Convert Planck unit to SI metric Objective

Given a dimension of an SI unit, convert the Lorentz-Heaviside version of a Planck unit \$1\$ into SI metric.

What is a Planck unit?

Planck units are a set of units of measurement. It defines five fundamental constants of the universe as dimensionless \$1\$.

What is a dimension?

There are five types of fundamental dimension: L, M, T, Q, and Θ (U+0398; Greek Capital Letter Theta).

L stands for length and corresponds to SI unit m (meter).

M stands for mass and corresponds to SI unit kg (kilogram).

T stands for time and corresponds to SI unit s (second).

Q stands for electric charge and corresponds to SI unit C (Coulomb).

Θ stands for temperature and corresponds to SI unit K (Kelvin).

A dimension is a multiplicative combination of these. For example, SI unit V (volt) is same as kg·m²·C/s⁴ and thus corresponds to dimension L²MQ/T⁴.

Planck to SI

\$1\$ as Planck unit can be converted to SI metric as follows:

$$
1 = 5.72938×10^{−35} \space [\text{m}] = 6.13971×10^{−9} \space [\text{kg}] = 1.91112×10^{−43} \space [\text{s}] = 5.29082×10^{−19} \space [\text{C}] = 3.99674×10^{31} \space [\text{K}]
$$

Input and Output

A dimension is given as the input. Its type and format doesn't matter. In particular, it can be an size-5 array of signed integers, each integer representing the exponent of a fundamental dimension.

The Planck unit \$1\$ is to be converted to the SI unit that corresponds to the inputted dimension, and then outputted. The output type and format doesn't matter.

Examples

Let's say the input format is a tuple of five integers, representing L, M, T, Q, and Θ, respectively.

For example, If the input is \$(2,1,-1,-2,0)\$, it corresponds to SI unit Ohm, and thus:

$$
1 = \frac{(5.72938×10^{−35})^2 × (6.13971×10^{−9})}{(1.91112×10^{−43})×(5.29082×10^{−19})^2} \space [\text{Ω}]
$$

So the output is approximately \$376.730\$.

For another example, if the input is \$(-2,-1,3,0,1)\$, it corresponds to SI unit K/W, and thus:

$$
1 = \frac{(1.91112×10^{−43})^3 × (3.99674×10^{31})}{(5.72938×10^{−35})^2 × (6.13971×10^{−9})} \space [\text{K/W}]
$$

So the output is approximately \$1.38424×10^{−20}\$.

Note that, if the input is \$(0,0,0,0,0)\$, the output must be \$1\$.
Python 3, 118 \$\cdots\$ 85 80 bytes

Saved a whopping 29 bytes thanks to Surculose Sputum!!!
Saved 4 bytes thanks to Arnauld!!!
Saved 5 bytes thanks to xnor!!!   



lambda a,b,c,d,e:399674e26**e/174539e29**a/162874e3**b/523253e37**c/189007e13**d


Try it online!