Order of target group in bilinear pairing Consider a bilinear pairing $e:G_1×G_2→G_T$, and $p^2q^2$ be the order of $G_1$ and $G_2$, where $p$ and $q$ are prime integers. 

Suppose that $g_1$ and $g_2$ are generators of $G_1$ and $G_2$ respectively, and $a$ is a random integer. What is the output of $e(g_1^p, g_2^a)$? Is it equal to $(g_t)^{ap}$?

What is the order of the result? Is it equal to $pq^2$?

I know usually in the pairing cryptography the order of groups is set to a prime integer, but, i just want to know what happens if the order is a composite integer $p^2q^2$.
I find it. The output is $e(g_1^p,g_2^a)=(g_t)^{ap}$. https://eprint.iacr.org/2013/812.pdf