Brute-force attacking One Time Pads feasible? I have a ciphertext encoded with One Time Pad. I do not know the key. How can I find the possible keys which when decoded, will result in a meaningful plain text?
The interesting property for the one time pad is that every plausible plaintext (given the length constraint, i.e. of same length as the ciphertext, maybe including some padding) has a corresponding key which produces a certain ciphertext.

As mentioned in the comment by CodesInChaos, this key can be retrieved by simply XORing both plaintext and ciphertext (if you are using the XOR variant of the one time pad ... for the addition variant you'll have to subtract).

Also, assuming a random key, every plaintext has the same probability, given the ciphertext, as it has without knowing the ciphertext (apart from the length).

This is known as perfect secrecy – you can get no information from the ciphertext about the plaintext which you didn't know before (apart from the length, but this can be hidden to a certain degree by padding, too).

Every cryptosystem with the perfect secrecy property must have a key as least as long as the messages, and each key must be used only once. This is why a one-time pad or other perfect encryption systems are not used often in practice.