Prove or disprove the given equivalence f(n) = n/100 = Ω(n) . I am new at proving asymptotic notations , especially at big-Ω. That's why I even didnt start the beginning myself.  I tried to prove myself as looking at other proofs and searched on the internet to find same question but I couldnt find. I dont think so this question is a duplicate of another which was asked here. Thanks for helps.
I assume $n$ takes only positive values. By the definition of Big-Omega you could prove it by showing the following 

$$\lim_{n \rightarrow \infty}\frac{\frac{n}{100}}{n} &gt;0$$ 

The rest is a simple exercise.