Have you mooed today? The Debian Linux distribution (and Debian-based distros, like Ubuntu, Kali and others) uses a package-manager called APT. To install program foo you would type into a terminal 

sudo apt-get install foo


One little Easter Egg of APT is the following

apt-get moo


Which after typing will produce the following output

                 (__) 
                 (oo) 
           /------\/ 
          / |    ||   
         *  /\---/\ 
            ~~   ~~   
..."Have you mooed today?"...


You must write a program that produces this EXACT output in as few bytes as possible. (including trailing spaces and a new line)

Here is the same output with \n added to represent newline characters, and a * to represent trailing spaces

                 (__)*\n
                 (oo)*\n
           /------\/*\n
          / |    ||***\n
         *  /\---/\*\n
            ~~   ~~***\n
..."Have you mooed today?"...\n


As requested in the comments, here is the md5sum of the mooing.

35aa920972944a9cc26899ba50024115  -
CJam, 96

This uses a lot of nasty bytes, so here's a hex dump of it:

00000000  22 ee 51 1e 53 41 15 ee  51 20 53 41 15 9a 5f 5a  |".Q.SA..Q SA.._Z|
00000010  b9 5f 41 15 8c 5f 41 f9  38 24 2a 15 7e 55 1c 5f  |._A.._A.8$*.~U._|
00000020  b9 30 5f b9 41 15 a8 26  2a 26 2a 15 36 45 91 c3  |.0_.A..&amp;*&amp;*.6E..|
00000030  ed cb 41 f3 df eb 41 db  20 cb c9 41 e9 df c9 c3  |..A...A. ..A....|
00000040  f3 7f 45 36 15 22 7b 69  32 6d 64 5c 5f 63 5c 37  |..E6."{i2md\_c\7|
00000050  6d 64 22 20 5f 6f 2d 7c  7e 2e 22 3d 2a 3f 7d 2f  |md" _o-|~."=*?}/|


You can run the file with the java interpreter; it may be necessary to use ISO-8859-1 encoding, such as:
java -Dfile.encoding=ISO-8859-1 …

Try it online

Equivalent (and much longer) ASCII version:

[238 81 30 83 65 21 238 81 32 83 65 21 154 95 90 185 95 65 21 140 95 65 249 56 36 42 21 126 85 28 95 185 48 95 185 65 21 168 38 42 38 42 21 54 69 145 195 237 203 65 243 223 235 65 219 32 203 201 65 233 223 201 195 243 127 69 54 21]:c
{i2md\_c\7md" _o-|~."=*?}/


Try it online

Explanation:

There are 7 characters that have repetitions:  _o-|~.. Each of them can be encoded as a number n from 0 to 6. For each repeating sequence, I am encoding both the character's index (n) and the number of repetitions (k) in a single byte: 2 * (k * 7 + n), written as a character with that code. And I am encoding any single characters as 2 * c + 1, where c is the ASCII code. Everything goes in the initial string, and the rest of the program is decoding it:

{…}/      for each character in the string
  i       convert to integer (extended-ASCII code)
  2md     integer division by 2, obtaining the quotient (q) and remainder (r)
           r decides whether it's a repetition or single character
  \_      swap q and r, and duplicate q
  c\      convert q to character and move it before the other q
           this is for the r=1 case (single character)
  7md     divide q by 7, obtaining the quotient (k) and remainder (n)
  "…"=    get the corresponding character from that string (decoding n)
  *       repeat the character k times
  ?       use the single character or the repetition, depending on r




Old version (109):

" H(_2) 
 H(o2) 
 B/-6\/ 
 A/ | 4|2 3
 9* 2/\-3/\ 
 C~2 3~2 3
.6"{_'M,48&gt;&amp;{~*}&amp;}/3/"Have you mooed today?"`*N


Try it online