title: Write An Efficient Method To Check If A Number Is Multiple Of 3
signature: func writeAnEfficientMethodToCheckIfANumberIsMultipleOf3(n int) int {
test_code: package main
  
  import (
      "fmt"
      "reflect"
      "math"
      "sort"
  )
  
  // SOLUTION CODE
  // ===================================
  PLACEHOLDER_CODE_BODY
  
  // TESTING CODE
  // ===================================
  func validateSolution(actual int, expected int) bool {
      return reflect.DeepEqual(actual,expected)
  }
  
  func driver(n int, expected int) string {
      if validateSolution(PLACEHOLDER_FN_NAME(n),expected) {
              return "PASSED"
      }
      return "FAILED"
  
  }
  
  func main() {
  
      // Use imports to avoid undefined errors
      var _ = reflect.DeepEqual
      _ = math.Abs
      _ = sort.Sort
      result := ""
      result = driver(94, 0)
      fmt.Printf("TEST-0...%s\n", result)
      
      result = driver(94, 0)
      fmt.Printf("TEST-1...%s\n", result)
      
      result = driver(79, 0)
      fmt.Printf("TEST-2...%s\n", result)
      
      result = driver(39, 1)
      fmt.Printf("TEST-3...%s\n", result)
      
      result = driver(16, 0)
      fmt.Printf("TEST-4...%s\n", result)
      
      result = driver(90, 1)
      fmt.Printf("TEST-5...%s\n", result)
      
      result = driver(64, 0)
      fmt.Printf("TEST-6...%s\n", result)
      
      result = driver(76, 0)
      fmt.Printf("TEST-7...%s\n", result)
      
      result = driver(83, 0)
      fmt.Printf("TEST-8...%s\n", result)
      
      result = driver(47, 0)
      fmt.Printf("TEST-9...%s\n", result)
      
          
  }
source_py: def write_an_efficient_method_to_check_if_a_number_is_multiple_of_3(n):
      odd_count = 0
      even_count = 0
      if (n < 0):
          n = (- n)
      if (n == 0):
          return 1
      if (n == 1):
          return 0
      while n:
          if (n & 1):
              odd_count += 1
          if (n & 2):
              even_count += 1
          n = (n >> 2)
      return write_an_efficient_method_to_check_if_a_number_is_multiple_of_3(abs((odd_count - even_count)))
source_cpp: int write_an_efficient_method_to_check_if_a_number_is_multiple_of_3(int n) {
    int odd_count = 0;
    int even_count = 0;
    if ( n < 0 ) n = - n;
    if ( n == 0 ) return 1;
    if ( n == 1 ) return 0;
    while ( n ) {
      if ( n & 1 ) odd_count ++;
      if ( n & 2 ) even_count ++;
      n = n >> 2;
    }
    return write_an_efficient_method_to_check_if_a_number_is_multiple_of_3 ( abs ( odd_count - even_count ) );
  }