RSA: Decrypting message with public key and private key I am trying to decrypt a message which its ciphertext in Hex A3 BB 05 00.
The original plain text is 8 bits and it is encrypted by a 32 bits RSA key.

I have successfully found the public key is $(e=947,n=2671079)$ and the private key is $(d=713604)$.

Then, I try to convert the Hex string to integer 00 05 BB A3 (Little Endian) $=375715$.

Finally, I calculate $C^d \mod n = 375715^{713604} \mod 2671079 = 544824$.


  Calculate in python: C**d % n


My problem: 

1) what does $544824$ mean? Is it the original plain text or I need to further converting this number?

2) The plain text should be 8 bits, why the result I get is larger than 8 bits? 

thanks!
Your ciphertext is A3 BB 05 00

In RSA, the ciphertext is always larger than the original data. In this case, the keys are 32 bits, which is 4 bytes, and A3 BB 05 00 is four bytes