title: Number Of Substrings With Odd Decimal Value In A Binary String
signature: def numberOfSubstringsWithOddDecimalValueInABinaryString(s: String) = {
test_code: import scala.collection.mutable.HashMap
  import scala.collection.immutable.HashSet
  
  
  // SOLUTION CODE
  // ============================================
  PLACEHOLDER_CODE_BODY
  
  
  // TESTING CODE 
  // ============================================
  def validateSolution(actual: Int , expected: Int): Boolean = {
      actual.toString == expected.toString
  }
  
  def driver(s: String, expected: Int): String = {
      try {
          if (validateSolution(PLACEHOLDER_FN_NAME(s),expected)) {
              "PASSED"
          } else{
              "FAILED"
          }
      }catch{
          case e: Exception => {e.getClass.getName}
      }
  
  }
  object QuestionEvaluator extends App {
  
      println(s"TEST-0...${driver(
        "OGiOkJF", 
        0    
      )}")   
  
  
      println(s"TEST-1...${driver(
        "517376", 
        1    
      )}")   
  
  
      println(s"TEST-2...${driver(
        "11", 
        3    
      )}")   
  
  
      println(s"TEST-3...${driver(
        "Ze", 
        0    
      )}")   
  
  
      println(s"TEST-4...${driver(
        "8763644247018", 
        1    
      )}")   
  
  
      println(s"TEST-5...${driver(
        "00111010001", 
        15    
      )}")   
  
  
      println(s"TEST-6...${driver(
        "HGwkBKUOVu", 
        0    
      )}")   
  
  
      println(s"TEST-7...${driver(
        "652", 
        0    
      )}")   
  
  
      println(s"TEST-8...${driver(
        "101000011110", 
        21    
      )}")   
  
  
      println(s"TEST-9...${driver(
        "kvdpG ", 
        0    
      )}")   
  
  }
  
source_py: def number_of_substrings_with_odd_decimal_value_in_a_binary_string(s):
      n = len(s)
      auxArr = [0 for i in range(n)]
      if (s[0] == '1'):
          auxArr[0] = 1
      for i in range(0, n):
          if (s[i] == '1'):
              auxArr[i] = (auxArr[(i - 1)] + 1)
          else:
              auxArr[i] = auxArr[(i - 1)]
      count = 0
      for i in range((n - 1), (- 1), (- 1)):
          if (s[i] == '1'):
              count += auxArr[i]
      return count
source_cpp: int number_of_substrings_with_odd_decimal_value_in_a_binary_string(string s) {
    int n = s . length ( );
    int auxArr [ n ] = {
      0 };
      if ( s [ 0 ] == '1' ) auxArr [ 0 ] = 1;
      for ( int i = 1;
      i < n;
      i ++ ) {
        if ( s [ i ] == '1' ) auxArr [ i ] = auxArr [ i - 1 ] + 1;
        else auxArr [ i ] = auxArr [ i - 1 ];
      }
      int count = 0;
      for ( int i = n - 1;
      i >= 0;
      i -- ) if ( s [ i ] == '1' ) count += auxArr [ i ];
      return count;
    }