Even and odd signal energy property In Signals and Systems by A. V. Oppenheim, A. S. Willsky, S. Hamid Nawab, 2nd Edition, and Signals and Systems, Simon Haykins, Barry Van Veen, 2nd Edition there is a problem related to energy of real-valued even and odd signal.

Energy of an arbitrary real-valued signal $x(t)$ is equal to the sum of the energy of the even component $x_{e}(t)$ and energy of the odd component $x_{o}(t)$ i.e.
\begin{equation}
 \int_{-\infty}^{\infty}x^2(t)dt = \int_{-\infty}^{\infty}x_{e}^2(t)dt + 
 \int_{-\infty}^{\infty}x_{o}^2(t)dt\notag
\end{equation}
Which can be proved very easily by expressing $x(t) = x_{e}(t) + x_{o}(t)$ and evaluating its energy as
\begin{align}
 \int_{-\infty}^{\infty}x^2(t)dt &amp;= 
 \int_{-\infty}^{\infty}\big(x_{e}(t) + x_{o}(t)\big)^2dt\notag\\
 &amp;= \int_{-\infty}^{\infty}x_{e}^{2}(t)dt + \int_{-\infty}^{\infty}x_{o}^{2}(t)dt
 +2\int_{-\infty}^{\infty}x_{e}(t)x_{o}(t)dt\notag.
\end{align}
The term $x_{e}(t)x_{o}(t)$ in the last integration corresponds to an odd signal (multiplication of even and odd signal results into odd signal) and its integration (joint energy) is equal to zero (area under an odd signal over symmetrical limits is zero). Hence
\begin{align}
 \int_{-\infty}^{\infty}x^2(t)dt = 
 \int_{-\infty}^{\infty}x_{e}^{2}(t)dt +  
    \int_{-\infty}^{\infty}x_{o}^{2}(t)dt\notag
\end{align}

I was wondering, what if I consider $x(t)$ to be a complex signal, will above property still be valid. I tried as
\begin{equation}
 \int_{-\infty}^{\infty}|x(t)|^2dt = \int_{-\infty}^{\infty}|x_{e}(t)|^2dt + \int_{-\infty}^{\infty}|x_{o}(t)|^2dt\notag
\end{equation}
Expressing $x(t) = x_{e}(t) + x_{o}(t)$ and evaluating its energy as
\begin{align}
 \int_{-\infty}^{\infty}|x(t)|^2dt &amp;= \int_{-\infty}^{\infty}\big|x_{e}(t) + x_{o}(t)\big|^2dt\notag\\
 &amp;= \int_{-\infty}^{\infty}|x_{e}(t)|^{2}dt +  
 \int_{-\infty}^{\infty}|x_{o}(t)|^{2}dt
 +\int_{-\infty}^{\infty}[x_{e}(t)x_{o}^{*}(t) + x_{o}(t)x_{e}^{*}(t)]dt\notag
\end{align}

On expanding the term
\begin{align}
 x_{e}(t)x_{o}^{*}(t) &amp;= \big(x_{er}(t) + jx_{ei}(t)\big)\big(x_{or}(t) - jx_{oi}(t)\big)\\
&amp;= x_{er}(t)x_{or}(t) + x_{ei}(t)x_{oi}(t) - jx_{er}(t)x_{oi}(t)  + jx_{ei}(t)x_{or}(t)\\
x_{o}(t)x_{e}^{*}(t) &amp;= \big(x_{or}(t) + jx_{oi}(t)\big)\big(x_{er}(t) - jx_{ei}(t)\big)\\
&amp;= x_{er}(t)x_{or}(t) + x_{ei}(t)x_{oi}(t) - jx_{ei}(t)x_{or}(t)  + jx_{er}(t)x_{oi}(t)
\end{align}
Further on adding this terms results into
\begin{align}
 \int_{-\infty}^{\infty}|x(t)|^2dt &amp;= \int_{-\infty}^{\infty}|x_{e}(t)|^{2}dt + \int_{-\infty}^{\infty}|x_{o}(t)|^{2}dt
 +2\int_{-\infty}^{\infty}\big(x_{er}(t)x_{or}(t) + x_{oi}(t)x_{ei}(t)\big)dt\notag
\end{align}
The terms $x_{er}(t)x_{or}(t)$ and $x_{oi}(t)x_{ei}(t)$ in the last integration corresponds to an odd signal and its integration (joint energy) is equal to zero. Hence
\begin{equation}
 \int_{-\infty}^{\infty}|x(t)|^2dt = \int_{-\infty}^{\infty}|x_{e}(t)|^2dt + \int_{-\infty}^{\infty}|x_{o}(t)|^2dt\notag
\end{equation}
I would appreciate if anyone here can validate the proof. Is it correct to say that the same property too holds for complex signal.
Your result is correct but note that for complex signals, the even and odd parts are defined by

$$x_e(t)=\frac12\left[x(t)+x^*(-t)\right]\tag{1}$$
and
$$x_o(t)=\frac12\left[x(t)-x^*(-t)\right]\tag{2}$$

where $^*$ denotes complex conjugation.

From $(1)$ and $(2)$ it follows that the real part of $x_e(t)$ is even and its imaginary part is odd, whereas $x_o(t)$ has an odd real part and an even imaginary part.

We get

$$|x(t)|^2=|x_e(t)+x_o(t)|^2=|x_e(t)|^2+|x_o(t)|^2+2\,\text{Re}\{x_e(t)x_o^*(t)\}\tag{3}$$

From

$$\begin{align}x_e(t)x_o^*(t)&amp;=\frac14\left[x(t)+x^*(-t)\right]\left[x^*(t)-x(-t)\right]\\&amp;=\frac14\left[|x(t)|^2-x(t)x(-t)+x^*(t)x^*(-t)-|x(-t)|^2\right]\end{align}\tag{4}$$

we see that $x_e(t)x_o^*(t)$ is an odd signal according to definition $(2)$ (it is the odd part of $\frac12 \left[|x(t)|^2-x(t)x(-t)\right]$), and, consequently, its real part is odd. This implies that the integral over the last term in $(3)$ is zero, and the stated property holds.