Conversion from continuous to sampled signal? I am bit confused regarding sampling as i read different types of statements in different texts

Forexample i have a continous time signal $x=sin(t)$ defined for $t=0:10$
and i want to sample it with sampling frequency 5000hz
How can i obtain sampled signal $x[n]$ in this case

Please guide me which of following two ways is correct to define sampled signal?

$x[n]$=$sin(ts)$               where ts=1/5000

               or


$x[n]$=$sin(ts/fs)$               where ts=1/5000 and fs=5000
You typically write a sine wave as 
$$x(t) = sin(2 \cdot \pi \cdot f \cdot t)$$
where t is time and f the frequency of the sine wave. 

Please note that both time and frequency are physical quantities, i.e. they have values and units. The units need to cancel each other since you can't apply the sine function to a unit

If you want to sample this at $f_s = 5000 Hz$ you simply calculate the value every a time interval $T_s = 1/f_s$. You get

$$x_d[n] = sin(2 \cdot \pi \cdot f \cdot n \cdot T_s) $$

or 

$$x_d[n] = sin(2 \cdot \pi \cdot n \cdot f/f_s) $$

Whether this is "correct" or not depends the ratio of frequency to sample rate and whether this meets the criteria of the sampling theorem or not.