Subtracting DC Offset a Complex Signal? If I take the magnitude of a complex signal, and then subtract the mean amplitude, I remove DC offset but lose the real and imaginary components. How can I properly subtract the DC offset of a complex signal? Subtracting the complex amplitude results in a non-zero magnitude so I don't believe that's the way to go...
Using the term "DC offset" is a little misleading in this context.  I think what you are asking is how do your "center" your signal.  That is simple:  Take the average value (sum of N samples divided by N) and subtract it from each sample.  A "DC offset" is usually considered in terms of real valued signals.  The DC stands for "Direct Current".