title: Count Palindromic Subsequence Given String
signature: function countPalindromicSubsequenceGivenString(str) {
test_code: 
  
  // SOLUTION CODE
  // ============================================
  PLACEHOLDER_CODE_BODY
  
  // TESTING CODE 
  // ============================================
  function convertToString(value) {
      return JSON.stringify(value, function (key, val) {
          if (val instanceof Set) {
              return Array.from(val);
          } return val;});
  }
  
  function validateSolution(actual, expected){
      return convertToString(actual)===convertToString(expected);
  }
  
  function driver(str, expected){
      try{
          if (validateSolution(PLACEHOLDER_FN_NAME(str),expected)){
              return "PASSED";
          }
          return "FAILED";
      } catch (error) {
        return error.name;
      }
      
  }
      
  function main(){
    let result = '';
    result = driver("R", 1);
    console.log(`TEST-0...${result}`);
  
    result = driver("2956350", 10);
    console.log(`TEST-1...${result}`);
  
    result = driver("11100111110101", 2798);
    console.log(`TEST-2...${result}`);
  
    result = driver("TZTDLIIfAD", 20);
    console.log(`TEST-3...${result}`);
  
    result = driver("98", 2);
    console.log(`TEST-4...${result}`);
  
    result = driver("1100100001", 270);
    console.log(`TEST-5...${result}`);
  
    result = driver("oKwGeatf", 8);
    console.log(`TEST-6...${result}`);
  
    result = driver("19", 2);
    console.log(`TEST-7...${result}`);
  
    result = driver("00010110100", 563);
    console.log(`TEST-8...${result}`);
  
    result = driver("Cyq", 3);
    console.log(`TEST-9...${result}`);
  
    process.exit(0);
  };
  
  if (require.main === module) {
    main();
  }
source_py: def count_palindromic_subsequence_given_string(str):
      N = len(str)
      cps = [[0 for i in range((N + 2))] for j in range((N + 2))]
      for i in range(N):
          cps[i][i] = 1
      for L in range(2, (N + 1)):
          for i in range(N):
              k = ((L + i) - 1)
              if (k < N):
                  if (str[i] == str[k]):
                      cps[i][k] = ((cps[i][(k - 1)] + cps[(i + 1)][k]) + 1)
                  else:
                      cps[i][k] = ((cps[i][(k - 1)] + cps[(i + 1)][k]) - cps[(i + 1)][(k - 1)])
      return cps[0][(N - 1)]
source_cpp: int count_palindromic_subsequence_given_string(string str) {
    int N = str . length ( );
    int cps [ N + 1 ] [ N + 1 ];
    memset ( cps, 0, sizeof ( cps ) );
    for ( int i = 0;
    i < N;
    i ++ ) cps [ i ] [ i ] = 1;
    for ( int L = 2;
    L <= N;
    L ++ ) {
      for ( int i = 0;
      i < N;
      i ++ ) {
        int k = L + i - 1;
        if ( str [ i ] == str [ k ] ) cps [ i ] [ k ] = cps [ i ] [ k - 1 ] + cps [ i + 1 ] [ k ] + 1;
        else cps [ i ] [ k ] = cps [ i ] [ k - 1 ] + cps [ i + 1 ] [ k ] - cps [ i + 1 ] [ k - 1 ];
      }
    }
    return cps [ 0 ] [ N - 1 ];
  }