Problem connecting 2 74HC595 8 bit shift registers in cascading connection I have now successfully learned how to control a single 8 bit shift register 74HC595 with Arduino UNO but whenever I tried to connect another one with the first shift resistor via cascading connection just like the image shown below (well I didn't use the 10uf capacitor between positive and negative terminal), the first shift register only outputs as desired but the second shift register, connected to a cascading connection, does not seem to work...

Here is the code.
    int latchPin = 10;  // Latch pin of 74HC595 is connected to Digital pin 5
int clockPin = 11;  // Clock pin of 74HC595 is connected to Digital pin 6
int dataPin = 9;    // Data pin of 74HC595 is connected to Digital pin 4

byte leds = 0;      // Variable to hold the pattern of which LEDs are currently turned on or off

/*
 * setup() - this function runs once when you turn your Arduino on
 * We initialize the serial connection with the computer
 */
void setup() 
{
  // Set all the pins of 74HC595 as OUTPUT
  pinMode(latchPin, OUTPUT);
  pinMode(dataPin, OUTPUT);  
  pinMode(clockPin, OUTPUT);
  Serial.begin(9600);
}

/*
 * loop() - this function runs over and over again
 */
void loop() 
{
  leds = 0; // Initially turns all the LEDs off, by giving the variable 'leds' the value 0
  updateShiftRegister();
  delay(500);
  for (int i = 0; i &lt;= 16; i++) // Turn all the LEDs ON one by one. 
  {
    bitSet(leds, i);        // Set the bit that controls that LED in the variable 'leds'
    updateShiftRegister();
    delay(500);
  }
  
 /* The loop above should repeated 16 times as there are 2 shift resistors, each of them containing 8 and we need to lit up all 16 LEDs*/ 
  
}

/*
 * updateShiftRegister() - This function sets the latchPin to low, then calls the Arduino function 'shiftOut' to shift out contents of variable 'leds' in the shift register before putting the 'latchPin' high again.
 */
void updateShiftRegister()
{
   digitalWrite(latchPin, LOW);
   shiftOut(dataPin, clockPin, LSBFIRST, leds);
   digitalWrite(latchPin, HIGH);
}

so is it my code or wiring problem?
I have read many articles on internet to make myself get it understood but unfortunately, none of the articles satisfied me.
many thanks for giving me a bit of your precious time...
I am really very sorry to say that after a long inspection , i have found that
shift register clear (pin 10) pin of the second shift register remained inactivated due to loose connection of power, after fixing it, all shift registers are working very fine.
I do really apologize to all those friends who came to help me, for wasting their time, i am really very sorry for that...
all problems are solved now.