Help me about Advanced Encryption Standard (AES) Suppose $E_k$$(a, b, c)$ is encryption of values $a, b$ and $c$ with key $k$ through encryption algorithm AES (AES-128) and each $a, b$ and $c$ are 300 bits integer values. 

Also Suppose this algorithm in my question situation work in CBC mode.  

If $V_1= E_k(a, b, c)$ and $V_2= E_k(c, a, b)$, my questions is:  are the two values $V_1$ and $V_2$ equal or not?
I'm going to assume that the comma $,$ operator used in your question means 'concatenate' (normally written $a||b||c$). Moreover, I'm assuming that $a,b,c$ are distinct.

In that case, With incredibly high probability, No: $V_1$ and $V_2$ will not be equal.

Think of it this way: if they were equal, then what would $D_k(V_1)$ be? Supposing $V_1=V_2$, we have:
$$a||b||c=D_k(E_k(a||b||c))=D_k(V_1)=D_k(V_2)=D_k(E_k(b||a||c))=b||a||c$$

That is, we would have to deduce that $a||b=b||a$ and thus $a=b$.