Interpolate two sets of tracking points Lets say I have two sets of tracking points with the same number of points/set, is it possible to associate points from one set to the other and make them interpolate in time? 

EDIT:

As suggested by @poor, I'll try to clarify what I try to achieve.
This question originates from @cegaton's comment in 2D morphing video images.

I am trying to use the tracker to morph from two video sequences. Imagine two videos, first video has a square moving from left to right of the screen, second video has a rectangle moving the same way. I track four vertices of square as object A and the rectangle's as object B. Both tracking points move according the the image of its video from left to right, but what I want is to interpolate those tracking points (I don't know if creating a new object C or just modifying one of the existing objects) so that at the same time they move from right to left they also aproximate positions of object's A points to object's B points. In the end we will have four points moving both from left to right and adjusting position from A to B thus making posible using on a plane two videos that distort and fade from video A to B.

Hope this makes sense.
Let's say you want to interpolate the movement of empties between frame 0 and 50


create one empty for each tracking point of set A. 
add a constraint to the empty associating with tracking point 1 of set A
add a constraint to the empty associating with tracking point 1 of set B
set the influence of the first constraint to 1 and add a keyframe
go to frame 50, set the influence to 0 and add a keyframe
do the inverse of steps 4 &amp; 5 for the second constraint (0 --> 1)
Repeat steps 2-6 for the other tracking points


This strictly answers your question of how to interpolate between tracking points (you might need to adjust the curves to be linear). 

However since you need to morph the next logical step was to use the empties as hooks to deform a mesh. However the hooks need to modify the position of the vertices directly and not relatively as they do (see this queston ). Still, the half-solution here is worth sharing.