The length of the shortest vector in Lattice In Micciancio and Regev's paper "Lattice-based Cryptography",the length of the shortest vector is at least $\min\{q, 2^{2\cdot\sqrt{(n\cdot \log{q}\cdot\log{\delta}})}\}$ . I want to ask why the paper chose the latter as the length of the shortest vector rather than $q$ when considering concert parameters. In addition, whether the $q$ is normally more than $2^{2\cdot\sqrt{(n\cdot \log{q}\cdot\log{\delta}})}$?
Remember that we are considering $q$-ary lattices, as defined by

$$ \Lambda^{\perp}_q(\mathbf{A}) = \{ \mathbf{y} \in \mathbb{Z}^m : \mathbf{A} \mathbf{y} = \mathbf{0} \mod q \}. $$

Clearly the vector $(q,\mathbf{0})$ is in this lattice, and has length $q$. This is a trivial, uninteresting solution, as it doesn't give a better understanding of the lattice.

$\min \{ q, 2^{2 \cdot \sqrt{(n\cdot \log{q} \cdot log{\delta})}} \}$ refers to the shortest vector one can find using (then) state of the art lattice reduction algorithms. If you're choosing parameters in order to make a cryptographic scheme secure, you are trying to ensure that the shortest non-trivial vectors that can be found are not very short. If trivial vectors break your scheme, it is broken anyway, and no amount of parameter tweaking will fix it.