title: Lexicographical Concatenation Substrings String
signature: function lexicographicalConcatenationSubstringsString(s: string): string {
test_code: 
  
  // SOLUTION CODE
  // ============================================
  PLACEHOLDER_CODE_BODY
  
  // TESTING CODE 
  // ============================================
  function convertToString(value: any): string{
      return JSON.stringify(value, function (key, val) {
          if (val instanceof Set) {
              return Array.from(val);
          } return val;});
  }
  
  function validateSolution(actual: string, expected: string): boolean {
      return convertToString(actual) === convertToString(expected);
  }
  
  function driver(s: string, expected:string): string {
      try{
          if (validateSolution(PLACEHOLDER_FN_NAME(s),expected)){
              return "PASSED";
          }
          return "FAILED";
      } catch (error) {
        return error.name;
      }
      
  }
      
  function main(){
    let result = '';
    result = driver("sqGOi", "GGOGOiOOiiqqGqGOqGOissqsqGsqGOsqGOi");
    console.log(`TEST-0...${result}`);
  
    result = driver("ZhWXUKmeiI", "IKKmKmeKmeiKmeiIUUKUKmUKmeUKmeiUKmeiIWWXWXUWXUKWXUKmWXUKmeWXUKmeiWXUKmeiIXXUXUKXUKmXUKmeXUKmeiXUKmeiIZZhZhWZhWXZhWXUZhWXUKZhWXUKmZhWXUKmeZhWXUKmeiZhWXUKmeiIeeieiIhhWhWXhWXUhWXUKhWXUKmhWXUKmehWXUKmeihWXUKmeiIiiImmemeimeiI");
    console.log(`TEST-1...${result}`);
  
    result = driver("tjP kR", "  k kRPP P kP kRRjjPjP jP kjP kRkkRttjtjPtjP tjP ktjP kR");
    console.log(`TEST-2...${result}`);
  
    result = driver("qJPHNSJOUj", "HHNHNSHNSJHNSJOHNSJOUHNSJOUjJJJOJOUJOUjJPJPHJPHNJPHNSJPHNSJJPHNSJOJPHNSJOUJPHNSJOUjNNSNSJNSJONSJOUNSJOUjOOUOUjPPHPHNPHNSPHNSJPHNSJOPHNSJOUPHNSJOUjSSJSJOSJOUSJOUjUUjjqqJqJPqJPHqJPHNqJPHNSqJPHNSJqJPHNSJOqJPHNSJOUqJPHNSJOUj");
    console.log(`TEST-3...${result}`);
  
  };
  
  main();
source_py: def lexicographical_concatenation_substrings_string(s):
      n = len(s)
      sub_count = ((n * (n + 1)) // 2)
      arr = ([0] * sub_count)
      index = 0
      for i in range(n):
          for j in range(1, ((n - i) + 1)):
              arr[index] = s[i:(i + j)]
              index += 1
      arr.sort()
      res = ''
      for i in range(sub_count):
          res += arr[i]
      return res
source_cpp: string lexicographical_concatenation_substrings_string(string s) {
    int n = s . length ( );
    int sub_count = n * ( n + 1 ) / 2;
    string arr [ sub_count ];
    int index = 0;
    for ( int i = 0;
    i < n;
    i ++ ) for ( int len = 1;
    len <= n - i;
    len ++ ) arr [ index ++ ] = s . substr ( i, len );
    sort ( arr, arr + sub_count );
    string res = "";
    for ( int i = 0;
    i < sub_count;
    i ++ ) res += arr [ i ];
    return res;
  }