How many goals has Steven Gerrard scored? Steven Gerrard was born on 30th of May 1980. He is now 37 years old. Happy birthday, Steven!

To celebrate his anniversary, your goal is to remind him the number of goals he has scored each year in premiere league for Liverpool. 

He doesn't want to remember the goals scored before or after playing for Liverpool. It is like scoring 0 goals.

Input

The starting year of football season.

Output

The number of goals scored by Steven during this season for Liverpool.

List of seasons and goals

1998–99     0
1999–2000   1   
2000–01     7   
2001–02     3   
2002–03     5   
2003–04     4   
2004–05     7   
2005–06     10  
2006–07     7   
2007–08     11  
2008–09     16  
2009–10     9   
2010–11     4   
2011–12     5   
2012–13     9   
2013–14     13  
2014–15     9


Example

Input    Output
2002     5
2017     0
1990     0
2014     9


This is code-golf so the shortest submission in bytes in each language wins. Explanations are encouraged.
JavaScript (ES6), 47 43 42 39 bytes

y=&gt;+'0723135148933694'[y-1999]+y%20%9|0


How?

We compute an approximation x of the number of goals for a given year y with the formula:

x = y % 20 % 9


This is actually a very bad approximation, but it's always less than or equal to the expected value v and never less than v - 9, which allows to encode the difference with a single decimal digit.

y    | y % 20 | x = y % 20 % 9 | v  | v - x
-----+--------+----------------+----+------
1999 |     19 |              1 |  1 |     0
2000 |      0 |              0 |  7 |     7
2001 |      1 |              1 |  3 |     2
2002 |      2 |              2 |  5 |     3
2003 |      3 |              3 |  4 |     1
2004 |      4 |              4 |  7 |     3
2005 |      5 |              5 | 10 |     5
2006 |      6 |              6 |  7 |     1
2007 |      7 |              7 | 11 |     4
2008 |      8 |              8 | 16 |     8
2009 |      9 |              0 |  9 |     9
2010 |     10 |              1 |  4 |     3
2011 |     11 |              2 |  5 |     3
2012 |     12 |              3 |  9 |     6
2013 |     13 |              4 | 13 |     9
2014 |     14 |              5 |  9 |     4


Demo



let f =

y=&gt;+'0723135148933694'[y-1999]+y%20%9|0

for(y = 1997; y &lt;= 2017; y++) {
  console.log(y, f(y))
}