Sensor size of Sony HDR-HC7e I want to motion track a shot from my Sony HDR-HC7e camcorder and I am not quite sure about the horizontal sensor size(width).
I set the focal length to minimum and the recording to HDV 16:9
This manual (HC7e and HC7 are basically the same) states it is a 1/2.9&quot; sensor with a diagonal of 6.3mm (page 101). But if I do my calculations and multiply (1/2.9) with 25.4 to convert it to mm I get 8.75862069?
The camcorder outputs a 1440*1080 interlaced .m2t file. The image in this file is squeezed by a factor of 1.33. as seen in this example.
So I suppose that the sensor has an aspect ratio of 4/3(1.33) So I did some math:

$$a^2 = b^2 +c^2$$
$$
\begin{matrix}
a_1 &amp;=&amp; 6.3\\
a_2 &amp;=&amp; 8.75862069\\
b &amp;=&amp; x\\
c &amp;=&amp; 1.33x\\
\end{matrix}
$$

$$6.3^2 = x^2 + (1.33x)^2$$
$$
\begin{matrix}
x &amp;=&amp; 3.78605\\
1.33x &amp;=&amp; 5.0354465\\
\textrm{horizontal 1} &amp;=&amp; 5.0354465
\end{matrix}
$$

$$8.75862069^2 = x^2 + (1.33x)^2$$
$$
\begin{matrix}
x &amp;=&amp; 5.26359\\
1.33x &amp;=&amp; 7.0005747\\
\textrm{horizontal 2} &amp;=&amp; 7.0005747\\
\end{matrix}
$$
So I thought because there always is a relation between sensor size and focal length, I just take the sensor size horizontal 35mm and the corresponding 35mm focal length equivalent of 49mm (manual page 101) and get the ration: 35 / 49 = 0.714285714 then multiply the true focal length of 5.4mm by that and get a horizontal sensor size of 3.857142856
So now I have got 3 possible horizontal sensor sizes. Now I want to calibrate my lens with a set of images like the linked one. Should I leave them with the 1.33 aspect ratio and where would I specify that in the OpenCV camera calibration or do I unsqueze them and then calibrate? And do I even need the sensor size and focal length for OpenCV camera calibration?
Answer over in Photography:
https://photo.stackexchange.com/questions/119761/sensor-size-of-sony-hdr-hc7e/119764#119764
It turns out to be Vertikal: 3.74 horizontal 4.98 and diagonal 6.23