Write a polyglot that prints the language's name Your task is to write a program that executes in as many languages as possible, with as few characters as you can. To avoid trivial solutions, the program must print the name of the language it was run in.
Scoring
Your program has to work in at least 5 languages. A program's score is given as:
$$\frac {\text{(number of languages)}^{1.5}} {\text{(length of program)}}$$
The highest score wins, not sooner than 10 days after the first valid answer.
Bash, C, C++, Obj-C, Obj-C++, Perl, PHP, Ruby, 183 chars

score ~ 0.1236

For the C and C-like codes I owe a debt to @baby-rabbit. The others are inspired by the recognition that many languages have an eval statement that will grudgingly accept invalid syntax. 

Outputs the language name to standard output. Sometimes generates a lot of error messages on standard error, so suppress them with 2&gt;/dev/null as you run them.

#if 0
'PHP&lt;?/*';eval "print\$=?'Perl':'Ruby';echo Bash";exit
__END__
#endif
#include &lt;stdio.h&gt;
main(){puts(
#ifdef __OBJC__
"obj-"
#endif
"C"
#ifdef __cplusplus
"++"
#endif
);}//*/?&gt;'


The php solution outputs 'PHP' (including the single quotes), which may be bending the rules a little bit.

Last edit: shaved 12 chars from insight that $= is false in Ruby, 60 in Perl, and print$=?... is almost surely an error in Bash. Shaved 7 more from insight the Perl/Ruby/Bash test can now go into a single eval statement.

If the rules can tolerate more bending, I present this 8 language, 43 character solution (score 0.5262)

print("phperluarscriptrubypythoncatebg13");


for which the output includes the name of the interpreter for php, perl, lua, rscript, ruby, python, cat, and rot13.