Calculate the sum of ILD Input:

An integer

Output:

Sum of the input itself + the length of the input + each individual digit of the input.

nr + nr-length + {sum of digits} = output


Examples:

Input: 99
Output: 99 (nr) + 2 (nr-length) + (9 + 9) (digits) → 119

Input: 123
Output: 123 + 3 + (1 + 2 + 3) → 132

Challenge rules:


The input can also contain negative input, which are resolved special. The -/minus-sign is also +1 for the length, and is part of the first digit.
For example:  

Input: -123
Output: -123 + 4 + (-1 + 2 + 3) → -115
You can assume that the input nor output will ever be outside the range of an (32-bit) integer.


General rules:


This is code-golf, so shortest answer in bytes wins.
Don't let code-golf languages discourage you from posting answers with non-codegolfing languages. Try to come up with an as short as possible answer for 'any' programming language.
Standard rules apply for your answer, so you are allowed to use STDIN/STDOUT, functions/method with the proper parameters and return-type, full programs. Your call.
Default Loopholes are forbidden.
If possible, please add a link with a test for your code.
Also, please add an explanation if necessary.


Test cases:

87901 → 87931
123 → 132
99 → 119
5 → 11
1 → 3
0 → 1
-3 → -4
-123 → -115
-900 → -905
-87901 → -87886


Semi-related: Count Sum of all Digits
Python 2, 39 bytes

lambda x:x+len(`x`)+eval(&quot;+&quot;.join(`x`))

Test suite
Using the same eval-trick as in my Pyth-answer.