title: Program To Check If A Given Number Is Lucky All Digits Are Different
signature: program_to_check_if_a_given_number_is_lucky_all_digits_are_different <- function(n) {
test_code: 
  
  
  # SOLUTION CODE
  # ============================================
  PLACEHOLDER_CODE_BODY
  
  # TESTING CODE 
  # ============================================
  validate_solution <- function(actual, expected) {
      toString(actual)==toString(expected)
  }
  
  driver <- function(n, expected){
      if (validate_solution(PLACEHOLDER_FN_NAME(n), expected)){
          "PASSED"
      } else{
          "FAILED"
      }
  }
  
  main <- function() {
      cat(sprintf("TEST-0...%s\n",driver(
          474L, 
          0L
      )))
  
      cat(sprintf("TEST-1...%s\n",driver(
          9445L, 
          0L
      )))
  
      cat(sprintf("TEST-2...%s\n",driver(
          90L, 
          0L
      )))
  
      cat(sprintf("TEST-3...%s\n",driver(
          30L, 
          0L
      )))
  
      cat(sprintf("TEST-4...%s\n",driver(
          37453L, 
          0L
      )))
  
      cat(sprintf("TEST-5...%s\n",driver(
          27L, 
          0L
      )))
  
      cat(sprintf("TEST-6...%s\n",driver(
          2400L, 
          0L
      )))
  
      cat(sprintf("TEST-7...%s\n",driver(
          98L, 
          0L
      )))
  
      cat(sprintf("TEST-8...%s\n",driver(
          46L, 
          0L
      )))
  
      cat(sprintf("TEST-9...%s\n",driver(
          722L, 
          0L
      )))
  
  }
  
  main()
source_py: def program_to_check_if_a_given_number_is_lucky_all_digits_are_different(n):
      ar = ([0] * 10)
      while (n > 0):
          digit = math.floor((n % 10))
          if ar[digit]:
              return 0
          ar[digit] = 1
          n = (n / 10)
      return 1
source_cpp: bool program_to_check_if_a_given_number_is_lucky_all_digits_are_different(int n) {
    bool arr [ 10 ];
    for ( int i = 0;
    i < 10;
    i ++ ) arr [ i ] = false;
    while ( n > 0 ) {
      int digit = n % 10;
      if ( arr [ digit ] ) return false;
      arr [ digit ] = true;
      n = n / 10;
    }
    return true;
  }