SHA-1 hash where each of the first 16 bytes is even Is it possible for a SHA-1 hash to have the first 16 characters with a character code $c$ where $c \bmod 2 = 0$?

So given the hash, hash[i] % 2 must be 0 for all 16 characters.
An input with the property you are looking for can easily be found by brute force:

#!/usr/bin/python

from hashlib import sha1

def good(s):
    for c in sha1(s).digest():
        if ord(c) &amp; 1:
            return False
    return True

for n in xrange(10**7):
    if good(str(n)):
        print n
        raise SystemExit


To double check the correctness of the result I used this command:

printf 1014746 | sha1sum | grep '^\(.[02468ace]\)*  -$'