cofactor matrix in Hill cipher I have been reading these slides about Hill cipher.

And there it says that the value of K is the following:

\begin{equation}
K=
\begin{pmatrix}
11&amp;8\\3&amp;7
\end{pmatrix}
\end{equation}

Now I need to calculate $K^{-1}$, so for that reason I calculate the adjoint matrix by using the cofactors. For what I know it should be:

\begin{pmatrix}
7&amp;-3\\-8&amp;11
\end{pmatrix}

but in the slides it appears that is:

\begin{pmatrix}
7&amp;-8\\-3&amp;11
\end{pmatrix}

which is different from the one I calculate, what am I doing wrong?
I think the adjugate matrix is the transpose of the cofactor matrix.

(Btw, I do not think this is a crypto question.)