How you find the unpadded short plaintext using RSA? I am currently trying to understand how you find the unpadded short plaintext when you are using RSA. Please help with explaining the process and so I can understand this topic more.
As kelalaka hinted, the issue with particularly short plaintext in unpadded RSA is that it is subject to brute force via chosen plaintext attack.

For each plaintext $m$ in the short space you suspect the enciphered plaintext to originate from calculate $c = m^e \text{ mod } n$ where $e$ is the public encryption exponent and $n$ is the public modulus. Then compare $c$ to the ciphertext for which you are trying to find the plaintext. If identical, the message $m$ is the same as the padded short plaintext in question. Because RSA is deterministic, identical plaintexts produce identical ciphertexts.