title: Round The Given Number To Nearest Multiple Of 10
signature: roundTheGivenNumberToNearestMultipleOf10(n) {
test_code: import 'dart:convert';
  
  // SOLUTION CODE
  // ============================================
  PLACEHOLDER_CODE_BODY
  
  // TESTING CODE 
  // ============================================
  bool validateSolution(int actual, int expected){
      return actual.toString() == expected.toString();
  }
  
  String driver(n, int expected){
      try
      {
          if (validateSolution(PLACEHOLDER_FN_NAME(n), expected)){
              return "PASSED";
          }
          return "FAILED";
      }catch(exception_object){
          return exception_object.runtimeType.toString();
      }
  }
  
  int main() {
  
      print("TEST-0...${driver(
          31, 
          30)
      }");
  
      print("TEST-1...${driver(
          78, 
          80)
      }");
  
      print("TEST-2...${driver(
          19, 
          20)
      }");
  
      print("TEST-3...${driver(
          36, 
          40)
      }");
  
      print("TEST-4...${driver(
          77, 
          80)
      }");
  
      print("TEST-5...${driver(
          94, 
          90)
      }");
  
      print("TEST-6...${driver(
          86, 
          90)
      }");
  
      print("TEST-7...${driver(
          16, 
          20)
      }");
  
      print("TEST-8...${driver(
          95, 
          90)
      }");
  
      print("TEST-9...${driver(
          2, 
          0)
      }");
  
      return 0;
  }
source_py: def round_the_given_number_to_nearest_multiple_of_10(n):
      a = ((n // 10) * 10)
      b = (a + 10)
      return (b if ((n - a) > (b - n)) else a)
source_cpp: int round_the_given_number_to_nearest_multiple_of_10(int n) {
    int a = ( n / 10 ) * 10;
    int b = a + 10;
    return ( n - a > b - n ) ? b : a;
  }