Time resolution of the Short Time Fourier Transform (STFT) I'm struggling to figure out how the time points of an STFT are calculated, and I can't find a definitive answer.  Let's say I have a 4Hz stationary signal and I'm going to use a 64 second window with 3 second overlap. So that's a 256 point window and a 12 point overlap. 

Assuming I start at time=0, take the first 64 seconds, and perform the FFT/Power Spectrum Density/etc... Can I then say that is the value at t=32? Is the next window, after the 3 second slide localized at t=35, and so on?

If so, and I really wanted to start at t=0, would I then effectively start at t=-32, fill the first 128 points with zeros and take the first 128 points from my signal, thus centering on t=0?
There is no single "time instant" associated with a short-time Fourier transform. As you noted, if you perform a DFT on data collected from $t = 0$ to $t = 64$, then there isn't a single point in time that you can associate with the output from that DFT; it is a function of every sample in its time interval. 

For this reason, there is no standard convention for how you might denote the time axis associated with successive STFTs, if you were tiling them together into a spectrogram, for example. You'll just need to pick a convention that is meaningful for your application. You've already identified a couple reasonable ones (using the beginning or center of the DFT's window as its "time instant").