Double-time is not double time Based on this challenge.
In the rhythm game osu!, the difficulty modifier &quot;Double-time&quot; actually only increases the speed by 50%.
Your task, is to write a program that outputs a positive even integer (higher than 0), and when each byte/character (your choice which) in your source code is duplicated, it should output the number multiplied by 1.5.
For example if your source code is ABC and that outputs 6, then AABBCC should output 9.
Following the original challenge's rules:
Rules

You must build a full program.
The initial source must be at least 1 byte long.
Both the integers must be in base 10 (outputting them in any other base or with scientific notation is forbidden).
Your program must not take input (or have an unused, empty input) and must not throw any error (compiler warnings are not considered errors).
Outputting the integers with trailing / leading spaces is allowed.
You may not assume a newline between copies of your source.
This is code-golf, so the fewest bytes in each language wins!
Default Loopholes apply.

I imagine this will be far less trivial than the original challenge, but hopefully we'll see some creative and unique answers!
Pylons, 7 5 4 bytes

Picked a random language on TIO used it

46vt


Explanation:

Try it Online!

46    # Stack is [4, 6]

v     # Reverse the stack [6, 4]

t     # take top of stack 4


Doubled:

4466   # Stack is [4, 4, 6, 6]

vv     # Reverse the stack twice so it's the same [4, 4, 6, 6]

tt     # take top of stack 6 and again which is 6 again


Saved 2 bytes thanks to  officialaimm

Saved 1 bytes thanks to  Veedrac