Stability of transfer function Now K(s) is obviously the negative feedback loop which is ${H(s) \over 1+H(s)G(s)}$

When I substitute ${H(s) = {1 \over s-2}}$ I get  K(s) = ${ 1 \over s-2 +G(s) }$

For the system to be stable I know that the poles have to be on the negative half of th imaginary plane. Not sure how to find G(s).
Hint:

Since $K(s) = \frac{1}{s-2+G(s)}$, then the roots of $s-2+G(s)$ must lie on the left side of the complex plane. Let's suppose that $G(s)$ is of the form $as + b$. Can you solve it then?