multiplication of a function with a Fourier-transformed equals to Fourier-transformed with a function I already showed b item using the fact that it is $h\left(0\right)=\int \:f\left(t\right)g\left(0-t\right)dt$
I struggle a lot of hours trying to find the trick in item C.
Can anyone help please ?
Hint:
You only need to use the definition of the Fourier transform and its inverse transform to show that if
$$G(f)=\mathscr{F}\{g(t)\}$$
then
$$g(f)=\mathscr{F}\{G(-t)\}$$
holds. Then just use the result from $b$.