Understanding The Mapping Of Edges to Nodes In A Graph Theory Problem I am really confused with this problem.

Here's the problem: 

You have $N$ points numbered $1$ through $N$,inclusive, and $N$ arrows again numbered $1$ through $N$,inclusive. No two arrows start at the same place, but multiple arrows can point to the same place and arrows can start and end in the same place. The arrow from place $i$ points to place $a[i-1]$,($a$ being an array representing the game board with $N$ elements and $i$ is between $1$ and $N$, inclusive).There are $0$ to $N$ tokens,inclusive, placed in those places and that, in each round, move along the arrows from their current place. If two or more tokens are in the same place, then you lose that game. But if that doesn't happen for the $K$ rounds specified, then you win the game. There may be multiple ways to solve the problem, but  Two ways are different if there is some $i$ such that at the beginning of the game place $i$ did contain a token in one case but not in the other. Count those ways and return their count modulo $1,000,000,007$.

The whole problem is confusing to me, but what really confuses me is that it states that the arrow that starts from $i$ goes to  $a[i-1]$. How I understand it, for the first example,( $\{1,2,3\} \;5$ Returns:$8$ ), if $a[1]=1$, $a[2]=2$, and $a[3]=3$, then $3$ maps to $2$ and $2$ maps to $1$, but then $1$ maps to $0$,(but point $0$ doesn't exist). 

What would be more correct would be if $a[0]=1$, $a[1]=2$, and $a[2]=3$, but then all the points would map to themselves,(though it says in the example that the tokens don't move during the rounds).

I am probably way off, but I couldn't find many explanations, and the ones I found didn't make any sense to me, and I couldn't find many visual depictions either.
$a[0] = 1, a[1] = 2, a[2] = 3$. 

"The arrow from place $i$ points to place $a[i−1]$"

So yes, all $3$ places in this sample point to themselves. It actually says in the explanation that "in each round each token will stay in the same place". 

In the second sample, all three places point towards the first one.

In the third sample, you have a $2$-cycle: $1$ points to $2$ and vice-versa. 

Is everything clear now?