title: Program To Check If A Given Number Is Lucky All Digits Are Different
signature: function programToCheckIfAGivenNumberIsLuckyAllDigitsAreDifferent($n) {
test_code: <?php
  
  
  // SOLUTION CODE 
  // ============================================
  PLACEHOLDER_CODE_BODY
  
  // TESTING CODE 
  // ============================================
  function validateSolution($actual, $expected){
      return serialize($actual) == serialize($expected);
  }
  
  function driver($n, $expected){
      try{
        if (validateSolution(PLACEHOLDER_FN_NAME($n), $expected)){
          return "PASSED";
        }
        return "FAILED";
      }
      catch (Exception $exception_obj) {
        return get_class($exception_obj);
      }
  }
  
  function main(){
      printf("TEST-0...%s\n",driver(
        474, 
        0));
      
      printf("TEST-1...%s\n",driver(
        9445, 
        0));
      
      printf("TEST-2...%s\n",driver(
        90, 
        0));
      
      printf("TEST-3...%s\n",driver(
        30, 
        0));
      
      printf("TEST-4...%s\n",driver(
        37453, 
        0));
      
      printf("TEST-5...%s\n",driver(
        27, 
        0));
      
      printf("TEST-6...%s\n",driver(
        2400, 
        0));
      
      printf("TEST-7...%s\n",driver(
        98, 
        0));
      
      printf("TEST-8...%s\n",driver(
        46, 
        0));
      
      printf("TEST-9...%s\n",driver(
        722, 
        0));
      
  }
  
  main();
  ?>
source_py: def program_to_check_if_a_given_number_is_lucky_all_digits_are_different(n):
      ar = ([0] * 10)
      while (n > 0):
          digit = math.floor((n % 10))
          if ar[digit]:
              return 0
          ar[digit] = 1
          n = (n / 10)
      return 1
source_cpp: bool program_to_check_if_a_given_number_is_lucky_all_digits_are_different(int n) {
    bool arr [ 10 ];
    for ( int i = 0;
    i < 10;
    i ++ ) arr [ i ] = false;
    while ( n > 0 ) {
      int digit = n % 10;
      if ( arr [ digit ] ) return false;
      arr [ digit ] = true;
      n = n / 10;
    }
    return true;
  }