title: Round The Given Number To Nearest Multiple Of 10
signature: function roundTheGivenNumberToNearestMultipleOf10($n) {
test_code: <?php
  
  
  // SOLUTION CODE 
  // ============================================
  PLACEHOLDER_CODE_BODY
  
  // TESTING CODE 
  // ============================================
  function validateSolution($actual, $expected){
      return serialize($actual) == serialize($expected);
  }
  
  function driver($n, $expected){
      try{
        if (validateSolution(PLACEHOLDER_FN_NAME($n), $expected)){
          return "PASSED";
        }
        return "FAILED";
      }
      catch (Exception $exception_obj) {
        return get_class($exception_obj);
      }
  }
  
  function main(){
      printf("TEST-0...%s\n",driver(
        31, 
        30));
      
      printf("TEST-1...%s\n",driver(
        78, 
        80));
      
      printf("TEST-2...%s\n",driver(
        19, 
        20));
      
      printf("TEST-3...%s\n",driver(
        36, 
        40));
      
      printf("TEST-4...%s\n",driver(
        77, 
        80));
      
      printf("TEST-5...%s\n",driver(
        94, 
        90));
      
      printf("TEST-6...%s\n",driver(
        86, 
        90));
      
      printf("TEST-7...%s\n",driver(
        16, 
        20));
      
      printf("TEST-8...%s\n",driver(
        95, 
        90));
      
      printf("TEST-9...%s\n",driver(
        2, 
        0));
      
  }
  
  main();
  ?>
source_py: def round_the_given_number_to_nearest_multiple_of_10(n):
      a = ((n // 10) * 10)
      b = (a + 10)
      return (b if ((n - a) > (b - n)) else a)
source_cpp: int round_the_given_number_to_nearest_multiple_of_10(int n) {
    int a = ( n / 10 ) * 10;
    int b = a + 10;
    return ( n - a > b - n ) ? b : a;
  }