title: Next Power Of 2 2
signature: nextPowerOf22 :: Integer -> Integer
  nextPowerOf22 n = 
test_code: import Text.Printf
  import Control.Exception (catch, SomeException)
  import Data.Typeable
  import qualified Data.List as List
  import qualified Data.Map as Map
  import qualified Data.Set as Set
  
  -- SOLUTION CODE
  -- ============================================
  
  PLACEHOLDER_CODE_BODY
  
  -- TESTING CODE 
  -- ============================================
  validateSolution :: Integer -> Integer -> Bool
  validateSolution actual expected = do
      actual == expected
  
  
  driver :: Integer -> Integer -> String
  driver n expected = do
      if (validateSolution (PLACEHOLDER_FN_NAME n) expected)
          then "PASSED"
      else "FAILED"
  
  main = do
      printf "TEST-0...%s\n" (driver (63) (64) )
  
      printf "TEST-1...%s\n" (driver (78) (128) )
  
      printf "TEST-2...%s\n" (driver (13) (16) )
  
      printf "TEST-3...%s\n" (driver (5) (8) )
  
      printf "TEST-4...%s\n" (driver (34) (64) )
  
      printf "TEST-5...%s\n" (driver (69) (128) )
  
      printf "TEST-6...%s\n" (driver (63) (64) )
  
      printf "TEST-7...%s\n" (driver (78) (128) )
  
      printf "TEST-8...%s\n" (driver (80) (128) )
  
      printf "TEST-9...%s\n" (driver (19) (32) )
  
source_py: def next_power_of_2_2(n):
      n -= 1
      n |= (n >> 1)
      n |= (n >> 2)
      n |= (n >> 4)
      n |= (n >> 8)
      n |= (n >> 16)
      n += 1
      return n
source_cpp: unsigned int next_power_of_2_2(unsigned int n) {
    n --;
    n |= n >> 1;
    n |= n >> 2;
    n |= n >> 4;
    n |= n >> 8;
    n |= n >> 16;
    n ++;
    return n;
  }