Are the lists divisible? Inspired (with the explanation stolen from) this

Background

Say you have two lists A = [a_1, a_2, ..., a_n] and B = [b_1, b_2, ..., b_n] of integers. We say A is potentially-divisible by B if there is a permutation of B that makes a_i divisible by b_i for all i. The problem is then: is it possible to reorder (i.e. permute) B so that a_i is divisible by b_i for all i?
For example, if you have

A = [6, 12, 8]
B = [3, 4, 6]


Then the answer would be True, as B can be reordered to be B = [3, 6, 4] and then we would have that a_1 / b_1 = 2, a_2 / b_2 = 2, and a_3 / b_3 = 2, all of which are integers, so A is potentially-divisible by B.

As an example which should output False, we could have:

A = [10, 12, 6, 5, 21, 25]
B = [2, 7, 5, 3, 12, 3]


The reason this is False is that we can't reorder B as 25 and 5 are in A, but the only divisor in B would be 5, so one would be left out.

Your task

Your task is, obviously, to determine whether two lists (given as input) are potentially divisible. You may take input in any accepted manner, as with output.

Duplicates in the lists are a possibility, and the only size restrictions on the integers are your language. All integers in both lists will be larger than 0, and both lists will be of equal size.

As with all decision-problems the output values must be 2 distinct values that represent true and false.

This is a code-golf so shortest code wins!

Test cases

Input, input =&gt; output

[6, 12, 8], [3, 4, 6] =&gt; True
[10, 5, 7], [1, 5, 100] =&gt; False
[14, 10053, 6, 9] [1,1,1,1] =&gt; True
[12] [7] =&gt; False
[0, 6, 19, 1, 3] [2, 3, 4, 5, 6] =&gt; undefined
Husk, 7 6 5 bytes
Saved 2 bytes thanks to @Zgarb
▼▲‡¦P

Takes argents in reverse order and returns 1 for True and 0 for False.
Try it online!
Explanation
    P     -- Permutations of the first argument
  ‡       -- Deep zip (vectorises function) with second argument
   ¦      --   Does x divide y
 ▲        -- Get the maximum of that list, returns [1,1...1] if present
▼         -- Get the minimum of that list, will return 0 unless the list is all 1s