title: How To Print Maximum Number Of A Using Given Four Keys
signature: function howToPrintMaximumNumberOfAUsingGivenFourKeys(n: number): number {
test_code: 
  
  // SOLUTION CODE
  // ============================================
  PLACEHOLDER_CODE_BODY
  
  // TESTING CODE 
  // ============================================
  function convertToString(value: any): string{
      return JSON.stringify(value, function (key, val) {
          if (val instanceof Set) {
              return Array.from(val);
          } return val;});
  }
  
  function validateSolution(actual: number, expected: number): boolean {
      return convertToString(actual) === convertToString(expected);
  }
  
  function driver(n: number, expected:number): string {
      try{
          if (validateSolution(PLACEHOLDER_FN_NAME(n),expected)){
              return "PASSED";
          }
          return "FAILED";
      } catch (error) {
        return error.name;
      }
      
  }
      
  function main(){
    let result = '';
    result = driver(41, 110592);
    console.log(`TEST-0...${result}`);
  
    result = driver(94, 274877906944);
    console.log(`TEST-1...${result}`);
  
    result = driver(80, 5435817984);
    console.log(`TEST-2...${result}`);
  
    result = driver(40, 82944);
    console.log(`TEST-3...${result}`);
  
    result = driver(76, 1811939328);
    console.log(`TEST-4...${result}`);
  
    result = driver(5, 5);
    console.log(`TEST-5...${result}`);
  
    result = driver(43, 196608);
    console.log(`TEST-6...${result}`);
  
    result = driver(67, 150994944);
    console.log(`TEST-7...${result}`);
  
    result = driver(24, 1024);
    console.log(`TEST-8...${result}`);
  
    result = driver(90, 86973087744);
    console.log(`TEST-9...${result}`);
  
  };
  
  main();
source_py: def how_to_print_maximum_number_of_a_using_given_four_keys(N):
      if (N <= 6):
          return N
      screen = ([0] * N)
      for n in range(1, 7):
          screen[(n - 1)] = n
      for n in range(7, (N + 1)):
          screen[(n - 1)] = max((2 * screen[(n - 4)]), max((3 * screen[(n - 5)]), (4 * screen[(n - 6)])))
      return screen[(N - 1)]
source_cpp: int how_to_print_maximum_number_of_a_using_given_four_keys(int N) {
    if ( N <= 6 ) return N;
    int screen [ N ];
    int b;
    int n;
    for ( n = 1;
    n <= 6;
    n ++ ) screen [ n - 1 ] = n;
    for ( n = 7;
    n <= N;
    n ++ ) {
      screen [ n - 1 ] = max ( 2 * screen [ n - 4 ], max ( 3 * screen [ n - 5 ], 4 * screen [ n - 6 ] ) );
    }
    return screen [ N - 1 ];
  }