Infinitely Print Zeno's Dichotomy Paradox (1/(2^n)) Wikipedia: Zeno's Dichotomy Paradox

An infinite number of mathematicians walk into a bar. The first one orders a beer. The second one orders half a beer. The third one orders a fourth of a beer. The bartender stops them, pours two beers and says, &quot;You're all a bunch of idiots.&quot;
Reddit

Print the following series for as long as the program runs, with the denominator of each item being multiplied by two each time:
1 + 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + ...
As n approaches infinity, the sum of this sequence approaches 2.
Rules
No, you may not print 2.
You may not print 1/1 as the first item.
You may remove spaces 1+1/2+... or add spaces 1 + 1 / 2 + ... as you need.
You may use newlines instead of spaces as a delimiter due to popular demand.
You may append a . plus a constant number of 0s to the denominator if need be.
&quot;Infinitely&quot; means no unnecessary delays, and for as long as possible limited by the current (variable) system's specs, but not limited by your current language.
Standard loopholes apply.
This is code-golf, so shortest answer in bytes wins.
05AB1E, 10 9 bytes

Saved 1 byte thanks to Erik the Outgolfer

[No…+1/J?


Try it online!

Explanation

[           # loop over N infinitely [0 ...]
 No         # calculate 2^N
   …+1/J    # join with the string "+1/"
        ?   # print without newline