Function for checking if a string is a path or an URL be improved I made myself a function to check if a string is a path or an URL:
import os

def isPath(s):
    &quot;&quot;&quot;
    @param s string containing a path or url
    @return True if it's a path, False if it's an url'
    &quot;&quot;&quot;
    if os.path.exists(s): # if a file with name s exists, we don't check any further and just return True
        return True
    elif s.startswith(&quot;/&quot;): # clearly a path, urls never start with a slash
        return True
    elif &quot;://&quot; in s.split(&quot;.&quot;)[0]: # if a protocol is present, it's an url
        return False
    elif &quot;localhost&quot; in s: # special case for localhost domain name where splits on . would fail
        return False
    elif len(s.split(&quot;/&quot;)[0].split(&quot;.&quot;)) &gt; 1: # dots before the first slash, normally separating TLD and domain name
        return False
    elif len(s.split(&quot;/&quot;)[0].split(&quot;:&quot;)) &gt; 1: # if colons are present, either it's a IPv6 adress or there is a port number
        return False
    else: # all possible cases of an url checked, so it must be a path
        return True

Did I miss any cases of an url / path, and can the function be improved in some way ?
Some high level comments:

Checking if a string is a url (or a path) is usually done using regular expressions that can be found online. Not sure what's the scope of this function, but it can be seen as reinventing the wheel and might miss some uncommon cases
The method name gives the impression that returning True means it's a path, and False means that it's not, where in fact False has the meaning of being a URL. I would split this function into two: isPath where False just means that the given string is not a Path, and isUrl where False means it's not a URL. Or at the very least renaming it to isPathOrUrl
It's a personal preference but I'd change elif to be if as all the conditional bodies are returning something so no need to use else