Convert x-illion into standard form Given a string, consisting of a prefix and then "illion", convert this number into standard form.

For example:

"million" -&gt; 10^6
"trillion" -&gt; 10^12
"quattuordecillion" -&gt; 10^45


The program needs to be able to handle input going up to Centillion, which is 10^303. A  list of names and their standard form values can be found here - note that this gives values for every 10^3 increment up to 10^63, but then gives them in 10^30 increments, however the pattern is fairly straightforward.  

The program needs to handle all 100 cases (even the ones not explicitly given by the website provided) - here are some examples of this:

"sexvigintillion" -&gt; 10^81
"unnonagintillion" -&gt; 10^276
"octotrigintillion" -&gt; 10^117


Input can be given via STDIN, function argument or hard-coded as a string.

This is code-golf, so shortest code wins!
Python 2 (384 368 365 348 347 bytes)

def c(s):
 s=s[:-6].replace('int','');k=0;d=dict(un=1,doe=2,tre=3,quattuor=4,quin=5,sex=6,septen=7,octo=8,novem=9,b=3,tr=4,quadr=5,qu=6,sext=7,sept=8,oct=9,non=10,dec=11,vig=21,trig=31,quadrag=41,quinquag=51,sexag=61,septuag=71,octog=81,nonag=91,cent=101)
 for p in(s!='m')*list(d)*2:
    if s.endswith(p):s=s[:-len(p)];k+=3*d[p]
 return 10**(k or 6)


(The if line is indented with a single tab, and the rest with single spaces.)

Here c('million') == 10**6 has to be a special case because 'novem' also ends in 'm'.

Examples:

c('million') == 10**6
c('trillion') == 10**12
c('quattuordecillion') == 10**45
c('novemnonagintillion') == 10**300
c('centillion') == 10**303


Thanks to Falko for obfuscating it down to 350 bytes.



For practice I tried rewriting this as a one-liner using lambdas. It's 404 398 390 384 380 379 bytes:

c=lambda s:(lambda t=[s[:-5].replace('gint',''),0],**d:([t.__setslice__(0,2,[t[0][:-len(p)],t[1]+3*d[p]])for p in 2*list(d)if t[0].endswith(p)],10**t[1])[1])(un=1,doe=2,tre=3,quattuor=4,quin=5,sex=6,septen=7,octo=8,novem=9,mi=2,bi=3,tri=4,quadri=5,qui=6,sexti=7,septi=8,octi=9,noni=10,deci=11,vii=21,trii=31,quadrai=41,quinquai=51,sexai=61,septuai=71,octoi=81,nonai=91,centi=101)