Big or Little Endian Write a program or function that outputs an L if run on a little endian architecture or a B if run on a big endian architecture. Lower case output l or b is also acceptable.

There is no input.

Scoring is code golf, so the code with the fewest bytes wins.

Edit: As per the comments below, I am clarifying that the entry must be able to run on either architecture.

I believe that there is only one answer that this affects, and that answer has clearly indicated that this is the case.
Python, 33 bytes

import sys
exit(sys.byteorder[0])


sys.byteorder is either 'little' or 'big' (and for those of you who will read this sentence without looking at the code, [0] means take the first character).