Expectation of deterministic signals Maybe this a stupid question, but I came along with this point and I would like to confirm that I am not wrong.

I found some similar posts in StackExchange, like:

Expectation and Auto-correlation of an Output from a Matched Filter.

In one of the answer, it is stated "as S(t) is determistic[...]" and then the deterministic signal is taken out of the expectation.

and we know that for instance if I have a constant value, I can take it out of the Expectation operator, e.g.:



Where lambda is a random variable and "a" is a constant. Ok, so, if "a" is a constant, then fair enough, but what happens when "a" is a deterministic signal, but it is not a constant, for instance, what happens if "a" is a squared subcarrier?

Can I still safely say that the expectation will be the product of the deterministic signal multiplied by the expectation of the random variable?

Thanks, guys!
If $x(t)$ is a deterministic signal, then you have $E[x(t)]=x(t)$. Furthermore, if $Y(t)$ is a random process you have $E[x(t)Y(t)]=x(t)E[Y(t)]$.