title: Count Of Occurrences Of A 101 Pattern In A String
signature: func countOfOccurrencesOfA101PatternInAString(s string) int {
test_code: package main
  
  import (
      "fmt"
      "reflect"
      "math"
      "sort"
  )
  
  // SOLUTION CODE
  // ===================================
  PLACEHOLDER_CODE_BODY
  
  // TESTING CODE
  // ===================================
  func validateSolution(actual int, expected int) bool {
      return reflect.DeepEqual(actual,expected)
  }
  
  func driver(s string, expected int) string {
      if validateSolution(PLACEHOLDER_FN_NAME(s),expected) {
              return "PASSED"
      }
      return "FAILED"
  
  }
  
  func main() {
  
      // Use imports to avoid undefined errors
      var _ = reflect.DeepEqual
      _ = math.Abs
      _ = sort.Sort
      result := ""
      result = driver("1001ab010abc01001", 2)
      fmt.Printf("TEST-0...%s\n", result)
      
      result = driver("1001010001", 3)
      fmt.Printf("TEST-1...%s\n", result)
      
      result = driver("010100010100", 3)
      fmt.Printf("TEST-2...%s\n", result)
      
      result = driver("DLCu", 0)
      fmt.Printf("TEST-3...%s\n", result)
      
      result = driver("7072430592", 0)
      fmt.Printf("TEST-4...%s\n", result)
      
      result = driver("011", 0)
      fmt.Printf("TEST-5...%s\n", result)
      
      result = driver("pnJpypYOza", 0)
      fmt.Printf("TEST-6...%s\n", result)
      
      result = driver("1037", 0)
      fmt.Printf("TEST-7...%s\n", result)
      
      result = driver("111", 0)
      fmt.Printf("TEST-8...%s\n", result)
      
      result = driver("HxK", 0)
      fmt.Printf("TEST-9...%s\n", result)
      
          
  }
source_py: def count_of_occurrences_of_a_101_pattern_in_a_string(s):
      length = len(s)
      oneSeen = False
      count = 0
      for i in range(length):
          if ((s[i] == '1') and oneSeen):
              if (s[(i - 1)] == '0'):
                  count += 1
          if ((s[i] == '1') and (oneSeen == 0)):
              oneSeen = True
          if ((s[i] != '0') and (s[i] != '1')):
              oneSeen = False
      return count
source_cpp: int count_of_occurrences_of_a_101_pattern_in_a_string(string str) {
    int len = str . size ( );
    bool oneSeen = 0;
    int count = 0;
    for ( int i = 0;
    i < len;
    i ++ ) {
      if ( str [ i ] == '1' && oneSeen == 1 ) if ( str [ i - 1 ] == '0' ) count ++;
      if ( str [ i ] == '1' && oneSeen == 0 ) {
        oneSeen = 1;
        continue;
      }
      if ( str [ i ] != '0' && str [ i ] != '1' ) oneSeen = 0;
    }
    return count;
  }