Internal volts in arduino for percent battery I'm working on a small project that is creating me a headache. I know arduimo (ATmega 328P .... etc. ..) has an internal voltage source code millivolts, but I would like to know how the full source code become percentage where 3 volts = 0%  and 4.2 volts = % 100% ??? . I appreciate the help because in codes is not my forte. I leave the code so Help me complete. Thank you.

long readVcc() {
  long result;
  // Read 1.1V reference against AVcc
  ADMUX = _BV(REFS0) | _BV(MUX3) | _BV(MUX2) | _BV(MUX1);
  delay(2); // Wait for Vref to settle
  ADCSRA |= _BV(ADSC); // Convert
  while (bit_is_set(ADCSRA,ADSC));
  result = ADCL;
  result |= ADCH&lt;&lt;8;
  result = 1126400L / result; // Back-calculate AVcc in mV
  return result;
}

void setup() {
  Serial.begin(9600);
}

void loop() {
  Serial.println( readVcc(), DEC );
  delay(1000);
}
map()

unsigned char level = map(readVcc(), 3000, 4200, 0, 100);