title: Count Obtuse Angles Circle K Equidistant Points 2 Given Points
signature: countObtuseAnglesCircleKEquidistantPoints2GivenPoints(a, b, k) {
test_code: import 'dart:convert';
  
  // SOLUTION CODE
  // ============================================
  PLACEHOLDER_CODE_BODY
  
  // TESTING CODE 
  // ============================================
  bool validateSolution(int actual, int expected){
      return actual.toString() == expected.toString();
  }
  
  String driver(a, b, k, int expected){
      try
      {
          if (validateSolution(PLACEHOLDER_FN_NAME(a, b, k), expected)){
              return "PASSED";
          }
          return "FAILED";
      }catch(exception_object){
          return exception_object.runtimeType.toString();
      }
  }
  
  int main() {
  
      print("TEST-0...${driver(
          83, 98, 86, 
          14)
      }");
  
      print("TEST-1...${driver(
          3, 39, 87, 
          35)
      }");
  
      print("TEST-2...${driver(
          11, 96, 30, 
          -56)
      }");
  
      print("TEST-3...${driver(
          50, 67, 48, 
          16)
      }");
  
      print("TEST-4...${driver(
          40, 16, 32, 
          -25)
      }");
  
      print("TEST-5...${driver(
          62, 86, 76, 
          23)
      }");
  
      print("TEST-6...${driver(
          40, 78, 71, 
          32)
      }");
  
      print("TEST-7...${driver(
          66, 11, 74, 
          -56)
      }");
  
      print("TEST-8...${driver(
          6, 9, 19, 
          2)
      }");
  
      print("TEST-9...${driver(
          25, 5, 5, 
          -21)
      }");
  
      return 0;
  }
source_py: def count_obtuse_angles_circle_k_equidistant_points_2_given_points(a, b, k):
      c1 = ((b - a) - 1)
      c2 = ((k - b) + (a - 1))
      if (c1 == c2):
          return 0
      return min(c1, c2)
source_cpp: int count_obtuse_angles_circle_k_equidistant_points_2_given_points(int a, int b, int k) {
    int c1 = ( b - a ) - 1;
    int c2 = ( k - b ) + ( a - 1 );
    if ( c1 == c2 ) return 0;
    return min ( c1, c2 );
  }