Non-deterministic Turing machine and palindromes I have to design a Non-deterministic Turing machine that accepts only non-palindromes in $NTime(n\log n)$.

I think this would be easy on a 2-tape DTM. Simply copy the string onto the second tape – $O(n)$ time – and then check both tapes (one from beginning and the second from the end) – $O(n)$ time again.

However, I can't picture how to do such procedure in a non-deterministic TM using only one tape. All the procedures I came up with take $O(n^2)$ steps. How can the non-determinism reduce the running time here?
Guess a position $\ell$ and add it to the left of the input. Copy it to the beginning of the tape, on top of the input string (use an expanded alphabet). Now go to position $\ell$, carrying your counter around with you. For each position you move, you need to spend $O(\log n)$ time to copy the counter, but that's fine. Decrementing the counter and comparing it to zero also take only $O(\log n)$. Once at position $\ell$, remember the symbol there, and go back to the beginning. Now move your counter all the way to the other end of the string, and count $\ell$ positions from there. Compare the symbol you find to the one you remember.