square wave with serial plotter I have this code which produces a square wave:

int output_state = 0;
unsigned long start;

void setup() {
  Serial.begin(1200);
  start = millis();
}

void loop() {

  if((millis() - start) &gt;=1000){
    output_state = ! output_state;
    //output_state *= 1023;
    start = millis();
  }

    Serial.println(output_state);
}




but should I multiply the signal by 1023:

output_state *= 1023;


this signal is produced by the Serial Plotter:



Mind that the timing is right, just the x axis speeds up in zero values. Why is that happening, and how can be solved?

Any thoughts would be appreciated.
It takes twice as long to print "1023" (6 bytes, including the CRLF line
terminator) than to print "0" (3 bytes). Thus, in the same time, you are
printing twice as many "0" than "1023".

If you want the data points to be printed at a consistent rate,
you can impose the printing timing just like you did on the
output_state. Keep in mind that you cannot print more than 20 samples
per second at 1200&nbsp;bps. You could also pad the strings so that they
always have the same length:

char s[5];  // one byte for the NULL terminator
sprintf(s, "%4d", output_state);
Serial.println(s);


I would prefer the first solution (explicitly control the timing).