title: Count Strings Can Formed Using B C Given Constraints 1
signature: function count_strings_can_formed_using_b_c_given_constraints_1(n)
test_code: using Printf
  
  # SOLUTION CODE
  # ============================================
  PLACEHOLDER_CODE_BODY
  
  # TESTING CODE 
  # ============================================
  function validate_solution(actual, expected)
      return actual == expected
  end
  
  function driver(n, expected)
      try
  
          if validate_solution(PLACEHOLDER_FN_NAME(n), expected)
              return "PASSED";
          end
          return "FAILED";
      catch exception_obj
          return string(Base.typename(typeof(exception_obj)).wrapper);
      end
  end
  
  function main()
      
      result = driver(55, 83271);
      @printf("TEST-0...%s\n",result);
      
      result = driver(36, 23383);
      @printf("TEST-1...%s\n",result);
      
      result = driver(69, 164359);
      @printf("TEST-2...%s\n",result);
      
      result = driver(92, 389483);
      @printf("TEST-3...%s\n",result);
      
      result = driver(73, 194619);
      @printf("TEST-4...%s\n",result);
      
      result = driver(16, 2073);
      @printf("TEST-5...%s\n",result);
      
      result = driver(88, 340869);
      @printf("TEST-6...%s\n",result);
      
      result = driver(19, 3459);
      @printf("TEST-7...%s\n",result);
      
      result = driver(66, 143848);
      @printf("TEST-8...%s\n",result);
      
      result = driver(68, 157319);
      @printf("TEST-9...%s\n",result);
      
  end
  
  main()
source_py: def count_strings_can_formed_using_b_c_given_constraints_1(n):
      return ((1 + (n * 2)) + ((n * ((n * n) - 1)) // 2))
source_cpp: int count_strings_can_formed_using_b_c_given_constraints_1(int n) {
    return 1 + ( n * 2 ) + ( n * ( ( n * n ) - 1 ) / 2 );
  }