What is the zero in this transfer function? What is the zero for the following transfer function, $-1/2$ or $-2$?

$$H(s) = \frac{2s +1}{(s + 3)(s + 2)}$$

This appears to give a zero of $-1/2$. 

I can transform this into the standard form that includes the gain $K$:

$$H(s) = \frac 12 \left(\frac{s + 2}{(s + 3)(s + 2)}\right)$$

Where the leading half is the gain. The zero now appears to be $-2$. What is the conceptual error I am making? Should I take the gain out or leave it in the numerator?

UPDATE: I think this question is worthy of deletion given the nature of the error but I am unable to. Instead, see my answer below.
$$2s+1=2\left(s+\frac12\right)$$
That's all I can say.