How to reconstruct a time-discrete signal German: Sie betrachten das zeitkontinuierliche Signal $s(t)$ mit einem digitalen Oszilloskop mit Abtastperiode $T_\mathrm{s}$ und messen das zeitdiskrete Signal $\tilde{s}[n] = s(n\:T_s)$

Nehmen Sie an, dass das Abtasttheorem eingehalten wird.

Können Sie $s(t)$ aus $\tilde{s}[n]$ rekonstruieren? Begründen Sie!
Skizzieren sie $s(t)$ für einen Bereich von $- 3\:T_\mathrm{s}\leq t \leq 3 \:T_\mathrm{s}$

English: You consider the time-continuous signal $ s (t) $ with a digital oscilloscope with sampling period $ T_\mathrm{s} $ and measure the time-discrete signal $\tilde{s}[n] = s(n\:T_s)$
Assume that the sampling theorem is met.

Can you reconstruct $ s (t) $ from  $\tilde{s}[n]$? Explain!
Sketch $ s (t) $ for a range from $- 3\:T_\mathrm{s}\leq t \leq 3 \:T_\mathrm{s}$


Sadly, that's all that's given. This is an exam problem from university and I don't have any clue how to get a useful solution.
Maybe some one is able to reconstruct it for me and tell me how it works?
Consider things you know about the sampling theorem:

If it is met, the original signal can always be reconstructed perfectly!
The signal has to be bandlimited for the theorem to be met!

Further, think about the spectral and time domains and their relation to each other:

If a signal is bandlimited in spectral domain, it has to be infinite in time domain.

Then, thinking about the given signal:

The given sampled signal has just zeros before and after the one none-zero value.
It is not periodic.
One can conclude, that in the original signal, there have to be none zero values between all (or at least some) sampling points, otherwise it would not be infinite.

So we have to ask ourselves the question:

Which signal is bandlimited, has zero crossings at regular intervals, a non zero value in the middle and is not periodic?

If you had any lectures on signal theory, the answer should be pretty obvious.