Shortest Solution in Python 3 for Caught Speeding - CodingBat I am trying to find the shortest code in python 3, to solve this problem:

You are driving a little too fast, and a police officer stops you. 

Write code to take two integer inputs, first one corresponds to speed, seconds one is either 1 or 0, corresponding to True and False respectively to indicate whether it is birthday. Then compute the result, encoded as an int value: 

0=no ticket, 

1=small ticket, 

2=big ticket. 

If speed is 60 or less, the result is 0. If speed is between 61 and 80 inclusive, the result is 1. If speed is 81 or more, the result is 2. Unless it is your birthday -- on that day, your speed can be 5 higher in all cases.

input:
60
0
Output:
0

input:
65
0
Output:
1

input:
65
1
output:
0


Here's my shortest solution (57 chars). Is there any way I can make it shorter in Python?

print(min(2,max(0,(int(input())-5*int(input())-41)//20)))


Reference: Problem inspired from this
Python 3, 32 bytes



lambda a,b:(a-b*5&gt;60)+(a-b*5&gt;80)


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Python 3, 50 bytes

If io must be done with stdin and stdout



s=int(input())-5*int(input());print((s&gt;60)+(s&gt;80))


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