How is the matrix $\mathbf R_x$ not Toeplitz in case of a signal missing one term? I am solving a question that says if we have sequence $x(n)$ of a signal missing one term then we have to find autocorrelation matrix $R_x$ as follows: 

$$R_x = E\{\mathbf {xx^H}\}$$ 
Now if I take $x(n) = [x(0) , x(2),x(3)]$ that is missing term $x(1)$
I found following value of $R_x$

$R_x =  $$\left(
        \begin{matrix}
        r_x(0) &amp; r_x^*(2) &amp; r_x^*(3) \\
        r_x(2) &amp; r_x(0) &amp; r_x^*(1) \\
        r_x(3) &amp; r_x(1) &amp; r_x(0) \\
        \end{matrix} \right)
$

Now I check that this matrix is Toeplitz or not, by the definition of Toeplitz (constant diagonal term) $R_x$ is Toeplitz. But when I checked the solution it says the above matrix is not Toeplitz and there is no explanation given. I wonder what I am missing in definition of a Toeplitz matrix that does not fit in the above matrix. Can anyone explain this?
For $\boldsymbol{R}_x$ to be toeplitz it should be:

$$\boldsymbol{R}_x = \begin{bmatrix}r_{x}(0) &amp; r_{x}(2) &amp; r_{x}(3) \\ r_{x}(2) &amp; r_{x}(0) &amp; r_{x}(2) \\
r_{x}(3) &amp; r_{x}(2) &amp; r_{x}(0) \end{bmatrix} $$

Since it is not, it is not a toeplitz matrix.