A question about linked list I would like to check the answer of this exercise:

A circular doubled linked list with N elements has pointers that cost k bytes each of space in memory. How many bytes do the pointers of this list cost in total?

Researching about circular linked lists, i can assume that each node has 2 pointers. So am i right to say that the answer is 2(n)k bytes?

Thanks.
The list takes $2*N*k$ bytes in total. A circular linked list is just a simple linked list with its last node's next pointer pointing back towards head. So, no extra pointer is required to make it circular. Hence, the total space is $2*N*k$.