Why only take 205 sample when using a sample rate of 10khz or 8khz? I've often seen i my DSP book, that when they record a sound, they use a sample rate at 10khz or 8 khz, which makes sense since the fs is 2 times bigger than the sampling signals max freq.
What i don't understand is why they only take 205 samples, rather than 10000 samples or 8000 samples, wouldn't each sample be "unperiodic"??.. 
What is the magic behind the number 205 ???

EDIT:
I know they aren't able to sample 8000 times here, but why not take 320 samples then?? than just 205??

Example:


  Estimating DTMF Tones with the Goertzel Algorithm
  
  The minimum duration of a DTMF signal defined by the ITU standard is
  40 ms. Therefore, there are at most 0.04 x 8000 = 320 samples
  available for estimation and detection. The DTMF decoder needs to
  estimate the frequencies contained in these short signals.
  
  One common approach to this estimation problem is to compute the
  Discrete-Time Fourier Transform (DFT) samples close to the seven
  fundamental tones. For a DFT-based solution, it has been shown that
  using 205 samples in the frequency domain minimizes the error between
  the original frequencies and the points at which the DFT is estimated.
  
  Nt = 205; original_f = [lfg(:);hfg(:)]  % Original frequencies
  original_f =

     697
     770
     852
     941
    1209
    1336
    1477

  
  k = round(original_f/Fs*Nt);  % Indices of the DFT estim_f =
  round(k*Fs/Nt)      % Frequencies at which the DFT is estimated
  estim_f =

     702
     780
     859
     937
    1210
    1327
    1483

  
  To minimize the error between the original frequencies and the points
  at which the DFT is estimated, we truncate the tones, keeping only 205
  samples or 25.6 ms for further processing.
  
  tones = tones(1:205,:);
The frequency of DFT bin centers is i*Fs/N, for integer i.  Thus different N will create different arrays of frequencies.  For some N, this will produce an array that has the lowest nearest bin center distance from the frequency set that you wish to measure (in thus case, a vector of DFT frequencies).  According to the referenced document, for some standard sample rate, N=205 will produce that vector with the closest DFT bin centers to DFT frequencies.

Since each DFT bin has a Sinc shaped roll-off, the closer a bin frequency is to a desired measurement frequency, the lower the magnitude measurement error will be without needing further interpolation computation.

For N greater than 320, the DFT will have greater frequency resolution, but the time resolution gets worse and will overlap multiple tones, which creates greater ambiguity in which tone is being detected.