String.format("%s%s","TEST-0...",result));    
      
          result = validateSolution(11, 58786);
          System.out.println(String.format("%s%s","TEST-1...",result));    
      
          result = validateSolution(11, 58786);
          System.out.println(String.format("%s%s","TEST-2...",result));    
      
          result = validateSolution(15, 9694845);
          System.out.println(String.format("%s%s","TEST-3...",result));    
      
      }
  }
  
  class Driver{
      public boolean run(Integer n, Integer expected){
  
          PLACEHOLDER_CLS_NAME sol = new PLACEHOLDER_CLS_NAME();
          return validateSolution(sol.PLACEHOLDER_FN_NAME(n),expected);
      }
      
      public boolean validateSolution(Integer actual, Integer expected){
          return actual.equals(expected);
      }
  }
  
  
  // SOLUTION CODE
  // ============================================
  PLACEHOLDER_CODE_BODY
source_py: def number_of_binary_trees_for_given_preorder_sequence_length(n):
      BT = ([0] * (n + 1))
      BT[0] = BT[1] = 1
      for i in range(2, (n + 1)):
          for j in range(i):
              BT[i] += (BT[j] * BT[((i - j) - 1)])
      return BT[n]
source_cpp: int number_of_binary_trees_for_given_preorder_sequence_length(int n) {
    int BT [ n + 1 ];
    memset ( BT, 0, sizeof ( BT ) );
    BT [ 0 ] = BT [ 1 ] = 1;
    for ( int i = 2;
    i <= n;
    ++ i ) for ( int j = 0;
    j < i;
    j ++ ) BT [ i ] += BT [ j ] * BT [ i - j - 1 ];
    return BT [ n ];
  }