Poker with Bluffing (game theory) I'm doing a self-study of Game Theory Evolving by Gintis, and am stuck on problem 4.16 "Poker with Bluffing".

The first question asks "Show that Ollie has 64 pure strategies and Stan has 8 pure strategies.". But no matter how I try to approach this, I can't get more then 4 strategies for Stan!

Here is the game tree for the game in question:


The question marks (?) in the figure mean that the payoff depends on who has the higher card.

Here is the game description:


Two players, each with a deck of three cards: H (high), M(medium) or L (low).
Each puts \$1 in the pot, chooses random card
Ollie (P1) either stays or raises
Stan (P2) simultaneously also stays or raises
If both raise/stay - highest card wins the pot (tie - they take their money back)
If Ollie raises, Stan stays  Ollie gets the \$3 pot.
If Stan raises and Ollie stays - Ollie gets another chance:
-> Drop - Stand wins the \$3 pot
-> Call - add \$1 to the pot.


Why does Stand have 8 pure strategies?
Stan has two pure strategies for each type of card. Since there are three types of cards (H, M, L), in total he has $2\times 2\times 2 = 8$ strategies. Here is a list of them:


Always stay.
Always raise.
Stay only if H.
Stay only if M.
Stay only if L.
Raise only if H.
Raise only if M.
Raise only if L.