title: Number Of Substrings With Odd Decimal Value In A Binary String
signature: pub fn number_of_substrings_with_odd_decimal_value_in_a_binary_string(s: String) -> i32 {
test_code: use std::collections::HashMap;
  use std::collections::HashSet;
  use std::cmp::*;
  use std::collections::*;
  use std::fmt::*; 
  
  
  // SOLUTION CODE
  // ============================================
  PLACEHOLDER_CODE_BODY
  
  // TESTING CODE 
  // ============================================
  pub fn validate_solution(actual: i32, expected: i32)->bool{
  return actual==expected
  }
  pub fn driver(s: String, expected: i32)->String{
      if validate_solution(PLACEHOLDER_FN_NAME(s), expected) {
        return "PASSED".to_string();
      };
      return "FAILED".to_string();
  
  }
  
  fn main() {
      println!("TEST-0...{}", driver(
        "OGiOkJF".to_string(), 
        0
      ));
      
      println!("TEST-1...{}", driver(
        "517376".to_string(), 
        1
      ));
      
      println!("TEST-2...{}", driver(
        "11".to_string(), 
        3
      ));
      
      println!("TEST-3...{}", driver(
        "Ze".to_string(), 
        0
      ));
      
      println!("TEST-4...{}", driver(
        "8763644247018".to_string(), 
        1
      ));
      
      println!("TEST-5...{}", driver(
        "00111010001".to_string(), 
        15
      ));
      
      println!("TEST-6...{}", driver(
        "HGwkBKUOVu".to_string(), 
        0
      ));
      
      println!("TEST-7...{}", driver(
        "652".to_string(), 
        0
      ));
      
      println!("TEST-8...{}", driver(
        "101000011110".to_string(), 
        21
      ));
      
      println!("TEST-9...{}", driver(
        "kvdpG ".to_string(), 
        0
      ));
      
  }
source_py: def number_of_substrings_with_odd_decimal_value_in_a_binary_string(s):
      n = len(s)
      auxArr = [0 for i in range(n)]
      if (s[0] == '1'):
          auxArr[0] = 1
      for i in range(0, n):
          if (s[i] == '1'):
              auxArr[i] = (auxArr[(i - 1)] + 1)
          else:
              auxArr[i] = auxArr[(i - 1)]
      count = 0
      for i in range((n - 1), (- 1), (- 1)):
          if (s[i] == '1'):
              count += auxArr[i]
      return count
source_cpp: int number_of_substrings_with_odd_decimal_value_in_a_binary_string(string s) {
    int n = s . length ( );
    int auxArr [ n ] = {
      0 };
      if ( s [ 0 ] == '1' ) auxArr [ 0 ] = 1;
      for ( int i = 1;
      i < n;
      i ++ ) {
        if ( s [ i ] == '1' ) auxArr [ i ] = auxArr [ i - 1 ] + 1;
        else auxArr [ i ] = auxArr [ i - 1 ];
      }
      int count = 0;
      for ( int i = n - 1;
      i >= 0;
      i -- ) if ( s [ i ] == '1' ) count += auxArr [ i ];
      return count;
    }