Reverse and add degeneracy Intro

Reverse and add is as simple as it sounds, take n and add it to its digits in reverse order. (e.g. 234 + 432 = 666).

If you apply this process repeatedly some numbers will eventually hit a prime number, and some will never reach a prime.

Example

I currently have 

11431 rep.

11431 is not prime
11431 + 13411 = 24842 which is not prime
24842 + 24842 = 49684 which is not prime
49684 + 48694 = 98378 which is not prime
98378 + 87389 = 185767 which is prime!


This number hits a prime

In contrast any multiple of 3 will never hit a prime, this is because the all multiples of 3 have a digit sum that is a multiple of 3 and vice versa.
Thus reverse and add on a multiple of 3 will always result in a new multiple of 3 and thus never a prime.

Task

Take a positive integer n and determine if repeatedly reversing and adding will ever result in a prime number. Output a truthy or falsy value.  Either truthy for reaches a prime and falsy value for does not or the other way around both are acceptable.

Prime numbers will be considered to reach a prime number in zero iterations.

This is code-golf so try to make your code as short as possible.

Test Cases

True for reaches a prime false for never reaches a prime

11 -&gt; True
11431 -&gt; True
13201 -&gt; True
13360 -&gt; True
13450 -&gt; True
1019410 -&gt; True
1019510 -&gt; True
22 -&gt; False
1431 -&gt; False
15621 -&gt; False
14641 -&gt; False


Hint

While I was writing this challenge I discovered a cool trick that makes this problem a good deal easier.  It is not impossible without this trick and it is not trivial with it either but it does help.  I had a lot of fun discovering this so I will leave it in a spoiler below.


   Repeated reverse and add will always hit a multiple of 11 in 6 iterations or less.  If it does not hit a prime before it hits a multiple of 11 it will never hit a prime.
Ruby, 84 79 77 74 bytes



-&gt;x{y=1;x+="#{x}".reverse.to_i while(2...x).any?{|z|0==y=x%z}&amp;&amp;x%11&gt;0;y&gt;0}


Try it online!


   If I got it right, when we reach a multiple of 11 we can stop (we will only get multiples of 11 after that)