Number in overlapping range You are given two integers between lets say 1 and 12, one and two 
and a integer between lets say 0 and 4 which is called range.  The challange is to decide if one is inside or equal the range from two ± range.   The range is restarting with 1 after 12 and vise versa. 

For example, if one = 2, two = 11 and range = 3, the result is true, as one is the the range [8, 9, 10, 11, 12, 1, 2].

The input has to be 3 seperated integers, the order doesn't matter. Input via string with seperators possible. But the Input has to consist of numbers reading as '10' and not 'A' e.g.

Test cases:

one=7  two=6  range=0   result=false
one=5  two=6  range=1   result=true
one=8  two=11 range=3   result=true
one=1  two=11 range=3   result=true
one=2  two=10 range=3   result=false
one=11 two=1  range=2   result=true
one=6  two=1  range=4   result=false
one=12 two=1  range=3   result=true


Shortest valid answer in bytes wins.
Jelly, 10 8 10 bytes

ŒR’+%12‘Ɠe


Try it online!

Saved 2 bytes thanks to Mr. Xcoder

+2 bytes due a bug if one = 12

I believe this meets the criteria. Takes one from STDIN, range as left argument and two as right argument