title: Write An Efficient Method To Check If A Number Is Multiple Of 3
signature: writeAnEfficientMethodToCheckIfANumberIsMultipleOf3(n) {
test_code: import 'dart:convert';
  
  // SOLUTION CODE
  // ============================================
  PLACEHOLDER_CODE_BODY
  
  // TESTING CODE 
  // ============================================
  bool validateSolution(int actual, int expected){
      return actual.toString() == expected.toString();
  }
  
  String driver(n, int expected){
      try
      {
          if (validateSolution(PLACEHOLDER_FN_NAME(n), expected)){
              return "PASSED";
          }
          return "FAILED";
      }catch(exception_object){
          return exception_object.runtimeType.toString();
      }
  }
  
  int main() {
  
      print("TEST-0...${driver(
          94, 
          0)
      }");
  
      print("TEST-1...${driver(
          94, 
          0)
      }");
  
      print("TEST-2...${driver(
          79, 
          0)
      }");
  
      print("TEST-3...${driver(
          39, 
          1)
      }");
  
      print("TEST-4...${driver(
          16, 
          0)
      }");
  
      print("TEST-5...${driver(
          90, 
          1)
      }");
  
      print("TEST-6...${driver(
          64, 
          0)
      }");
  
      print("TEST-7...${driver(
          76, 
          0)
      }");
  
      print("TEST-8...${driver(
          83, 
          0)
      }");
  
      print("TEST-9...${driver(
          47, 
          0)
      }");
  
      return 0;
  }
source_py: def write_an_efficient_method_to_check_if_a_number_is_multiple_of_3(n):
      odd_count = 0
      even_count = 0
      if (n < 0):
          n = (- n)
      if (n == 0):
          return 1
      if (n == 1):
          return 0
      while n:
          if (n & 1):
              odd_count += 1
          if (n & 2):
              even_count += 1
          n = (n >> 2)
      return write_an_efficient_method_to_check_if_a_number_is_multiple_of_3(abs((odd_count - even_count)))
source_cpp: int write_an_efficient_method_to_check_if_a_number_is_multiple_of_3(int n) {
    int odd_count = 0;
    int even_count = 0;
    if ( n < 0 ) n = - n;
    if ( n == 0 ) return 1;
    if ( n == 1 ) return 0;
    while ( n ) {
      if ( n & 1 ) odd_count ++;
      if ( n & 2 ) even_count ++;
      n = n >> 2;
    }
    return write_an_efficient_method_to_check_if_a_number_is_multiple_of_3 ( abs ( odd_count - even_count ) );
  }