The plot of instantaneous power of the Dirac function I am very confused. I have tried researching this question for the last two weeks and I cannot get a conclusive answer.
I was wondering how would I go about plotting the instantaneous power in the time domain of the Dirac input signal.
The problem becomes as I try to calculate the power in time domain, $P(t) = \left\lvert\delta(t)\right\rvert^2$. I know how to calculate power by using Rayleigh's theorem to convert the the signal to frequency domain where delta(f) = 1. to get infinity over an infinite period which is undefined value for power, but I just want to plot power over time for the Dirac function.
delta isn't square-able since as x goes to 0 the delta function goes to infinity and you cannot square infinity, also something about the delta function being a distribution and not able to be square-able.
I was wondering if someone could point me in the right direction to be able to plot this function.
Thank you
The problem becomes as I try to calculate the power in time domain, $P(t) = \left\lvert\delta(t)\right\rvert^2$

As you figured out yourself, that's impossible: the power of the Dirac impulse isn't defined, it diverges (goes to infinity).
Hence, you especially can't plot the power &quot;correctly&quot;; it's zero anywhere but at $t=0$, where it diverges.
But quite honestly, this should come as no surprise: you can't correctly plot $\delta(t)$, either (the value at $t=0$ isn't defined just as much as its square isn't).
So, whatever question can be answered by that plot: I'm afraid you'll have to find a &quot;better&quot; question.