title: Find Last Digit Factorial Divides Factorial B
signature: findLastDigitFactorialDividesFactorialB :: Integer -> Integer -> Integer
  findLastDigitFactorialDividesFactorialB a b = 
test_code: import Text.Printf
  import Control.Exception (catch, SomeException)
  import Data.Typeable
  import qualified Data.List as List
  import qualified Data.Map as Map
  import qualified Data.Set as Set
  
  -- SOLUTION CODE
  -- ============================================
  
  PLACEHOLDER_CODE_BODY
  
  -- TESTING CODE 
  -- ============================================
  validateSolution :: Integer -> Integer -> Bool
  validateSolution actual expected = do
      actual == expected
  
  
  driver :: Integer -> Integer -> Integer -> String
  driver a b expected = do
      if (validateSolution (PLACEHOLDER_FN_NAME a b) expected)
          then "PASSED"
      else "FAILED"
  
  main = do
      printf "TEST-0...%s\n" (driver (79) (84) (0) )
  
      printf "TEST-1...%s\n" (driver (61) (29) (1) )
  
      printf "TEST-2...%s\n" (driver (39) (77) (0) )
  
      printf "TEST-3...%s\n" (driver (39) (65) (0) )
  
      printf "TEST-4...%s\n" (driver (61) (78) (0) )
  
      printf "TEST-5...%s\n" (driver (86) (73) (1) )
  
      printf "TEST-6...%s\n" (driver (7) (92) (0) )
  
      printf "TEST-7...%s\n" (driver (86) (50) (1) )
  
      printf "TEST-8...%s\n" (driver (86) (63) (1) )
  
      printf "TEST-9...%s\n" (driver (11) (2) (1) )
  
source_py: def find_last_digit_factorial_divides_factorial_b(A, B):
      variable = 1
      if (A == B):
          return 1
      elif ((B - A) >= 5):
          return 0
      else:
          for i in range((A + 1), (B + 1)):
              variable = ((variable * (i % 10)) % 10)
          return (variable % 10)
source_cpp: int find_last_digit_factorial_divides_factorial_b(long long int A, long long int B) {
    int variable = 1;
    if ( A == B ) return 1;
    else if ( ( B - A ) >= 5 ) return 0;
    else {
      for ( long long int i = A + 1;
      i <= B;
      i ++ ) variable = ( variable * ( i % 10 ) ) % 10;
      return variable % 10;
    }
  }