title: Write An Efficient Method To Check If A Number Is Multiple Of 3
signature: writeAnEfficientMethodToCheckIfANumberIsMultipleOf3 :: Integer -> Integer
  writeAnEfficientMethodToCheckIfANumberIsMultipleOf3 n = 
test_code: import Text.Printf
  import Control.Exception (catch, SomeException)
  import Data.Typeable
  import qualified Data.List as List
  import qualified Data.Map as Map
  import qualified Data.Set as Set
  
  -- SOLUTION CODE
  -- ============================================
  
  PLACEHOLDER_CODE_BODY
  
  -- TESTING CODE 
  -- ============================================
  validateSolution :: Integer -> Integer -> Bool
  validateSolution actual expected = do
      actual == expected
  
  
  driver :: Integer -> Integer -> String
  driver n expected = do
      if (validateSolution (PLACEHOLDER_FN_NAME n) expected)
          then "PASSED"
      else "FAILED"
  
  main = do
      printf "TEST-0...%s\n" (driver (94) (0) )
  
      printf "TEST-1...%s\n" (driver (94) (0) )
  
      printf "TEST-2...%s\n" (driver (79) (0) )
  
      printf "TEST-3...%s\n" (driver (39) (1) )
  
      printf "TEST-4...%s\n" (driver (16) (0) )
  
      printf "TEST-5...%s\n" (driver (90) (1) )
  
      printf "TEST-6...%s\n" (driver (64) (0) )
  
      printf "TEST-7...%s\n" (driver (76) (0) )
  
      printf "TEST-8...%s\n" (driver (83) (0) )
  
      printf "TEST-9...%s\n" (driver (47) (0) )
  
source_py: def write_an_efficient_method_to_check_if_a_number_is_multiple_of_3(n):
      odd_count = 0
      even_count = 0
      if (n < 0):
          n = (- n)
      if (n == 0):
          return 1
      if (n == 1):
          return 0
      while n:
          if (n & 1):
              odd_count += 1
          if (n & 2):
              even_count += 1
          n = (n >> 2)
      return write_an_efficient_method_to_check_if_a_number_is_multiple_of_3(abs((odd_count - even_count)))
source_cpp: int write_an_efficient_method_to_check_if_a_number_is_multiple_of_3(int n) {
    int odd_count = 0;
    int even_count = 0;
    if ( n < 0 ) n = - n;
    if ( n == 0 ) return 1;
    if ( n == 1 ) return 0;
    while ( n ) {
      if ( n & 1 ) odd_count ++;
      if ( n & 2 ) even_count ++;
      n = n >> 2;
    }
    return write_an_efficient_method_to_check_if_a_number_is_multiple_of_3 ( abs ( odd_count - even_count ) );
  }