Comparing two integers without logical, relational or bitwise operators I answered a question on SO today, however it did't receive any up-votes, so I want to know what's wrong with my code.

The requirement is to compare the input numbers(granted to be positive) without logical, relational or bitwise operators, and insert the corresponding comparison sign between them. For example:

input:  4 6
output: 4 &lt; 6
input:  10 2
output: 10 &gt; 2
input:  2 2
output: 2 = 2


Here is my posted code:

#include &lt;stdio.h&gt;

int main(void)
{
    unsigned a, b;
    scanf("%u %u", &amp;a, &amp;b);
    printf("%u ", a);
    char relationship[] = {'&lt;', '=', '&gt;'};
    putchar(relationship[!!(a/b) - !!(b/a) + 1]);
    printf(" %u", b);
    return 0;
}


That OP wants to know how to insert a comparison sign(&lt;, &gt;, =) between the two numbers. But my emphasis is on how to determine the relationship of the two numbers.

See: https://stackoverflow.com/q/35532123/5399734 for the original question.
That seems a fine solution. Some minor suggestions:


Instead of spelling out relationship as {'&lt;', '=', '&gt;'}, you could use simply "&lt;=&gt;"
Instead of printing a, the relation and b in separate statements, it will be more readable to print in a single printf
The expression !!(a/b) - !!(b/a) evaluates to -1, 0, 1, commonly returned by a cmp function. If you give the expression a name by putting it in a variable, that will ring a bell with many readers and make it easier to understand.


Something like this:

unsigned a, b;
scanf("%u %u", &amp;a, &amp;b);

int cmp = !!(a/b) - !!(b/a);
char relation = "&lt;=&gt;"[cmp + 1];
printf("%u %c %u\n", a, relation, b);