Overlapping Polyglots Unlike many C&amp;R challenges, this does not require a separate robbers post; the goal of the robbers is to crack the previous answer and then post a new one as a cop.

As answerers, you will write a series of polyglots that look like this (each column is a language, and each entry is the output of the answer in that language):

Language:  1  2  3  4  5  6  7  8  ...
Answer 1:  0  1  2
Answer 2:     1  2  3
Answer 3:        2  3  4
Answer 4:           3  4  5
Answer 5:              4  5  6
Answer 6:                 5  6  7
...


(blank spaces mean that no behavior is required in that case).

Each answer should work in 3 languages and print 3 different consecutive numbers which are each one more than the numbers printed by the previous answer (the first answer prints 0, 1, and 2). Each answer uses two languages from the previous submission, and a third new language. The answerer should try to obfuscate what this third language is.

To post a new answer, you should:


Crack the most recent answer by finding what its third language is.
Preferably, add an explanation for your crack and notify the poster of the answer. Once your submission has been cracked, you should preferably add an explanation as well.
Write a polyglot consisting of this answer's second and third languages, along with another language of your choice. Reveal your first two languages, but do not reveal your new one. It will be the next poster's goal to find this language (or any other language in which it works), so you should try to obfuscate it.


Specifications


The criteria for a valid programming language are the same as those of The Programming Language Quiz, Mark II - Cops:


  
  It has an English Wikipedia article, an esolangs article or a Rosetta Code article at the time this challenge was posted, or is on Try It Online!. Having an interpreter linked in any of these pages makes that interpreter completely legal.
  It must satisfy our rules on what constitutes a programming language.
  It must have a free interpreter (as in beer). Free here means that anyone can use the program without having to pay to do so.
  

Each answer must run in less than a minute on a reasonable PC.
You can reuse programming languages, but there must be at least two answers in between (so an individual answer cannot reuse a language).
Cracking a submission consists of finding any programming language that prints the correct result, not just the intended one. If a submission is run in any language that was not declared or found to work, there are no requirements to do anything.
You may not post twice (or more) in a row.


Winning Criterion

The winning answer is whichever answer took to most time to be cracked. The challenge will  never end, so it is always possible for the winning answer to change.
Hexagony, Klein (101) and ???

  xx={puts/}
gets87!@xx=p

main\

&gt;9.*5,6v


This prints 7 in Hexagony, 8 in Klein (101), and 9 in ???.

The 9 does not work if a newline is added at the end of the code. Be careful if you're testing locally.

Edit: Being live for 20 hours is already a record, so I'll give some hints from now on. (Also because the language in question is IMO not yet well-known.)

Hints


"The 9 does not work if a newline is added at the end" is very significant, as well as the first two spaces (which are ignored by both Hexagony and Klein).
The language is on TIO.
The first two spaces make the program jump to the last line. (It's not a 2D language.)
There's no explicit output command, and the v command ends the program.


Explanation (cracked post)

In the source code

abcd={} -- a gaffe avoiding tactic in C++/C#
abcd[!1]=   1+2+3+4+5+6+7+8+9+10+11+12+13+17!
print(abcd[0&gt;1+2+3 and 4+8+6&lt;0-0]//35)
if 0&gt;1 then a.next=';' en\
                    &gt;1+6.@.@


The relevant instructions in Klein (101) are:

IP-&gt;.....................^...........IP-&gt;/
.........................|...................
.........................8
.........................\&lt;-.............IP&lt;-
                         @


Klein is fungelike 2D language where crossing the boundary of code area (which is a square) depends on the Klein topology. / and \ are mirrors.

The IP starts at upper left corner facing right. It meets a mirror towards the top boundary, and re-enters the code area on the right side as shown above. Then it hits the mirror again, 8 is pushed, and then (after passing through the boundary several times) stops at @. Then the content of the stack is printed to stdout, which is single 8.