title: Number Of Substrings With Odd Decimal Value In A Binary String
signature: function numberOfSubstringsWithOddDecimalValueInABinaryString($s) {
test_code: <?php
  
  
  // SOLUTION CODE 
  // ============================================
  PLACEHOLDER_CODE_BODY
  
  // TESTING CODE 
  // ============================================
  function validateSolution($actual, $expected){
      return serialize($actual) == serialize($expected);
  }
  
  function driver($s, $expected){
      try{
        if (validateSolution(PLACEHOLDER_FN_NAME($s), $expected)){
          return "PASSED";
        }
        return "FAILED";
      }
      catch (Exception $exception_obj) {
        return get_class($exception_obj);
      }
  }
  
  function main(){
      printf("TEST-0...%s\n",driver(
        "OGiOkJF", 
        0));
      
      printf("TEST-1...%s\n",driver(
        "517376", 
        1));
      
      printf("TEST-2...%s\n",driver(
        "11", 
        3));
      
      printf("TEST-3...%s\n",driver(
        "Ze", 
        0));
      
      printf("TEST-4...%s\n",driver(
        "8763644247018", 
        1));
      
      printf("TEST-5...%s\n",driver(
        "00111010001", 
        15));
      
      printf("TEST-6...%s\n",driver(
        "HGwkBKUOVu", 
        0));
      
      printf("TEST-7...%s\n",driver(
        "652", 
        0));
      
      printf("TEST-8...%s\n",driver(
        "101000011110", 
        21));
      
      printf("TEST-9...%s\n",driver(
        "kvdpG ", 
        0));
      
  }
  
  main();
  ?>
source_py: def number_of_substrings_with_odd_decimal_value_in_a_binary_string(s):
      n = len(s)
      auxArr = [0 for i in range(n)]
      if (s[0] == '1'):
          auxArr[0] = 1
      for i in range(0, n):
          if (s[i] == '1'):
              auxArr[i] = (auxArr[(i - 1)] + 1)
          else:
              auxArr[i] = auxArr[(i - 1)]
      count = 0
      for i in range((n - 1), (- 1), (- 1)):
          if (s[i] == '1'):
              count += auxArr[i]
      return count
source_cpp: int number_of_substrings_with_odd_decimal_value_in_a_binary_string(string s) {
    int n = s . length ( );
    int auxArr [ n ] = {
      0 };
      if ( s [ 0 ] == '1' ) auxArr [ 0 ] = 1;
      for ( int i = 1;
      i < n;
      i ++ ) {
        if ( s [ i ] == '1' ) auxArr [ i ] = auxArr [ i - 1 ] + 1;
        else auxArr [ i ] = auxArr [ i - 1 ];
      }
      int count = 0;
      for ( int i = n - 1;
      i >= 0;
      i -- ) if ( s [ i ] == '1' ) count += auxArr [ i ];
      return count;
    }