Proof that if P=PSPACE, RP=BPP Like the title says. I can't figure out how to prove this.
I think it probably has to do with the polynomial hierarchy collapsing but I'm not sure.
$P \subseteq RP $, $BPP \subseteq PSPACE $.
So $PSPACE \subseteq P $, $--&gt;$ $BPP \subseteq RP $.