How to calculate this equation? Can someone please explain to me what are the steps used to get this result (0.9154n+0.8876) from this equation
$$(2n+2){T}_{ecc}^{sm}+(2n){T}_{h}+(2n+2){T}_{ecc}^{pa}+(2n){T}_{ecc}^{sm-s} \approx 0.9154n + 0.8876?$$
where ${T}_{ecc}^{sm}$ =0.442,  ${T}_{h}$= 0.0001,  ${T}_{ecc}^{pa}$= 0.0018, and  ${T}_{ecc}^{sm-s}$= 0.0138
PS: These variables represent the Execution time of cryptographic operations in ms
The sagemath with symbolic computations doesn't provide the same results. Contact the authors.
n = var('n');
a = 0.442
b = 0.0001
c = 0.0018
d = 0.0138
(2*n+2)*a + (2*n)*b + (2*n+2)*c + (2*n)*d

output
0.915400000000000*n + 0.887600000000000

$$(2*n+2)*a + (2*n)*b + (2*n+2)*c + (2*n)*d = $$
$$ 2n(a+b+c+d) + 2(a +c) $$
$$ 2n ( 0.442 + 0.0001 + 0.0018 + 0.0138) + 2 (0.442 + 0.0018)$$
$$ 2n ( 0.442 + 0.0019 + 0.0138) + 2 (0.4439)$$
$$ 2n ( 0.4439 + 0.0138) + 0.8878)$$
$$ 2n ( 0.4577 ) + 0.8878)$$
$$  0.9154n  + 0.8878)$$