title: Count Of Occurrences Of A 101 Pattern In A String
signature: countOfOccurrencesOfA101PatternInAString :: String -> Integer
  countOfOccurrencesOfA101PatternInAString s = 
test_code: import Text.Printf
  import Control.Exception (catch, SomeException)
  import Data.Typeable
  import qualified Data.List as List
  import qualified Data.Map as Map
  import qualified Data.Set as Set
  
  -- SOLUTION CODE
  -- ============================================
  
  PLACEHOLDER_CODE_BODY
  
  -- TESTING CODE 
  -- ============================================
  validateSolution :: Integer -> Integer -> Bool
  validateSolution actual expected = do
      actual == expected
  
  
  driver :: String -> Integer -> String
  driver s expected = do
      if (validateSolution (PLACEHOLDER_FN_NAME s) expected)
          then "PASSED"
      else "FAILED"
  
  main = do
      printf "TEST-0...%s\n" (driver ("1001ab010abc01001") (2) )
  
      printf "TEST-1...%s\n" (driver ("1001010001") (3) )
  
      printf "TEST-2...%s\n" (driver ("010100010100") (3) )
  
      printf "TEST-3...%s\n" (driver ("DLCu") (0) )
  
      printf "TEST-4...%s\n" (driver ("7072430592") (0) )
  
      printf "TEST-5...%s\n" (driver ("011") (0) )
  
      printf "TEST-6...%s\n" (driver ("pnJpypYOza") (0) )
  
      printf "TEST-7...%s\n" (driver ("1037") (0) )
  
      printf "TEST-8...%s\n" (driver ("111") (0) )
  
      printf "TEST-9...%s\n" (driver ("HxK") (0) )
  
source_py: def count_of_occurrences_of_a_101_pattern_in_a_string(s):
      length = len(s)
      oneSeen = False
      count = 0
      for i in range(length):
          if ((s[i] == '1') and oneSeen):
              if (s[(i - 1)] == '0'):
                  count += 1
          if ((s[i] == '1') and (oneSeen == 0)):
              oneSeen = True
          if ((s[i] != '0') and (s[i] != '1')):
              oneSeen = False
      return count
source_cpp: int count_of_occurrences_of_a_101_pattern_in_a_string(string str) {
    int len = str . size ( );
    bool oneSeen = 0;
    int count = 0;
    for ( int i = 0;
    i < len;
    i ++ ) {
      if ( str [ i ] == '1' && oneSeen == 1 ) if ( str [ i - 1 ] == '0' ) count ++;
      if ( str [ i ] == '1' && oneSeen == 0 ) {
        oneSeen = 1;
        continue;
      }
      if ( str [ i ] != '0' && str [ i ] != '1' ) oneSeen = 0;
    }
    return count;
  }