Is there a fixed total amount of Bitcoin cash? As I understood from Nakamoto's original bitcoin proposal, the bitcoin algorithm was designed in such a way that there would be a fixed total number of bitcoins and that bitcoin is designed for microtransactions. Therefore, once all of the mine-able bitcoin has been mined, no new bitcoins will appear in the system. As the value of bitcoin increases, people will simply trade smaller and smaller fractions of the original fixed number of bitcoins.

Is this true with Bitcoin Cash? Is the only difference between Bitcoin Cash and the original bitcoin a larger block size?
Is this true with Bitcoin Cash?


Yes, the same.


  Is the only difference between Bitcoin Cash and the original bitcoin a larger block size?


There's one more difference: Bitcoin Cash uses BIP-143 to solve the quadratic hashing and to add replay protection. (BIP-143 is also enabled by SegWit on main chain.) (the formula is hashType | SIGHASH_FORKID (0x40) while it's hashType | SIGHASH_FORKID (0x40) | 79 &lt;&lt; 8 (20,024) on Bitcoin Gold)

As @jnewbery said, transactions are now being signed differently, and there's an emergency difficulty adjustment algorithm that makes difficulty lower by 20%, if the blocks come too slow. (More info about it here)



UPDATE November 13 A hardfork has occured. EDA was disabled and a new difficulty adjustment algorithm (cw-144) came. Also the 3rd person malleability (a.k.a. transaction malleability) is fixed. More info: https://www.bitcoinabc.org/november or https://github.com/bitcoincashorg/spec/blob/master/nov-13-hardfork-spec.md