Does seemingly random output imply irreversibility in hash function? My question mainly stems from the following observation of properties of cryptographic hash function:


Preimage resistance: Given $H(x)$, it's hard to find $x$ 
Second preimage resistance: Given $m1$, it's hard to find another $m2$ such that $H(m1)=H(m2)$
Collision resistance: It's hard to find any two distinct messages $m1$, $m2$ such that $H(m1)=H(m2)$.


It is said that property 3 implies property 2 which implies property 1. I can understand if it is hard to find any two distinct messages $m1$ and $m2$ for $H(m1)=H(m2)$ then it will be hard to find a distinct $m2$ for given $m1$ for $H(m1)=H(m2)$ (property 3 implies property 2). And if I have $m1$ and $H(m1)$ then from property 2 I can say it is hard to get $m2$ from $H(m2)$ if $H(m1)=H(m2)$, and as $H(m2)=H(m1)$ it is hard to get $m1$ from $H(m1)$ as well (property 2 implies property 1). 

Now my question is if a hash function has this property: for small changes in inputs it outputs such numbers that will seem random so that from output it will be hard to determine changes in input, does it imply any of the above property specially property 1, i.e. irreversibility of cryptographic hash function? 

I am asking this because for $m1$ &amp; $m2$ I will get $H(m1)$ &amp; $H(m2)$ respectively and if $H(m1)$ &amp; $H(m2)$ are correlated (not random) and I know $m1$ and $H(m1)$ (prior information) then from changes in output can I know easily changes in input thus know which input produces output? Putting slight differently is it possible to train a hash function from input and output if outputs are not seemingly random so that for given output I will know input?
Now my question is if a hash function has this property: for small changes in inputs it outputs such numbers that will seem random so that from output it will be hard to determine changes in input, does it imply any of the above property specially property 1, i.e. irreversibility of cryptographic hash function? 


No. Randomness is hard to test and it's easy to use any of the non-secure random number generators to generate random looking output. So anything that is "non-random" is certainly not irreversible because of just that.


  Putting slight differently is it possible to train a hash function from input and output if outputs are not seemingly random so that for given output I will know input?


That's kind of the opposite. But if you just take $H'(x) = H(x) | 1$ then it should be clear that $H'(x)$ is as irreversible as $H(x)$, while the output is clearly not random.