Getting absolute file path Part of my code:

def get_file():

    custom_data_folder = input("Name of custom data directory - " +
                               "Hit ENTER to default: ")
    file_name = input("File name: ")
    default_path = os.path.abspath(os.path.join('data', file_name))
    custom_path = os.path.abspath(os.path.join(custom_data_folder, file_name))

    if custom_data_folder == '':
        return(default_path if os.path.exists(default_path) is True 
                         else "The file or path does not exist.")
    else:
        return(custom_path if os.path.exists(custom_path) is True 
                           else "The file or path does not exist.")


My script assumes a file is in a directory called "data", but I wanted to provide an option of a entering a custom directory where a file could be.

It works, but is there a better way to go about doing what this function is trying to accomplish?
You can simplify several things:


if custom_data_folder == '': can become if not custom_data_folder:
if os.path.exists(default_path) is True can be just if os.path.exists(default_path)


Other notes:


it is questionable that you return "The file or path does not exist." string in case a path does not exist. Throwing an error would probably make more sense
make your default directory name a constant
you can avoid calculating the full default path if custom is provided
you can reduce code duplication and construct a path first, then check if it exist, raise an error if it does not and return if does exist


All the above things taken into account, here is the modified code:

import os


DEFAULT_DIRECTORY = 'data'


def get_file(): 
    """TODO: docstring"""
    custom_data_directory = input("Name of custom data directory - Hit ENTER to default: ")
    file_name = input("File name: ")

    directory = custom_data_directory or DEFAULT_DIRECTORY
    path = os.path.abspath(os.path.join(directory, file_name))

    if not os.path.exists(path):
        raise ValueError("Path '{path}' does not exist".format(path=path))

    return path


Some thoughts for further improvements:


you should probably create a better separation of concerns and have this function parameterized with file and directory names - moving user input related things from out of the function
create a docstring explaining what your function does
.format() formatting can be replaced with an f-string if on Python 3.6+
get_file is probably not the most descriptive name for this function, consider renaming it - get_full_file_path?..