what happens to the depth channels when convolved by multiple filters in a cnn (keras, tensorflow) I have a $15$-channel time series that I want to convolve using a $1$d CNN ($1\times n$ time-steps kernel). Now, let's say I want to have, as my first layer, $16$ filters. This would imply to my mind that the output would have a depth of $16 \times 15 = 240$, because each filter would be applied to each channel independently. However when I implement this in keras, (using Sequential) the filter dimensions in the summary do not reflect this. Here is a code fragment:

TIME_RANGE = 31
NUMBER_OF_CHANNELS = 15

model = Sequential()
model.add(Conv1D(input_shape = (TIME_RANGE, NUMBER_OF_CHANNELS),
                    filters=16,
                    kernel_size=7,
                    padding='valid',
                    data_format='channels_last'))
model.add(ReLU())
model.add(BatchNormalization())

model.add(Conv1D(   filters=32,
                    kernel_size=5,
                    padding='valid'))


and here is the corresponding summary output:

Layer (type)                 Output Shape              Param #


=================================================================

conv1d_1 (Conv1D)            (None, 25, 16)            1696




re_lu_1 (ReLU)               (None, 25, 16)            0




batch_normalization_1 (Batch (None, 25, 16)            64




conv1d_2 (Conv1D)            (None, 21, 32)            2592


as you can see output's shape along the time-wise axis decreases as expected due to the no-padding argument, from $31$ to $25$ to $21$, but the depth just reflects the number of filters-- so where have all my channels gone? At this point in the architecture I was expecting a depth of $15\times 16\times 32 = 7680$. It seems an implicit $1\times 1$ convolution is occurring somewhere, which I don't think I actually want-- I'd like to do my $1\times 1$ convolutions later on in the network. So what am I missing here?
When you have a image dimension of HxWxC and you apply a convolutional layer with filter size F and kernel size KxK, you will be sliding F different KxKxC kernels over your image, resulting in the output dimension of the total operation being H'xW'xF which is what you are seeing.