title: Number Of Substrings With Odd Decimal Value In A Binary String
signature: function number_of_substrings_with_odd_decimal_value_in_a_binary_string(s)
test_code: using Printf
  
  # SOLUTION CODE
  # ============================================
  PLACEHOLDER_CODE_BODY
  
  # TESTING CODE 
  # ============================================
  function validate_solution(actual, expected)
      return actual == expected
  end
  
  function driver(s, expected)
      try
  
          if validate_solution(PLACEHOLDER_FN_NAME(s), expected)
              return "PASSED";
          end
          return "FAILED";
      catch exception_obj
          return string(Base.typename(typeof(exception_obj)).wrapper);
      end
  end
  
  function main()
      
      result = driver("OGiOkJF", 0);
      @printf("TEST-0...%s\n",result);
      
      result = driver("517376", 1);
      @printf("TEST-1...%s\n",result);
      
      result = driver("11", 3);
      @printf("TEST-2...%s\n",result);
      
      result = driver("Ze", 0);
      @printf("TEST-3...%s\n",result);
      
      result = driver("8763644247018", 1);
      @printf("TEST-4...%s\n",result);
      
      result = driver("00111010001", 15);
      @printf("TEST-5...%s\n",result);
      
      result = driver("HGwkBKUOVu", 0);
      @printf("TEST-6...%s\n",result);
      
      result = driver("652", 0);
      @printf("TEST-7...%s\n",result);
      
      result = driver("101000011110", 21);
      @printf("TEST-8...%s\n",result);
      
      result = driver("kvdpG ", 0);
      @printf("TEST-9...%s\n",result);
      
  end
  
  main()
source_py: def number_of_substrings_with_odd_decimal_value_in_a_binary_string(s):
      n = len(s)
      auxArr = [0 for i in range(n)]
      if (s[0] == '1'):
          auxArr[0] = 1
      for i in range(0, n):
          if (s[i] == '1'):
              auxArr[i] = (auxArr[(i - 1)] + 1)
          else:
              auxArr[i] = auxArr[(i - 1)]
      count = 0
      for i in range((n - 1), (- 1), (- 1)):
          if (s[i] == '1'):
              count += auxArr[i]
      return count
source_cpp: int number_of_substrings_with_odd_decimal_value_in_a_binary_string(string s) {
    int n = s . length ( );
    int auxArr [ n ] = {
      0 };
      if ( s [ 0 ] == '1' ) auxArr [ 0 ] = 1;
      for ( int i = 1;
      i < n;
      i ++ ) {
        if ( s [ i ] == '1' ) auxArr [ i ] = auxArr [ i - 1 ] + 1;
        else auxArr [ i ] = auxArr [ i - 1 ];
      }
      int count = 0;
      for ( int i = n - 1;
      i >= 0;
      i -- ) if ( s [ i ] == '1' ) count += auxArr [ i ];
      return count;
    }