Does Increasing Resolution Lead to Have a Poor Resolution? As it has proven in some paper and books the time and frequency resolution of Morlet wavelet is :
  $\Delta t=\frac{f_c\sqrt{f_b}}{2f_i}$ 
 $\Delta f=\frac{1}{2\pi f_c \sqrt{f_b}}$
I don't know how these relations have obtained, I have asked it in detail in here.you can answer that if you want.
 but lets accept these relationship for now. there is some misunderstanding for me in here about the concept of resolution.
for this case, by increasing the term $f_c\sqrt{f_b}$ we have finer frequency resolution but poor time resolution. I am sure about finer frequency and poor time resolution because my practical results meet it.  but if you look at $\Delta t$ and  $\Delta f$ relationships you receive that increasing the term $f_c\sqrt{f_b}$ leads to decrease $\Delta f$  and increase the $\Delta t$.
does it mean that smaller value of resolution spell to have finer resolution and vice verca?
Indeed, that's the Heisenberg Uncertainty Principle - you can't have both very good frequency and time resolution. You always have to sacrifice something. In case of Short Time Fourier Transform it's straightforward, but for wavelets are being 'squeezed', which is changing their frequency resolution. Figure below describes more than a thousand words:



EDIT:
Because you are still trying to understand why it is like that, then please mind that by increasing the frequency of the wavelet ($f_c$), you should also shrink it in time (decrease $f_b$). For more info please refer for example to: Paul Addison - The Illustrated Wavelet Transform Handbook. You can find there a following graphs (Section 2.12):